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2025年练习与测试六年级数学上册苏教版培优版
注：目前有些书本章节名称可能整理的还不是很完善，但都是按照顺序排列的，请同学们按照顺序仔细查找。练习册 2025年练习与测试六年级数学上册苏教版培优版 答案主要是用来给同学们做完题方便对答案用的，请勿直接抄袭。
1. 直接写出得数。(4分)
$\frac{3}{4} × \frac{1}{9} = $
$\frac{5}{6} × \frac{3}{10} = $
$\frac{3}{4} × \frac{1}{9} = $
$\frac{1}{12}$
$\frac{2}{3} × 210 = $140
$32 ÷ \frac{4}{5} = $40
$7 × \frac{5}{14} = $$\frac{5}{2}$
$\frac{5}{6} × \frac{3}{10} = $
$\frac{1}{4}$
$\frac{2}{5} ÷ 4 = $$\frac{1}{10}$
$\frac{5}{12} ÷ \frac{5}{6} = $$\frac{1}{2}$
$\frac{1}{8} × \frac{1}{9} ÷ \frac{1}{8} × \frac{1}{9} = $$\frac{1}{81}$
答案：
$\frac{1}{12}$；140；40；$\frac{5}{2}$；$\frac{1}{4}$；$\frac{1}{10}$；$\frac{1}{2}$；$\frac{1}{81}$
2. 解方程。(6分)
$x ÷ \frac{3}{4} = \frac{4}{3}$ $x + 40\%x = 98$ $\frac{4}{5} + \frac{4}{5}x = 1$
$x ÷ \frac{3}{4} = \frac{4}{3}$ $x + 40\%x = 98$ $\frac{4}{5} + \frac{4}{5}x = 1$
答案：
解方程
1. $ x ÷ \frac{3}{4} = \frac{4}{3} $
解：$ x = \frac{4}{3} × \frac{3}{4} $
$ x = 1 $
2. $ x + 40\%x = 98 $
解：$ 1.4x = 98 $
$ x = 98 ÷ 1.4 $
$ x = 70 $
3. $ \frac{4}{5} + \frac{4}{5}x = 1 $
解：$ \frac{4}{5}x = 1 - \frac{4}{5} $
$ \frac{4}{5}x = \frac{1}{5} $
$ x = \frac{1}{5} ÷ \frac{4}{5} $
$ x = \frac{1}{4} $
1. $ x ÷ \frac{3}{4} = \frac{4}{3} $
解：$ x = \frac{4}{3} × \frac{3}{4} $
$ x = 1 $
2. $ x + 40\%x = 98 $
解：$ 1.4x = 98 $
$ x = 98 ÷ 1.4 $
$ x = 70 $
3. $ \frac{4}{5} + \frac{4}{5}x = 1 $
解：$ \frac{4}{5}x = 1 - \frac{4}{5} $
$ \frac{4}{5}x = \frac{1}{5} $
$ x = \frac{1}{5} ÷ \frac{4}{5} $
$ x = \frac{1}{4} $
3. 计算下面各题,能简算的要简算。(18分)
$\frac{12}{9} - (\frac{2}{9} + \frac{3}{4})$ $\frac{2}{5} × \frac{6}{11} + 40\% × \frac{5}{11}$ $48 × \frac{3}{7} + 3 ÷ 7$
$(\frac{1}{2} - \frac{1}{3}) × \frac{1}{3} ÷ \frac{1}{4}$ $\frac{3}{10} × [\frac{7}{8} ÷ (\frac{3}{5} - \frac{1}{4})]$ $\frac{9}{16} ÷ (\frac{3}{8} + \frac{1}{16})$
$\frac{12}{9} - (\frac{2}{9} + \frac{3}{4})$ $\frac{2}{5} × \frac{6}{11} + 40\% × \frac{5}{11}$ $48 × \frac{3}{7} + 3 ÷ 7$
$(\frac{1}{2} - \frac{1}{3}) × \frac{1}{3} ÷ \frac{1}{4}$ $\frac{3}{10} × [\frac{7}{8} ÷ (\frac{3}{5} - \frac{1}{4})]$ $\frac{9}{16} ÷ (\frac{3}{8} + \frac{1}{16})$
答案：
1.
