2025年快乐口算六年级数学上册人教版


注:目前有些书本章节名称可能整理的还不是很完善,但都是按照顺序排列的,请同学们按照顺序仔细查找。练习册 2025年快乐口算六年级数学上册人教版 答案主要是用来给同学们做完题方便对答案用的,请勿直接抄袭。



《2025年快乐口算六年级数学上册人教版》

1
$ 12 - \frac{7}{8} = $
$ 10 × \frac{3}{7} = $
$ 14 ÷ \frac{4}{7} = $
$ \frac{1}{4} + \frac{2}{3} = $
$ 20 × \frac{1}{6} = $
$ \frac{28}{9} + \frac{4}{9} = $
$ 0.9 ÷ \frac{3}{7} = $
$ \frac{5}{12} ÷ \frac{10}{3} = $
$ 0.6 × \frac{2}{3} = $
$ \frac{1}{7} ÷ \frac{3}{10} = $
$ 0.625 ÷ \frac{5}{8} = $
$ \frac{5}{13} × 26 = $
$ 35 ÷ \frac{7}{9} = $
答案: 1. $12 - \frac{7}{8} = 11\frac{1}{8}$
2. $10 × \frac{3}{7} = \frac{30}{7}$
3. $14 ÷ \frac{4}{7} = 14×\frac{7}{4} = \frac{49}{2}$
4. $\frac{1}{4} + \frac{2}{3} = \frac{3}{12} + \frac{8}{12} = \frac{11}{12}$
5. $20 × \frac{1}{6} = \frac{10}{3}$
6. $\frac{28}{9} + \frac{4}{9} = \frac{32}{9}$
7. $0.9 ÷ \frac{3}{7} = \frac{9}{10}×\frac{7}{3} = \frac{21}{10} = 2.1$
8. $\frac{5}{12} ÷ \frac{10}{3} = \frac{5}{12}×\frac{3}{10} = \frac{1}{8}$
9. $0.6 × \frac{2}{3} = \frac{3}{5}×\frac{2}{3} = \frac{2}{5} = 0.4$
10. $\frac{1}{7} ÷ \frac{3}{10} = \frac{1}{7}×\frac{10}{3} = \frac{10}{21}$
11. $0.625 ÷ \frac{5}{8} = \frac{5}{8}×\frac{8}{5} = 1$
12. $\frac{5}{13} × 26 = 10$
13. $35 ÷ \frac{7}{9} = 35×\frac{9}{7} = 45$
2
$ 4 × \frac{7}{16} × \frac{1}{2} = $
$ 21 × \frac{2}{3} × \frac{3}{7} = $
$ \frac{1}{3} ÷ \frac{7}{9} × \frac{1}{2} = $
$ \frac{2}{9} × \frac{3}{8} ÷ \frac{1}{2} = $
$ \frac{1}{6} × \frac{1}{2} + \frac{1}{3} = $
$ \frac{2}{3} × \frac{3}{8} ÷ \frac{3}{8} = $
$ \frac{9}{14} ÷ \frac{3}{7} ÷ \frac{1}{2} = $
$ 9 ÷ \frac{3}{7} ÷ \frac{1}{3} = $
$ 0.125 ÷ \frac{5}{8} ÷ \frac{1}{2} = $
$ \frac{1}{2} ÷ 6 × \frac{6}{7} = $
$ \frac{5}{12} × \frac{4}{5} ÷ 3 = $
$ 3 ÷ \frac{1}{9} - 17 = $
$ \frac{1}{3} + \frac{3}{4} ÷ \frac{9}{20} = $
答案: 1.
$4×\frac{7}{16}×\frac{1}{2}$
$=\frac{7}{4}×\frac{1}{2}$
$=\frac{7}{8}$
2.
$21×\frac{2}{3}×\frac{3}{7}$
$ = 14×\frac{3}{7}$
$ = 6$
3.
$\frac{1}{3}÷\frac{7}{9}×\frac{1}{2}$
$=\frac{1}{3}×\frac{9}{7}×\frac{1}{2}$
$=\frac{3}{7}×\frac{1}{2}$
$=\frac{3}{14}$
4.
$\frac{2}{9}×\frac{3}{8}÷\frac{1}{2}$
$=\frac{1}{12}×2$
$=\frac{1}{6}$
5.
$\frac{1}{6}×\frac{1}{2}+\frac{1}{3}$
$=\frac{1}{12}+\frac{4}{12}$
$=\frac{5}{12}$
6.
$\frac{2}{3}×\frac{3}{8}÷\frac{3}{8}$
$=\frac{1}{4}÷\frac{3}{8}$(此步可简化为$\frac{2}{3}×1=\frac{2}{3}$,按步骤计算如下)
$=\frac{1}{4}×\frac{8}{3}$
$=\frac{2}{3}$
7.
$\frac{9}{14}÷\frac{3}{7}÷\frac{1}{2}$
$=\frac{9}{14}×\frac{7}{3}×2$
$=\frac{3}{2}×2$
$ = 3$
8.
$9÷\frac{3}{7}÷\frac{1}{3}$
$=9×\frac{7}{3}×3$
$ = 21×3$
$ = 63$
9.
$0.125÷\frac{5}{8}÷\frac{1}{2}$
$=\frac{1}{8}×\frac{8}{5}×2$
$=\frac{1}{5}×2$
$=\frac{2}{5}$
10.
$\frac{1}{2}÷6×\frac{6}{7}$
$=\frac{1}{12}×\frac{6}{7}$
$=\frac{1}{14}$
11.
$\frac{5}{12}×\frac{4}{5}÷3$
$=\frac{1}{3}÷3$
$=\frac{1}{3}×\frac{1}{3}$
$=\frac{1}{9}$
12.
$3÷\frac{1}{9}-17$
$ = 3×9 - 17$
$ = 27 - 17$
$ = 10$
13.
$\frac{1}{3}+\frac{3}{4}÷\frac{9}{20}$
$=\frac{1}{3}+\frac{3}{4}×\frac{20}{9}$
$=\frac{1}{3}+\frac{5}{3}$
$ = 2$
3
$ \left( \frac{2}{5} + \frac{3}{8} \right) × 40 $
$ ( 1.4 + 42 ) × \frac{3}{7} $
$ ( 0.125 + 0.375 ) ÷ \frac{1}{8} $
$ \left( 7 + \frac{14}{3} \right) ÷ 7 $
$ \left( \frac{1}{18} + \frac{1}{9} \right) ÷ \frac{1}{9} $
答案: 第1题:$\left( \frac{2}{5} + \frac{3}{8} \right) × 40$
解:
$\frac{2}{5}×40 + \frac{3}{8}×40$
$=16 + 15$
$=31$
第2题:$( 1.4 + 42 ) × \frac{3}{7}$
解:
$1.4×\frac{3}{7} + 42×\frac{3}{7}$
$=0.6 + 18$
$=18.6$
第3题:$( 0.125 + 0.375 ) ÷ \frac{1}{8}$
解:
$(0.125 + 0.375)×8$
$=0.125×8 + 0.375×8$
$=1 + 3$
$=4$
第4题:$\left( 7 + \frac{14}{3} \right) ÷ 7$
解:
$7÷7 + \frac{14}{3}÷7$
$=1 + \frac{2}{3}$
$=\frac{5}{3}$
第5题:$\left( \frac{1}{18} + \frac{1}{9} \right) ÷ \frac{1}{9}$
解:
$\left( \frac{1}{18} + \frac{2}{18} \right)×9$
$=\frac{3}{18}×9$
$=\frac{1}{6}×9$
$=\frac{3}{2}$

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