《2025年名校课堂六年级数学上册鲁教版山东专版54制》

计算：
(1)$-0.75×(-\frac {3}{2})÷(-\frac {9}{4})$；
(2)$3×(-1)+2^{2}+|-4|$；
(3)$(-5)×3\frac {1}{3}+2×3\frac {1}{3}+(-6)×3\frac {1}{3}$；
(4)$(-5)÷(-\frac {9}{7})×\frac {4}{5}×(-\frac {9}{4})÷7$；
(5)$(-6)^{2}×[-\frac {1}{4}+(-\frac {2}{9})-(-\frac {7}{18})]$；
(6)$(-1)^{4}×|-8|+(-2)^{3}×(\frac {1}{2})^{2}$；
(7)$6×(1-\frac {1}{3})-3^{2}÷(-9)$；
(8)$4+16÷(-2)^{3}×|-3-1|$；
(9)$(-5)^{3}×(-\frac {3}{5})+32÷(-2^{2})×(-1\frac {1}{4})$；
(10)$-2^{2}×7-(-3)×6-5÷(-\frac {1}{5})$；
(11)$-8×(-\frac {1}{2})^{2}+(\frac {2}{3}-\frac {5}{8})÷(-\frac {1}{24})$；
(12)$-2^{3}×\frac {1}{4}-4^{2}+(-2)^{4}+|-3|$；
(13)$-1^{2024}+8÷(-2)^{2}-|-4|×5$；
(14)$(-2)^{3}×[-7+(3-1.2×\frac {5}{6})]$；
(15)$-4^{2}-6×(-\frac {4}{3})+2×(-1)^{3}÷(-\frac {1}{2})$；
(16)$[(-1)^{100}+(1-\frac {1}{2})×\frac {1}{3}]÷(-3^{2}+2)$；
(17)$(-\frac {1}{30})÷(\frac {2}{3}-\frac {1}{10}+\frac {1}{6}-\frac {2}{5})-(-1)^{2023}$；
(18)$-3^{2}-[8÷(-2)^{3}-1]+3÷2×\frac {1}{2}$；
(19)$(-2)^{2}-(1-\frac {2}{3})÷2\frac {1}{3}×[6+(-3)^{3}]$.

答案：
(1)原式$= - \frac{3}{4} × ( - \frac{3}{2}) × ( - \frac{4}{9}) = - \frac{1}{2}$．
(2)原式$= - 3 + 4 + 4 = 5$．
(3)原式$= \lbrack( - 5) + 2 + ( - 6)\rbrack × 3\frac{1}{3} = ( - 9) × \frac{10}{3} = - 30$．
(4)原式$= - 5 × \frac{7}{9} × \frac{4}{5} × \frac{9}{4} × \frac{1}{7} = - 5 × \frac{4}{5} × (\frac{7}{9} × \frac{9}{4} × \frac{1}{7}) = - 4 × \frac{1}{4} = - 1$．
(5)原式$= 36 × ( - \frac{1}{4} - \frac{2}{9} + \frac{7}{18}) = 36 × ( - \frac{1}{4}) + 36 × ( - \frac{2}{9}) + 36 × \frac{7}{18} = - 9 - 8 + 14 = - 3$．
(6)原式$= 1 × 8 - 8 × \frac{1}{4} = 8 - 2 = 6$．
(7)原式$= 6 × \frac{2}{3} - 9 ÷ ( - 9) = 4 + 1 = 5$．
(8)原式$= 4 + 16 ÷ ( - 8) × 4 = 4 + ( - 2) × 4 = 4 + ( - 8) = - 4$．
(9)原式$= ( - 125) × ( - \frac{3}{5}) + 32 ÷ ( - 4) × ( - \frac{5}{4}) = 75 + ( - 8) × ( - \frac{5}{4}) = 75 + 10 = 85$．
(10)原式$= - 4 × 7 + 18 + 5 × 5 = - 28 + 18 + 25 = 15$．
(11)原式$= - 8 × \frac{1}{4} + (\frac{2}{3} - \frac{5}{8}) × ( - 24) = - 2 + \frac{2}{3} × ( - 24) - \frac{5}{8} × ( - 24) = - 2 - 16 + 15 = - 3$．
(12)原式$= - 8 × \frac{1}{4} - 16 + 16 + 3 = - 2 - 16 + 16 + 3 = 1$．
(13)原式$= - 1 + 8 ÷ 4 - 4 × 5 = - 1 + 2 - 20 = - 19$．
(14)原式$= ( - 8) × \lbrack - 7 + (3 - \frac{6}{5} × \frac{5}{6})\rbrack = ( - 8) × \lbrack - 7 + (3 - 1)\rbrack = ( - 8) × ( - 5) = 40$．
(15)原式$= - 16 - ( - 8) + 2 × ( - 1) × ( - 2) = - 16 + 8 + 4 = - 4$．
(16)原式$= (1 + \frac{1}{2} × \frac{1}{3}) ÷ ( - 9 + 2) = (1 + \frac{1}{6}) ÷ ( - 7) = \frac{7}{6} × ( - \frac{1}{7}) = - \frac{1}{6}$．
(17)原式$= ( - \frac{1}{30}) ÷ (\frac{20}{30} - \frac{3}{30} + \frac{5}{30} - \frac{12}{30}) - ( - 1) = ( - \frac{1}{30}) ÷ \frac{1}{3} + 1 = ( - \frac{1}{30}) × 3 + 1 = - \frac{1}{10} + 1 = \frac{9}{10}$．
(18)原式$= - 9 - ( - 1 - 1) + \frac{3}{2} × \frac{1}{2} = - 9 + 2 + \frac{3}{4} = - 6\frac{1}{4}$．
(19)原式$= 4 - \frac{1}{3} ÷ \frac{7}{3} × (6 - 27) = 4 - \frac{1}{3} × \frac{3}{7} × ( - 21) = 4 + 3 = 7$．