《2025年名校课堂七年级数学上册人教版山西专版》

计算：
(1)$-0.75×(-\frac {3}{2})÷(-\frac {9}{4}).$
(2)$3×(-1)+2^{2}+|-4|.$
(3)$(-1)×(-4)+3^{2}÷(7-4).$
(4)$(-5)×3\frac {1}{3}+2×3\frac {1}{3}+(-6)×3\frac {1}{3}.$
(5)$(-6)^{2}×[-\frac {1}{4}+(-\frac {2}{9})-(-\frac {7}{18})].$
(6)$(-1)^{4}×|-8|+(-2)^{3}×(\frac {1}{2})^{2}.$
(7)$4+16÷(-2)^{3}×|-3-1|.$
(8)$(-5)^{3}×(-\frac {3}{5})+32÷(-2^{2})×(-1\frac {1}{4}).$
(9)$-1^{2026}+8÷(-2)^{2}-|-4|×5.$
(10)$(-4)^{2}-(1-\frac {2}{3})÷2\frac {1}{3}×[6+(-3)^{3}].$

答案：
(1)原式= $-\frac {3}{4} × (-\frac {3}{2}) × (-\frac {4}{9}) = -\frac {1}{2}$．
(2)原式= $-3 + 4 + 4 = 5$．
(3)原式= $(-1) × (-4) + 9 ÷ 3 = 4 + 3 = 7$．
(4)原式= $[(-5) + 2 + (-6)] × 3\frac {1}{3} = (-9) × \frac {10}{3} = -30$．
(5)原式= $36 × (-\frac {1}{4} - \frac {2}{9} + \frac {7}{18}) = 36 × (-\frac {1}{4}) + 36 × (-\frac {2}{9}) + 36 × \frac {7}{18} = -9 - 8 + 14 = -3$．
(6)原式= $1 × 8 - 8 × \frac {1}{4} = 8 - 2 = 6$．
(7)原式= $4 + 16 ÷ (-8) × 4 = 4 + (-2) × 4 = 4 + (-8) = -4$．
(8)原式= $(-125) × (-\frac {3}{5}) + 32 ÷ (-4) × (-\frac {5}{4}) = 75 + (-8) × (-\frac {5}{4}) = 75 + 10 = 85$．
(9)原式= $-1 + 8 ÷ 4 - 4 × 5 = -1 + 2 - 20 = -19$．
(10)原式= $16 - \frac {1}{3} ÷ \frac {7}{3} × (6 - 27) = 16 - \frac {1}{3} × \frac {3}{7} × (-21) = 16 + 3 = 19$．