$\frac{12}{9} - (\frac{2}{9} + \frac{3}{4})$
$=\frac{12}{9} - \frac{2}{9} - \frac{3}{4}$
$=\frac{10}{9} - \frac{3}{4}$
$=\frac{40}{36} - \frac{27}{36}$
$=\frac{13}{36}$
2.
$\frac{2}{5} × \frac{6}{11} + 40\% × \frac{5}{11}$
$=\frac{2}{5}×\frac{6}{11}+\frac{2}{5}×\frac{5}{11}$
$=\frac{2}{5}×(\frac{6}{11}+\frac{5}{11})$
$=\frac{2}{5}×1$
$=\frac{2}{5}$
3.
$48 × \frac{3}{7} + 3 ÷ 7$
$=48×\frac{3}{7}+\frac{3}{7}$
$=\frac{3}{7}×(48 + 1)$
$=\frac{3}{7}×49$
$=21$
4.
$(\frac{1}{2} - \frac{1}{3}) × \frac{1}{3} ÷ \frac{1}{4}$
$=(\frac{3}{6}-\frac{2}{6})×\frac{1}{3}÷\frac{1}{4}$
$=\frac{1}{6}×\frac{1}{3}×4$
$=\frac{1}{18}×4$
$=\frac{2}{9}$
5.
$\frac{3}{10} × [\frac{7}{8} ÷ (\frac{3}{5} - \frac{1}{4})]$
$=\frac{3}{10}×[\frac{7}{8}÷(\frac{12}{20}-\frac{5}{20})]$
$=\frac{3}{10}×(\frac{7}{8}÷\frac{7}{20})$
$=\frac{3}{10}×(\frac{7}{8}×\frac{20}{7})$
$=\frac{3}{10}×\frac{5}{2}$
$=\frac{3}{4}$
6.
$\frac{9}{16} ÷ (\frac{3}{8} + \frac{1}{16})$
$=\frac{9}{16}÷(\frac{6}{16}+\frac{1}{16})$
$=\frac{9}{16}÷\frac{7}{16}$
$=\frac{9}{16}×\frac{16}{7}$
$=\frac{9}{7}$
$\frac{12}{9} - (\frac{2}{9} + \frac{3}{4})$
$=\frac{12}{9} - \frac{2}{9} - \frac{3}{4}$
$=\frac{10}{9} - \frac{3}{4}$
$=\frac{40}{36} - \frac{27}{36}$
$=\frac{13}{36}$
2.
$\frac{2}{5} × \frac{6}{11} + 40\% × \frac{5}{11}$
$=\frac{2}{5}×\frac{6}{11}+\frac{2}{5}×\frac{5}{11}$
$=\frac{2}{5}×(\frac{6}{11}+\frac{5}{11})$
$=\frac{2}{5}×1$
$=\frac{2}{5}$
3.
$48 × \frac{3}{7} + 3 ÷ 7$
$=48×\frac{3}{7}+\frac{3}{7}$
$=\frac{3}{7}×(48 + 1)$
$=\frac{3}{7}×49$
$=21$
4.
$(\frac{1}{2} - \frac{1}{3}) × \frac{1}{3} ÷ \frac{1}{4}$
$=(\frac{3}{6}-\frac{2}{6})×\frac{1}{3}÷\frac{1}{4}$
$=\frac{1}{6}×\frac{1}{3}×4$
$=\frac{1}{18}×4$
$=\frac{2}{9}$
5.
$\frac{3}{10} × [\frac{7}{8} ÷ (\frac{3}{5} - \frac{1}{4})]$
$=\frac{3}{10}×[\frac{7}{8}÷(\frac{12}{20}-\frac{5}{20})]$
$=\frac{3}{10}×(\frac{7}{8}÷\frac{7}{20})$
$=\frac{3}{10}×(\frac{7}{8}×\frac{20}{7})$
$=\frac{3}{10}×\frac{5}{2}$
$=\frac{3}{4}$
6.
$\frac{9}{16} ÷ (\frac{3}{8} + \frac{1}{16})$
$=\frac{9}{16}÷(\frac{6}{16}+\frac{1}{16})$
$=\frac{9}{16}÷\frac{7}{16}$
$=\frac{9}{16}×\frac{16}{7}$
$=\frac{9}{7}$
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