2025年口算训练六年级数学上册人教版双色升级版


注:目前有些书本章节名称可能整理的还不是很完善,但都是按照顺序排列的,请同学们按照顺序仔细查找。练习册 2025年口算训练六年级数学上册人教版双色升级版 答案主要是用来给同学们做完题方便对答案用的,请勿直接抄袭。



《2025年口算训练六年级数学上册人教版双色升级版》

$\frac{1}{6}× 8= $
$\frac{9}{20}× 3= $
$\frac{3}{10}× 5= $
$\frac{2}{3}× 9= $
$\frac{5}{14}× 7= $
$\frac{4}{21}× 9= $
$\frac{7}{15}× 3= $
$\frac{9}{10}× 2= $
$\frac{4}{7}× 49= $
$\frac{3}{10}× 50= $
$\frac{4}{7}× 7= $
$\frac{5}{9}× 18= $
$\frac{7}{18}× 6= $
答案: 解析:
这些题目都是分数与整数的乘法运算。
可以直接将分数与整数相乘,然后化简得到结果。
答案:
$\frac{1}{6} × 8 = \frac{8}{6} = \frac{4}{3}$
$\frac{9}{20} × 3 = \frac{27}{20}$
$\frac{3}{10} × 5 = \frac{15}{10} = \frac{3}{2}$
$\frac{2}{3} × 9 = \frac{18}{3} = 6$
$\frac{5}{14} × 7 = \frac{35}{14} = \frac{5}{2}$
$\frac{4}{21} × 9 = \frac{36}{21} = \frac{12}{7}$
$\frac{7}{15} × 3 = \frac{21}{15} = \frac{7}{5}$
$\frac{9}{10} × 2 = \frac{18}{10} = \frac{9}{5}$
$\frac{4}{7} × 49 = \frac{196}{7} = 28$
$\frac{3}{10} × 50 = \frac{150}{10} = 15$
$\frac{4}{7} × 7 = \frac{28}{7} = 4$
$\frac{5}{9} × 18 = \frac{90}{9} = 10$
$\frac{7}{18} × 6 = \frac{42}{18} = \frac{7}{3}$
$\frac{1}{3}× \frac{1}{4}= $
$\frac{1}{2}× \frac{1}{5}= $
$\frac{1}{4}× \frac{1}{8}= $
$\frac{7}{5}× \frac{3}{4}= $
$\frac{1}{8}× \frac{2}{5}= $
$\frac{2}{3}× \frac{3}{4}= $
$\frac{3}{5}× \frac{1}{6}= $
$\frac{3}{8}× \frac{2}{9}= $
$\frac{5}{6}× \frac{3}{7}= $
$\frac{3}{7}× \frac{1}{12}= $
$\frac{1}{4}× \frac{1}{6}= $
$\frac{4}{7}× \frac{5}{8}= $
$\frac{2}{3}× \frac{5}{6}= $
答案: 解析:
这些题目都是分数乘法的基础练习。分数相乘时,直接将分子相乘得到新的分子,分母相乘得到新的分母。最后,如果结果可以约分,则进行约分。
答案:
$\frac{1}{3} × \frac{1}{4} = \frac{1}{12}$
$\frac{1}{2} × \frac{1}{5} = \frac{1}{10}$
$\frac{1}{4} × \frac{1}{8} = \frac{1}{32}$
$\frac{7}{5} × \frac{3}{4} = \frac{21}{20}$
$\frac{1}{8} × \frac{2}{5} = \frac{1}{20}$
$\frac{2}{3} × \frac{3}{4} = \frac{1}{2}$
$\frac{3}{5} × \frac{1}{6} = \frac{1}{10}$
$\frac{3}{8} × \frac{2}{9} = \frac{1}{12}$
$\frac{5}{6} × \frac{3}{7} = \frac{5}{14}$
$\frac{3}{7} × \frac{1}{12} = \frac{1}{28}$
$\frac{1}{4} × \frac{1}{6} = \frac{1}{24}$
$\frac{4}{7} × \frac{5}{8} = \frac{5}{14}$
$\frac{2}{3} × \frac{5}{6} = \frac{5}{9}$
$\frac{3}{7}× \frac{4}{5}=$
$\frac{12}{35}$

$\frac{7}{9}× \frac{3}{7}=$
$\frac{1}{3}$

$\frac{5}{22}× \frac{2}{3}=$
$\frac{5}{33}$

$\frac{1}{4}× \frac{3}{5}=$
$\frac{3}{20}$

$\frac{9}{20}× \frac{4}{5}=$
$\frac{9}{25}$

$\frac{5}{6}× \frac{3}{5}=$
$\frac{1}{2}$

$\frac{4}{9}× \frac{3}{16}=$
$\frac{1}{12}$

$\frac{5}{11}× \frac{2}{3}=$
$\frac{10}{33}$

$\frac{5}{16}× \frac{4}{15}=$
$\frac{1}{12}$

$\frac{6}{7}× \frac{5}{24}=$
$\frac{5}{28}$

$\frac{5}{7}× \frac{3}{20}=$
$\frac{3}{28}$

$\frac{7}{8}× \frac{3}{14}=$
$\frac{3}{16}$

$\frac{5}{18}× \frac{2}{25}=$
$\frac{1}{45}$
答案: 解析:
这些题目都是分数乘法的基础练习。分数相乘时,直接将分子相乘得到新的分子,分母相乘得到新的分母。最后,如果结果可以约分,则进行约分。
答案:
$\frac{3}{7} × \frac{4}{5} = \frac{12}{35}$
$\frac{7}{9} × \frac{3}{7} = \frac{1}{3}$
$\frac{5}{22} × \frac{2}{3} = \frac{5}{33}$
$\frac{1}{4} × \frac{3}{5} = \frac{3}{20}$
$\frac{9}{20} × \frac{4}{5} = \frac{9}{25}$
$\frac{5}{6} × \frac{3}{5} = \frac{1}{2}$
$\frac{4}{9} × \frac{3}{16} = \frac{1}{12}$
$\frac{5}{11} × \frac{2}{3} = \frac{10}{33}$
$\frac{5}{16} × \frac{4}{15} = \frac{1}{12}$
$\frac{6}{7} × \frac{5}{24} = \frac{5}{28}$
$\frac{5}{7} × \frac{3}{20} = \frac{3}{28}$
$\frac{7}{8} × \frac{3}{14} = \frac{3}{16}$
$\frac{5}{18} × \frac{2}{25} = \frac{1}{45}$

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