《2025年名校课堂七年级数学上册人教版贵州专版》

1. (70分)脱式计算：
(1) $ 5 - (\frac{6}{7} ÷ \frac{13}{14} + \frac{6}{13}) $
(2) $ \frac{4}{9} × [75\% - (\frac{7}{16} - 25\%)] $
(3) $ 60 × (25\% + \frac{5}{6} - \frac{7}{12}) $
(4) $ \frac{3}{5} ÷ [(\frac{1}{5} + \frac{1}{3}) ÷ \frac{2}{9}] $
(5) $ 48 × (\frac{7}{12} + 2) ÷ \frac{2}{3} $
(6) $ \frac{9}{20} ÷ [\frac{2}{7} × (\frac{3}{4} - \frac{2}{5})] $
(7) $ (\frac{3}{5} + \frac{3}{5} × 99) ÷ \frac{12}{17} $
(8) $ 24.3 ÷ [(7.5 - 5.7) × 0.45] $
(9) $ \frac{5}{18} ÷ [\frac{5}{16} × (\frac{1}{5} + \frac{1}{3})] $
(10) $ [40 ÷ (3.49 - 3.09)] × 4.5 $

答案：
(1)原式$=5-(\frac {12}{13}+\frac {6}{13})=3\frac {8}{13}$
(2)原式$=\frac {4}{9}×(75\% -\frac {7}{16}+25\% )=\frac {4}{9}×(1-\frac {7}{16})=\frac {1}{4}$
(3)原式$=60×\frac {1}{4}+60×\frac {5}{6}-60×\frac {7}{12}=15+50-35=30$
(4)原式$=\frac {3}{5}÷(\frac {8}{15}÷\frac {2}{9})=\frac {3}{5}÷\frac {12}{5}=\frac {1}{4}$
(5)原式$=48×\frac {31}{12}÷\frac {2}{3}=124×\frac {3}{2}=186$
(6)原式$=\frac {9}{20}÷(\frac {2}{7}×\frac {7}{20})=\frac {9}{20}÷\frac {1}{10}=\frac {9}{2}$
(7)原式$=[\frac {3}{5}×(1+99)]÷\frac {12}{17}=60÷\frac {12}{17}=85$
(8)原式$=24.3÷(1.8×0.45)=24.3÷0.81=30$
(9)原式$=\frac {5}{18}÷(\frac {5}{16}×\frac {8}{15})=\frac {5}{18}÷\frac {1}{6}=\frac {5}{3}$
(10)原式$=(40÷0.4)×4.5=100×4.5=450$

2. (30分)计算：
(1) $ 1.6 × (2.25 + 10.5 ÷ 1.5) $
(2) $ 0.6 ÷ [(6.1 - 4.6) × 0.8] $
(3) $ 12.48 ÷ [4 × (1.39 - 0.19)] $
(4) $ (25 + \frac{3}{4}) ÷ \frac{1}{4} + \frac{1}{4} × \frac{4}{25} $
(5) $ [\frac{6}{7} ÷ (\frac{2}{3} - \frac{1}{2})] × \frac{7}{12} - \frac{3}{5} $
(6) $ 999 \frac{8}{9} + 99 \frac{8}{9} + 9 \frac{8}{9} + \frac{1}{3} $

答案：
(1)原式$=1.6×(2.25+7)=1.6×9.25=14.8$
(2)原式$=0.6÷(1.5×0.8)=0.6÷1.2=0.5$
(3)原式$=12.48÷(4×1.2)=12.48÷4.8=2.6$
(4)原式$=(25+\frac {3}{4})×4+\frac {1}{25}=100+3+\frac {1}{25}=103\frac {1}{25}$
(5)原式$=\frac {6}{7}÷\frac {1}{6}×\frac {7}{12}-\frac {3}{5}=3-\frac {3}{5}=2\frac {2}{5}$
(6)原式$=(999\frac {8}{9}+\frac {1}{9})+(99\frac {8}{9}+\frac {1}{9})+(9\frac {8}{9}+\frac {1}{9})=1000+100+10=1110$