《2025年校内巩固六年级数学上册苏教版》

1. 直接写出得数。
$21×\frac{5}{14}=$$\frac{15}{2}$ $1÷\frac{1}{3}=$3 $\frac{1}{4}÷\frac{2}{3}=$$\frac{3}{8}$ $8×\frac{1}{6}=$$\frac{4}{3}$
$\frac{1}{5}÷\frac{3}{5}=$$\frac{1}{3}$ $\frac{1}{4}+\frac{1}{3}=$$\frac{7}{12}$ $5-\frac{2}{5}=$$\frac{23}{5}$ $\frac{7}{10}×\frac{4}{7}=$$\frac{2}{5}$

答案： $\frac{15}{2}$；3；$\frac{3}{8}$；$\frac{4}{3}$；$\frac{1}{3}$；$\frac{7}{12}$；$\frac{23}{5}$；$\frac{2}{5}$

2. 计算下面各题,能简算的要简算。
$5×(\frac{2}{5}+\frac{1}{6})×6$ $98×\frac{4}{7}-98×\frac{3}{7}$ $(\frac{1}{3}-\frac{1}{4})÷\frac{1}{2}+\frac{5}{6}$
$(\frac{1}{2}+\frac{1}{3}+\frac{1}{4})×24$ $\frac{4}{9}×\frac{1}{6}+\frac{5}{9}÷6$ $\frac{13}{12}-(\frac{1}{12}+\frac{1}{5})$
$\frac{32}{33}×32$ $\frac{7}{24}+9÷\frac{8}{3}+\frac{5}{8}$ $\frac{1}{4}+\frac{3}{4}×(\frac{1}{5}-\frac{1}{6})$

答案： 1. $5×(\frac{2}{5}+\frac{1}{6})×6$
$\begin{aligned}&=5×6×\frac{2}{5}+5×6×\frac{1}{6}\\&=12+5\\&=17\end{aligned}$
2. $98×\frac{4}{7}-98×\frac{3}{7}$
$\begin{aligned}&=98×(\frac{4}{7}-\frac{3}{7})\\&=98×\frac{1}{7}\\&=14\end{aligned}$
3. $(\frac{1}{3}-\frac{1}{4})÷\frac{1}{2}+\frac{5}{6}$
$\begin{aligned}&=(\frac{4}{12}-\frac{3}{12})×2+\frac{5}{6}\\&=\frac{1}{12}×2+\frac{5}{6}\\&=\frac{1}{6}+\frac{5}{6}\\&=1\end{aligned}$
4. $(\frac{1}{2}+\frac{1}{3}+\frac{1}{4})×24$
$\begin{aligned}&=\frac{1}{2}×24+\frac{1}{3}×24+\frac{1}{4}×24\\&=12+8+6\\&=26\end{aligned}$
5. $\frac{4}{9}×\frac{1}{6}+\frac{5}{9}÷6$
$\begin{aligned}&=\frac{4}{9}×\frac{1}{6}+\frac{5}{9}×\frac{1}{6}\\&=(\frac{4}{9}+\frac{5}{9})×\frac{1}{6}\\&=1×\frac{1}{6}\\&=\frac{1}{6}\end{aligned}$
6. $\frac{13}{12}-(\frac{1}{12}+\frac{1}{5})$
$\begin{aligned}&=\frac{13}{12}-\frac{1}{12}-\frac{1}{5}\\&=1-\frac{1}{5}\\&=\frac{4}{5}\end{aligned}$
7. $\frac{32}{33}×32$
$\begin{aligned}&=\frac{32}{33}×(33-1)\\&=\frac{32}{33}×33-\frac{32}{33}×1\\&=32-\frac{32}{33}\\&=31\frac{1}{33}\end{aligned}$
8. $\frac{7}{24}+9÷\frac{8}{3}+\frac{5}{8}$
$\begin{aligned}&=\frac{7}{24}+9×\frac{3}{8}+\frac{5}{8}\\&=\frac{7}{24}+\frac{27}{8}+\frac{5}{8}\\&=\frac{7}{24}+(\frac{27}{8}+\frac{5}{8})\\&=\frac{7}{24}+4\\&=4\frac{7}{24}\end{aligned}$
9. $\frac{1}{4}+\frac{3}{4}×(\frac{1}{5}-\frac{1}{6})$
$\begin{aligned}&=\frac{1}{4}+\frac{3}{4}×\frac{1}{30}\\&=\frac{1}{4}+\frac{1}{40}\\&=\frac{10}{40}+\frac{1}{40}\\&=\frac{11}{40}\end{aligned}$

3. 解方程。
$\frac{4}{5}x×\frac{3}{2}= 6$ $x-\frac{1}{4}x= \frac{7}{8}$

答案： 解方程
1. $\frac{4}{5}x×\frac{3}{2}= 6$
解：$\frac{12}{10}x = 6$
$\frac{6}{5}x = 6$
$x = 6×\frac{5}{6}$
$x = 5$
2. $x-\frac{1}{4}x= \frac{7}{8}$
解：$\frac{3}{4}x = \frac{7}{8}$
$x = \frac{7}{8}×\frac{4}{3}$
$x = \frac{7}{6}$