《2025年名校课堂七年级数学上册人教版福建专版》

计算：
(1)$-0.75×(-\frac {3}{2})÷(-\frac {9}{4})$. (2)$3×(-1)+2^{2}+|-4|$.
(3)$(-5)×3\frac {1}{3}+2×3\frac {1}{3}+(-6)×3\frac {1}{3}$. (4)$(-5)÷(-\frac {9}{7})×\frac {4}{5}×(-\frac {9}{4})÷7$.
(5)$(-\frac {1}{4}-\frac {5}{6}+\frac {8}{9})÷(-\frac {1}{6})^{2}$. (6)$(-1)^{4}×|-8|+(-2)^{3}×(\frac {1}{2})^{2}$.
(7)$-81÷\frac {9}{4}×|-\frac {4}{9}|-(-3)^{3}÷27$. (8)$4+16÷(-2)^{3}×|-3-1|$.
(9)$-2^{2}+(-3)^{2}×(-\frac {2}{3})-4^{2}÷|-4|$. (10)$(-5)^{3}×(-\frac {3}{5})+32÷(-2^{2})×(-1\frac {1}{4})$.
(11)$-8×(-\frac {1}{2})^{2}+(\frac {2}{3}-\frac {5}{8})÷(-\frac {1}{24})$. (12)$(-2)^{3}×[-7+(3-1.2×\frac {5}{6})]$.
(13)$-4^{2}-6×(-\frac {4}{3})+2×(-1)^{3}÷(-\frac {1}{2})$. (14)$[(-1)^{100}+(1-\frac {1}{2})×\frac {1}{3}]÷(-3^{2}+2)$.
(15)$(-\frac {1}{30})÷(\frac {2}{3}-\frac {1}{10}+\frac {1}{6}-\frac {2}{5})-(-1)^{2025}$. (16)$-2^{3}÷[2\frac {1}{4}×(-1\frac {1}{3})^{2}]×(-0.25)^{2}$.
(17)$(-2)^{2}-(1-\frac {2}{3})÷2\frac {1}{3}×[6+(-3)^{3}]$. (18)$(-2)^{4}÷(-3)×(1-\frac {1}{4})^{2}+[-(-1)^{2026}+9]$.

答案：
(1)原式$=-\frac {3}{4}×(-\frac {3}{2})×(-\frac {4}{9})=-\frac {1}{2}$.
(2)原式$=-3+4+4=5$.
(3)原式$=[(-5)+2+(-6)]×3\frac {1}{3}=(-9)×\frac {10}{3}=-30$.
(4)原式$=-5×\frac {7}{9}×\frac {4}{5}×\frac {9}{4}×\frac {1}{7}=-5×\frac {4}{5}×(\frac {7}{9}×\frac {9}{4}×\frac {1}{7})=-4×\frac {1}{4}=-1$.
(5)原式$=(-\frac {1}{4}-\frac {5}{6}+\frac {8}{9})÷\frac {1}{36}=(-\frac {1}{4}-\frac {5}{6}+\frac {8}{9})×36=-\frac {1}{4}×36-\frac {5}{6}×36+\frac {8}{9}×36=-9-30+32=-7$.
(6)原式$=1×8-8×\frac {1}{4}=8-2=6$.
(7)原式$=-81×\frac {4}{9}×\frac {4}{9}-(-27)÷27=-16+1=-15$.
(8)原式$=4+16÷(-8)×4=4+(-2)×4=4+(-8)=-4$.
(9)原式$=-4+9×(-\frac {2}{3})-16÷4=-4+(-6)-4=-14$.
(10)原式$=(-125)×(-\frac {3}{5})+32÷(-4)×(-\frac {5}{4})=75+(-8)×(-\frac {5}{4})=75+10=85$.
(11)原式$=-8×\frac {1}{4}+(\frac {2}{3}-\frac {5}{8})×(-24)=-2+\frac {2}{3}×(-24)-\frac {5}{8}×(-24)=-2-16+15=-3$.
(12)原式$=(-8)×[-7+(3-\frac {6}{5}×\frac {5}{6})]=(-8)×[-7+(3-1)]=(-8)×(-5)=40$.
(13)原式$=-16-(-8)+2×(-1)×(-2)=-16+8+4=-4$.
(14)原式$=(1+\frac {1}{2}×\frac {1}{3})÷(-9+2)=(1+\frac {1}{6})÷(-7)=\frac {7}{6}×(-\frac {1}{7})=-\frac {1}{6}$.
(15)原式$=(-\frac {1}{30})÷(\frac {20}{30}-\frac {3}{30}+\frac {5}{30}-\frac {12}{30})-(-1)=(-\frac {1}{30})÷\frac {1}{3}+1=(-\frac {1}{30})×3+1=-\frac {1}{10}+1=\frac {9}{10}$.
(16)原式$=-8÷(\frac {9}{4}×\frac {16}{9})×\frac {1}{16}=-8×\frac {1}{4}×\frac {1}{16}=-\frac {1}{8}$.
(17)原式$=4-\frac {1}{3}÷\frac {7}{3}×(6-27)=4-\frac {1}{3}×\frac {3}{7}×(-21)=4+3=7$.
(18)原式$=16÷(-3)×(\frac {3}{4})^{2}+(-1+9)=-16×\frac {1}{3}×\frac {9}{16}+8=-3+8=5$.