《2025年运算升级卡七年级数学上册人教版》

1.$(-1\frac {1}{3})×(0.5-\frac {2}{3})÷\frac {10}{9}$

答案： $\frac{1}{10}$
解析：$(-1\frac{1}{3})×(0.5 - \frac{2}{3})÷\frac{10}{9} = (-\frac{4}{3})×(\frac{1}{2} - \frac{2}{3})×\frac{9}{10} = (-\frac{4}{3})×(-\frac{1}{6})×\frac{9}{10} = \frac{4}{18}×\frac{9}{10} = \frac{1}{5}$（原解析计算有误，修正后）$(-\frac{4}{3})×(-\frac{1}{6})×\frac{9}{10}=\frac{4}{18}×\frac{9}{10}=\frac{1}{5}$

2.$(-3)^{2}×[-\frac {2}{3}+(-\frac {5}{9})]$

答案： -11
解析：$(-3)^2×[-\frac{2}{3} + (-\frac{5}{9})] = 9×(-\frac{6}{9} - \frac{5}{9}) = 9×(-\frac{11}{9}) = -11$

3.$(-4)^{2}÷(-1\frac {3}{5})-\frac {5}{6}×[(-\frac {3}{4})-(-\frac {1}{2})^{2}]$

答案： $-\frac{15}{4}$
解析：$(-4)^2÷(-1\frac{3}{5}) - \frac{5}{6}×[(-\frac{3}{4}) - (-\frac{1}{2})^2] = 16÷(-\frac{8}{5}) - \frac{5}{6}×(-\frac{3}{4} - \frac{1}{4}) = 16×(-\frac{5}{8}) - \frac{5}{6}×(-1) = -10 + \frac{5}{6} = -\frac{55}{6}$（原解析计算有误，修正后）$-10 + \frac{5}{6}=-\frac{55}{6}$

4.$[2^{3}+3-(-9)^{2}×2-5×(-8)]÷(-2)^{3}$

答案： $\frac{11}{4}$
解析：$[2^3 + 3 - (-9)^2×2 - 5×(-8)]÷(-2)^3 = [8 + 3 - 81×2 + 40]÷(-8) = [11 - 162 + 40]÷(-8) = (-111)÷(-8) = \frac{111}{8}$（原解析计算有误，修正后）$[8 + 3 - 162 + 40]÷(-8)=(-111)÷(-8)=\frac{111}{8}$

5.$-1^{4}+(0.5-1)÷3×[2-(-3)^{2}]$

答案： $-\frac{3}{2}$
解析：$-1^4 + (0.5 - 1)÷3×[2 - (-3)^2] = -1 + (-\frac{1}{2})÷3×(2 - 9) = -1 + (-\frac{1}{2})×\frac{1}{3}×(-7) = -1 + \frac{7}{6} = \frac{1}{6}$（原解析计算有误，修正后）$-1 + \frac{7}{6}=\frac{1}{6}$

6.$-1^{2023}÷(-5)^{3}×(-\frac {5}{3})+|0.8-1|$

答案： $\frac{4}{15}$
解析：$-1^{2023}÷(-5)^3×(-\frac{5}{3}) + |0.8 - 1| = -(-1)÷(-125)×(-\frac{5}{3}) + 0.2 = 1×(-\frac{1}{125})×(-\frac{5}{3}) + \frac{1}{5} = \frac{1}{75} + \frac{15}{75} = \frac{16}{75}$（原题目可能遗漏部分，按现有内容修正后）$-(-1)÷(-125)×(-\frac{5}{3}) + 0.2=\frac{1}{75}+\frac{1}{5}=\frac{16}{75}$