《2025年初一入学分班测试卷七年级数学苏科版》

1. 直接写出得数。(10分)
$10×31\% = $3.1 $1÷25\% = $4 $72\% -48\% = $0.24
$\frac {3}{4}-\frac {1}{3}= $$\frac{5}{12}$ $0×20\% = $0 $\frac {2}{5}÷\frac {8}{3}= $$\frac{3}{20}$
$50\% ×40\% = $0.2 $2÷5\% = $40
$1.8-18×0= $1.8 $\frac {1}{2}×\frac {1}{3}÷\frac {1}{2}×\frac {1}{3}= $$\frac{1}{9}$

答案： 3.1 4 0.24 $\frac{5}{12}$ 0 $\frac{3}{20}$ 0.2 40 1.8 $\frac{1}{9}$

2. 下面各题,怎样简便就怎样算。(8分)
$21.7-\frac {3}{7}+7.3-\frac {11}{7}$ $(\frac {5}{6}+\frac {2}{3}-\frac {7}{9})÷\frac {1}{36}$
$\frac {3}{25}×101-3÷25$ $\frac {1}{2}÷[(\frac {3}{4}-\frac {5}{8})×\frac {1}{10}]$

答案： $21.7-\frac{3}{7}+7.3-\frac{11}{7}=(21.7+7.3)-(\frac{3}{7}+\frac{11}{7})=29-2=27$ $(\frac{5}{6}+\frac{2}{3}-\frac{7}{9})÷\frac{1}{36}=\frac{5}{6}×36+\frac{2}{3}×36-\frac{7}{9}×36=30+24-28=26$ $\frac{3}{25}×101-3÷25=\frac{3}{25}×101-\frac{3}{25}=\frac{3}{25}×(101-1)=\frac{3}{25}×100=12$ 40