《2025年课本配套练习六年级数学上册苏教版》

1. 计算下面各题。
$2 - \frac{8}{15} × \frac{9}{16}$
$1 - \frac{8}{9} × \frac{3}{8} × \frac{1}{7}$
$[1 - (\frac{3}{4} - \frac{3}{8})] ÷ \frac{5}{6}$
$5 - (\frac{6}{7} ÷ \frac{3}{14} + \frac{6}{13})$
$6 ÷ (\frac{3}{5} + \frac{3}{4})$
$1 - \frac{6}{7} ÷ \frac{3}{7} × \frac{3}{16}$

答案： 1.
$2 - \frac{8}{15} × \frac{9}{16}$
$= 2 - \frac{3}{10}$
$= \frac{20}{10} - \frac{3}{10}$
$= \frac{17}{10}$
$= 1.7$
2.
$1 - \frac{8}{9} × \frac{3}{8} × \frac{1}{7}$
$= 1 - \frac{1}{3} × \frac{1}{7}$
$= 1 - \frac{1}{21}$
$= \frac{21}{21} - \frac{1}{21}$
$= \frac{20}{21}$
3.
$[1 - (\frac{3}{4} - \frac{3}{8})] ÷ \frac{5}{6}$
$= [1 - \frac{3}{8}] ÷ \frac{5}{6}$
$= \frac{5}{8} ÷ \frac{5}{6}$
$= \frac{5}{8} × \frac{6}{5}$
$= \frac{3}{4}$
4.
$5 - (\frac{6}{7} ÷ \frac{3}{14} + \frac{6}{13})$
$= 5 - (4 + \frac{6}{13})$
$= 5 - 4 - \frac{6}{13}$
$= 1 - \frac{6}{13}$
$= \frac{7}{13}$
5.
$6 ÷ (\frac{3}{5} + \frac{3}{4})$
$= 6 ÷ (\frac{12}{20} + \frac{15}{20})$
$= 6 ÷ \frac{27}{20}$
$= 6 × \frac{20}{27}$
$= \frac{40}{9}$
6.
$1 - \frac{6}{7} ÷ \frac{3}{7} × \frac{3}{16}$
$= 1 - 2 × \frac{3}{16}$
$= 1 - \frac{3}{8}$
$= \frac{5}{8}$

2. 用简便方法计算。
$\frac{6}{5} × \frac{2}{15} + \frac{2}{15} × \frac{4}{5}$
$\frac{6}{11} ÷ 4 - \frac{1}{4} × \frac{5}{11}$
$\frac{7}{9} × \frac{7}{11} + \frac{7}{9} × \frac{4}{11}$
$\frac{32}{33} × 32$

答案： 1.
$\frac{6}{5} × \frac{2}{15} + \frac{2}{15} × \frac{4}{5}$
$=\frac{2}{15}×(\frac{6}{5}+\frac{4}{5})$
$=\frac{2}{15}× 2$
$=\frac{4}{15}$
2.
$\frac{6}{11} ÷ 4 - \frac{1}{4} × \frac{5}{11}$
$=\frac{6}{11} × \frac{1}{4} - \frac{1}{4} × \frac{5}{11}$
$=\frac{1}{4}×(\frac{6}{11}-\frac{5}{11})$
$=\frac{1}{4}×\frac{1}{11}$
$=\frac{1}{44}$
3.
$\frac{7}{9} × \frac{7}{11} + \frac{7}{9} × \frac{4}{11}$
$=\frac{7}{9}×(\frac{7}{11}+\frac{4}{11})$
$=\frac{7}{9}× 1$
$=\frac{7}{9}$
4.
$\frac{32}{33} × 32$
$=\frac{32}{33}×(33 - 1)$
$=\frac{32}{33}× 33 - \frac{32}{33}$
$=32 - \frac{32}{33}$
$=31\frac{1}{33}$