《2025年名校课堂六年级数学上册鲁教版山东专版54制》

计算：
(1)$(-13)× (-28)× \frac{1}{13}× (-\frac{1}{7})$；
(2)$(-20)× (-1\frac{1}{5})× (-0.3)× 5$；
(3)$25× \frac{3}{4}-(-25)× \frac{1}{2}+25× (-\frac{1}{4})$；
(4)$(\frac{2}{3}-\frac{3}{4}+\frac{1}{6})÷ (-\frac{1}{24})$；
(5)$(-36)× 99\frac{71}{72}$；
(6)$[1\frac{2}{13}-(\frac{5}{8}-\frac{1}{6}+\frac{7}{12})× 24]÷ (-5)$；
(7)$(-\frac{1}{30})÷ (\frac{2}{3}-\frac{1}{10}+\frac{1}{6}-\frac{2}{5})$；
(8)$(\frac{7}{9}-\frac{5}{6}+\frac{3}{18})× 18+3.95× 6-1.45× 6$；
(9)$0.7× 1\frac{4}{9}+2\frac{3}{4}× (-17)+0.7× \frac{5}{9}+\frac{1}{4}× (-17)$。

答案：
(1)原式=-13×28×$\frac{1}{13}$×$\frac{1}{7}$=-(13×$\frac{1}{13}$)×(28×$\frac{1}{7}$)=-1×4=-4.
(2)原式=-(20×0.3)×($\frac{6}{5}$×5)=-6×6=-36.
(3)原式=25×$\frac{3}{4}$+25×$\frac{1}{2}$-25×$\frac{1}{4}$=25×($\frac{3}{4}$+$\frac{1}{2}$-$\frac{1}{4}$)=25×1=25.
(4)原式=($\frac{2}{3}$-$\frac{3}{4}$+$\frac{1}{6}$)×(-24)=-$\frac{2}{3}$×24+$\frac{3}{4}$×24-$\frac{1}{6}$×24=-16 + 18 - 4=-2.
(5)原式=(-36)×(100-$\frac{1}{72}$)=-3600+$\frac{1}{2}$=-3599$\frac{1}{2}$.
(6)原式=[1$\frac{2}{13}$-(15 - 4 + 14)]÷(-5)=($\frac{15}{13}$-25)×(-$\frac{1}{5}$)=$\frac{15}{13}$×(-$\frac{1}{5}$)-25×(-$\frac{1}{5}$)=-$\frac{3}{13}$+5=4$\frac{10}{13}$.
(7)原式的倒数为($\frac{2}{3}$-$\frac{1}{10}$+$\frac{1}{6}$-$\frac{2}{5}$)÷(-$\frac{1}{30}$)=($\frac{2}{3}$-$\frac{1}{10}$+$\frac{1}{6}$-$\frac{2}{5}$)×(-30)=$\frac{2}{3}$×(-30)-$\frac{1}{10}$×(-30)+$\frac{1}{6}$×(-30)-$\frac{2}{5}$×(-30)=-20-(-3)+(-5)-(-12)=-10.故原式=-$\frac{1}{10}$.
(8)原式=$\frac{7}{9}$×18-$\frac{5}{6}$×18+$\frac{3}{18}$×18+(3.95 - 1.45)×6=14 - 15 + 3+2.5×6=2 + 15=17.
(9)原式=(0.7×1$\frac{4}{9}$+0.7×$\frac{5}{9}$)+[-17×(2$\frac{3}{4}$+$\frac{1}{4}$)]=0.7×(1$\frac{4}{9}$+$\frac{5}{9}$)+(-17)×3=0.7×2+(-51)=1.4 - 51=-49.6.