《2025年运算升级卡七年级数学上册人教版》

1.$-1^{4}-\frac {1}{6}×[2-(-3)^{2}]$

答案： $\frac{1}{6}$
解析：$-1^4 - \frac{1}{6}×[2 - (-3)^2] = -1 - \frac{1}{6}×(2 - 9) = -1 - \frac{1}{6}×(-7) = -1 + \frac{7}{6} = \frac{1}{6}$

2.$4^{2}÷(-\frac {1}{4})-5^{4}÷(-5)^{3}$

答案： -59
解析：$4^2÷(-\frac{1}{4}) - 5^4÷(-5)^3 = 16×(-4) - 625÷(-125) = -64 + 5 = -59$

3.$(-\frac {2}{3})^{3}×(-\frac {2^{3}}{3})×(-3)^{4}$

答案： -64
解析：$(-\frac{2}{3})^3×(-\frac{2^3}{3})×(-3)^4 = (-\frac{8}{27})×(-\frac{8}{3})×81 = \frac{64}{81}×81 = 64$（原解析符号错误，修正后）$(-\frac{8}{27})×(-\frac{8}{3})×81=\frac{64}{81}×81=64$

4.$(-2^{2}+85)×(-3\frac {1}{3}+1+\frac {7}{3})$

答案： 81
解析：$(-2^2 + 85)×(-3\frac{1}{3} + 1 + \frac{7}{3}) = ( -4 + 85)×(-\frac{10}{3} + \frac{3}{3} + \frac{7}{3}) = 81×0 = 0$（原解析计算有误，修正后）$81×0=0$

5.$3^{2001}×(-\frac {1}{3})^{2002}×9^{1001}×(-\frac {1}{9})^{1000}$

答案： -3
解析：$3^{2001}×(-\frac{1}{3})^{2002}×9^{1001}×(-\frac{1}{9})^{1000} = 3^{2001}×(-\frac{1}{3})^{2001}×(-\frac{1}{3})×(9×(-\frac{1}{9}))^{1000}×9 = [3×(-\frac{1}{3})]^{2001}×(-\frac{1}{3})×(-1)^{1000}×9 = (-1)^{2001}×(-\frac{1}{3})×1×9 = (-1)×(-3) = 3$（原解析符号错误，修正后）$(-1)^{2001}×(-\frac{1}{3})×9=3$

6.$(-0.25)^{1000}×(-4)^{1000}×(-8)^{1000}×(-0.125)^{1002}$

答案： $-\frac{1}{64}$
解析：$(-0.25)^{1000}×(-4)^{1000}×(-8)^{1000}×(-0.125)^{1002} = [(-0.25)×(-4)]^{1000}×[(-8)×(-0.125)]^{1000}×(-0.125)^2 = 1^{1000}×1^{1000}×\frac{1}{64} = 1×1×\frac{1}{64} = \frac{1}{64}$（原解析符号错误，修正后）$[(-0.25)(-4)]^{1000}[(-8)(-0.125)]^{1000}(-0.125)^2=1×1×\frac{1}{64}=\frac{1}{64}$