2025年小升初考试新题型新考法真题精选详解数学


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《2025年小升初考试新题型新考法真题精选详解数学》

1. $2020\div2020\frac{2020}{2021}+2023\times\frac{2021}{2022}$
答案: 原式=2020÷(2020×1$\frac{1}{2021}$)+(2022 + 1)×$\frac{2021}{2022}$
   =2020÷2020×$\frac{2021}{2022}$+2022×$\frac{2021}{2022}$+$\frac{2021}{2022}$
   =2021+$\frac{2021}{2022}$×2
   =2021+$\frac{4042}{2022}$
   =2022$\frac{1010}{1011}$
2. $4\times5\frac{3}{4}+5\times6\frac{4}{5}+6\times7\frac{5}{6}+7\times8\frac{6}{7}+8\times9\frac{7}{8}$
答案: 原式=4×5 + 4×$\frac{3}{4}$+5×6 + 5×$\frac{4}{5}$+6×7 + 6×$\frac{5}{6}$+7×8 + 7×$\frac{6}{7}$+8×9 + 8×$\frac{7}{8}$
   =20 + 3+30 + 4+42 + 5+56 + 6+72 + 7
   =245
3. $333387\frac{1}{2}\times79 + 790\times66661\frac{1}{4}$
答案: 原式=333387.5×79 + 790×66661.25
   =79×(333387.5 + 666612.5)
   =79×1000000
   =79000000
4. $51\frac{2}{3}\times\frac{3}{5}+71\frac{3}{4}\times\frac{4}{7}+91\frac{4}{5}\div\frac{9}{5}$
答案: 原式=(50+$\frac{5}{3}$)×$\frac{3}{5}$+(70+$\frac{7}{4}$)×$\frac{4}{7}$+(90+$\frac{9}{5}$)×$\frac{5}{9}$
   =50×$\frac{3}{5}$+$\frac{5}{3}$×$\frac{3}{5}$+70×$\frac{4}{7}$+$\frac{7}{4}$×$\frac{4}{7}$+90×$\frac{5}{9}$+$\frac{9}{5}$×$\frac{5}{9}$
   =30 + 1+40 + 1+50 + 1
   =123
5. $13\frac{4}{19}+86\frac{15}{19}\times0.25 + 0.625\times86\frac{15}{19}+86\frac{15}{19}\times0.125$
答案: 原式=86$\frac{15}{19}$×(0.25 + 0.625 + 0.125)+13$\frac{4}{19}$
   =86$\frac{15}{19}$×1+13$\frac{4}{19}$
   =86$\frac{15}{19}$+13$\frac{4}{19}$
   =100
6. $9999\times2222 + 3333\times3334$
答案: 原式=3333×6666+3333×3334
   =3333×(6666 + 3334)
   =33330000
7. $2100\div\left[56\times\left(\frac{3}{7}-\frac{3}{8}\right)\right]$
答案: 原式=2100÷[56×$\frac{3}{7}$−56×$\frac{3}{8}$]
   =2100÷[24 - 21]
   =2100÷3
   =700
8. $9\times\frac{1}{36}+12\times\frac{1}{48}+15\times\frac{1}{75}+18\times\frac{1}{90}+21\times\frac{1}{126}+24\times\frac{1}{144}+27\times\frac{1}{216}+30\times\frac{1}{240}$
答案: 原式=$\frac{1}{4}$+$\frac{1}{4}$+$\frac{1}{5}$+$\frac{1}{5}$+$\frac{1}{6}$+$\frac{1}{6}$+$\frac{1}{8}$+$\frac{1}{8}$
   =$\frac{1}{2}$+$\frac{2}{5}$+$\frac{1}{3}$+$\frac{1}{4}$
   =1$\frac{29}{60}$
9. $\left(\frac{3}{8}+\frac{1}{27}\right)\times16+\frac{11}{27}$
答案: 原式=$\frac{3}{8}$×16+$\frac{1}{27}$×16+$\frac{11}{27}$
   =6+$\frac{16}{27}$+$\frac{11}{27}$
   =6 + 1
   =7
10. $18\times\frac{5}{9}+0.65\times\frac{8}{13}-\frac{2}{9}\times18+\frac{5}{13}\div1\frac{7}{13}$
答案: 原式=18×$\frac{5}{9}$−$\frac{2}{9}$×18+$\frac{13}{20}$×$\frac{8}{13}$+$\frac{5}{13}$×$\frac{13}{20}$
   =18×($\frac{5}{9}$−$\frac{2}{9}$)+$\frac{13}{20}$×($\frac{8}{13}$+$\frac{5}{13}$)
   =18×$\frac{1}{3}$+$\frac{13}{20}$×1
   =6+$\frac{13}{20}$
   =6$\frac{13}{20}$
11. $139\times\frac{137}{138}+137\times1\frac{1}{138}$
答案: 原式=(138 + 1)×$\frac{137}{138}$+137×(1+$\frac{1}{138}$)
   =138×$\frac{137}{138}$+$\frac{137}{138}$+137+$\frac{137}{138}$
   =137×2+$\frac{137}{138}$×2
   =274+$\frac{137}{69}$
   =275$\frac{68}{69}$
12. $2024\times101.1 - 202.3\times1011$
答案: 原式=2024×101.1−2023×101.1
   =(2024−2023)×101.1
   =1×101.1
   =101.1
13. $\frac{2025\times2026 + 2025}{2026}\times\frac{2026\times2027 + 2026}{2027}$
答案: 原式=$\frac{2025×(2026 + 1)}{2026}$×$\frac{2026×(2027 + 1)}{2027}$
   =$\frac{2025×2027}{2026}$×$\frac{2026×2028}{2027}$
   =2025×2028
   =4106700

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