1. 下列方程组属于二元一次方程组的是(
A.$\left\{\begin{array}{l} 2x+\frac {1}{y}= 2,\\ 3x+y= 0\end{array} \right. $
B.$\left\{\begin{array}{l} x+y= 2,\\ 2xy= 5\end{array} \right. $
C.$\left\{\begin{array}{l} x-2y= 6,\\ x+6y= 7\end{array} \right. $
D.$\left\{\begin{array}{l} 3x^{2}= 5y,\\ \frac {x}{4}+\frac {y}{3}= 1\end{array} \right. $
C
)A.$\left\{\begin{array}{l} 2x+\frac {1}{y}= 2,\\ 3x+y= 0\end{array} \right. $
B.$\left\{\begin{array}{l} x+y= 2,\\ 2xy= 5\end{array} \right. $
C.$\left\{\begin{array}{l} x-2y= 6,\\ x+6y= 7\end{array} \right. $
D.$\left\{\begin{array}{l} 3x^{2}= 5y,\\ \frac {x}{4}+\frac {y}{3}= 1\end{array} \right. $
答案:
C
2. 若关于$x,y的方程x^{|a|-1}-(a-2)y= 5$是二元一次方程,则(
A.$a>2$
B.$a= 2$
C.$a= -2$
D.$a<-2$
C
)A.$a>2$
B.$a= 2$
C.$a= -2$
D.$a<-2$
答案:
C
3. 用代入法解方程组$\left\{\begin{array}{l} 2x+3y= 8①,\\ 3x-5y= 5②\end{array} \right. $有以下过程,其中开始出现错误的一步是(
(1)由①,得$x= \frac {8-3y}{2}$③;
(2)把③代入②,得$3×\frac {8-3y}{2}-5y= 5$;
(3)去分母,得$24-9y-10y= 5$;
(4)解得$y= 1$,再由③,得$x= 2.5$。
A. (1)
B. (2)
C. (3)
D. (4)
C
)(1)由①,得$x= \frac {8-3y}{2}$③;
(2)把③代入②,得$3×\frac {8-3y}{2}-5y= 5$;
(3)去分母,得$24-9y-10y= 5$;
(4)解得$y= 1$,再由③,得$x= 2.5$。
A. (1)
B. (2)
C. (3)
D. (4)
答案:
C
4. 若方程组$\left\{\begin{array}{l} 4x+3y= 2k+2,\\ 2x+y= k\end{array} \right. 的解x,y$的值互为相反数,则$k$的值为(
A.2
B.3
C.-2
D.-1
C
)A.2
B.3
C.-2
D.-1
答案:
C
5. 已知关于$x,y的二元一次方程组\left\{\begin{array}{l} ax-y= 4,\\ 3x+by= 4\end{array} \right. 的解是\left\{\begin{array}{l} x= 2,\\ y= -2,\end{array} \right. 则a+b$的值是(
A.1
B.2
C.-1
D.0
B
)A.1
B.2
C.-1
D.0
答案:
B
查看更多完整答案,请扫码查看