《2025年运算升级卡七年级数学上册人教版》

1.$-4^{2}-(-3)^{2}+(-1)^{7}$

答案： -26
解析：$-4^2 - (-3)^2 + (-1)^7 = -16 - 9 + (-1) = -25 - 1 = -26$

2.$\frac {(-3)^{2}}{5}-(-\frac {3}{4})^{2}-(\frac {1}{2})^{3}$

答案： $\frac{163}{240}$
解析：$\frac{(-3)^2}{5} - (-\frac{3}{4})^2 - (\frac{1}{2})^3 = \frac{9}{5} - \frac{9}{16} - \frac{1}{8} = \frac{144}{80} - \frac{45}{80} - \frac{10}{80} = \frac{89}{80} - \frac{10}{80} = \frac{79}{80}$（原解析计算有误，修正后）$\frac{9}{5}-\frac{9}{16}-\frac{1}{8}=\frac{144}{80}-\frac{45}{80}-\frac{10}{80}=\frac{89}{80}$

3.$(-9)÷(-\frac {1}{3})^{3}×\frac {5}{3^{4}}$

答案： 135
解析：$(-9)÷(-\frac{1}{3})^3×\frac{5}{3^4}=(-9)÷(-\frac{1}{27})×\frac{5}{81}=(-9)×(-27)×\frac{5}{81}=243×\frac{5}{81}=135$

4.$(-0.2)^{3}×(-\frac {1}{2})^{3}+(\frac {1}{10})^{2}$

答案： $\frac{101}{10000}$
解析：$(-0.2)^3×(-\frac{1}{2})^3 + (\frac{1}{10})^2 = (-\frac{1}{5})^3×(-\frac{1}{2})^3 + \frac{1}{100} = [(-\frac{1}{5})×(-\frac{1}{2})]^3 + \frac{1}{100} = (\frac{1}{10})^3 + \frac{1}{100} = \frac{1}{1000} + \frac{10}{1000} = \frac{11}{1000}$（原解析计算有误，修正后）$(-\frac{1}{5})^3×(-\frac{1}{2})^3=\frac{1}{1000}$，$\frac{1}{100}=\frac{10}{1000}$，$\frac{1}{1000}+\frac{10}{1000}=\frac{11}{1000}$

5.$-1^{4}×(-0.3)^{3}×(-\frac {2^{2}}{3})$

答案： $-\frac{9}{1250}$
解析：$-1^4×(-0.3)^3×(-\frac{2^2}{3})=-1×(-\frac{27}{1000})×(-\frac{4}{3})=-1×\frac{27}{1000}×\frac{4}{3}=-\frac{9}{250}$（原解析计算有误，修正后）$-1×(-\frac{27}{1000})×(-\frac{4}{3})=-\frac{9}{250}$

6.$|-5|^{2}×[-(\frac {2}{5})^{2}]÷(-2)^{4}$

答案： $-\frac{1}{4}$
解析：$|-5|^2×[-(\frac{2}{5})^2]÷(-2)^4=25×(-\frac{4}{25})÷16=(-4)÷16=-\frac{1}{4}$

7.$-1^{2021}+(-1)^{2022}+(-1)^{2023}$

答案： -1
解析：$-1^{2021} + (-1)^{2022} + (-1)^{2023} = -1 + 1 + (-1) = 0 - 1 = -1$

8.$-1^{4}-(2.5-2)×\frac {1}{4}×[4-(-1)^{3}]$

答案： $-\frac{13}{8}$
解析：$-1^4 - (2.5 - 2)×\frac{1}{4}×[4 - (-1)^3] = -1 - 0.5×\frac{1}{4}×(4 + 1) = -1 - \frac{1}{2}×\frac{1}{4}×5 = -1 - \frac{5}{8} = -\frac{13}{8}$