《2025年一本五年级数学苏教版暑假计算加应用题》

1. 直接写出得数。(每题1★)
$\frac {6}{13}-\frac {2}{13}=$$\frac{4}{13}$ $\frac {5}{12}-\frac {1}{4}=$$\frac{1}{6}$ $\frac {5}{9}-\frac {1}{3}=$$\frac{2}{9}$ $1-\frac {3}{10}=$$\frac{7}{10}$
$\frac {5}{6}+\frac {1}{3}=$$\frac{7}{6}$ $\frac {2}{7}+2=$$2\frac{2}{7}$ $\frac {1}{4}+\frac {1}{2}=$$\frac{3}{4}$ $1-\frac {9}{14}=$$\frac{5}{14}$
$\frac {5}{6}-\frac {2}{3}=$$\frac{1}{6}$ $0.25-\frac {1}{4}=$0 $\frac {1}{3}+\frac {1}{8}=$$\frac{11}{24}$ $7-\frac {5}{3}=$$5\frac{1}{3}$
$\frac {7}{8}-\frac {1}{8}+\frac {2}{8}=$1 $\frac {3}{5}-\frac {1}{5}+\frac {1}{2}=$$\frac{9}{10}$ $1-\frac {2}{5}-\frac {3}{5}=$0

答案： 1.$\frac{4}{13}$ $\frac{1}{6}$ $\frac{2}{9}$ $\frac{7}{10}$
$\frac{7}{6}$ $2\frac{2}{7}$ $\frac{3}{4}$ $\frac{5}{14}$
$\frac{1}{6}$ 0 $\frac{11}{24}$ $5\frac{1}{3}$
1 $\frac{9}{10}$ 0

2. 计算下面各题,能简算的要简算。(每题3★)
$\frac {2}{7}+\frac {2}{3}+\frac {5}{7}$ $1-(\frac {3}{10}-\frac {1}{6})$ $\frac {4}{15}+\frac {7}{10}+\frac {4}{15}+\frac {3}{10}$
$\frac {10}{11}+(\frac {1}{11}+\frac {2}{5})$ $\frac {17}{16}-(\frac {1}{4}+\frac {3}{8})$ $\frac {13}{24}+\frac {2}{3}-\frac {5}{6}$
$13-\frac {5}{13}-\frac {8}{13}$ $\frac {14}{9}-\frac {5}{11}+\frac {4}{9}-\frac {6}{11}$ $0.75+\frac {10}{17}+\frac {1}{4}+\frac {7}{17}$

答案： 2.$1\frac{2}{3}$ $\frac{13}{15}$ $1\frac{8}{15}$
$1\frac{2}{5}$ $\frac{7}{16}$ $\frac{3}{8}$
12 1 2

3. 根据运算律,在$◯$里填上合适的运算符号,在$□$里填上合适的分数。(每空1★)
(1)$\frac {4}{7}$+$\frac {5}{12}= \frac {5}{12}+\frac {4}{7}$ (2)$\frac {16}{17}+\frac {4}{5}+\frac {1}{5}= \frac {16}{17}+(\frac {4}{5}$+$\frac {1}{5})$
(3)$\frac {17}{14}-\frac {5}{8}-\frac {3}{8}= \frac {17}{14}-$($\frac{5}{8}$+$\frac{3}{8}$) (4)$\frac {13}{5}-(\frac {3}{5}+\frac {7}{9})= \frac {13}{5}$-$\frac {3}{5}$-$\frac {7}{9}$
(5)$(\frac {8}{25}+\frac {4}{9})+(\frac {17}{25}+\frac {5}{9})= (\frac {8}{25}+$$\frac{17}{25}$)+($\frac{4}{9}$+$\frac{5}{9}$)

答案： 3.
(1)+
(2)+
(3)$\frac{5}{8}$ $\frac{3}{8}$
(4)- -
(5)$\frac{17}{25}$ $\frac{4}{9}$ $\frac{5}{9}$