《2025年口算训练六年级数学上册人教版双色升级版》

$\frac {1}{3}÷\frac {1}{3}÷\frac {3}{2}= $
$\frac {1}{4}×\frac {1}{3}÷\frac {3}{4}= $
$\frac {1}{4}÷\frac {1}{3}×\frac {3}{4}= $
$\frac {1}{4}×\frac {1}{3}×\frac {3}{4}= $
$\frac {4}{3}÷\frac {1}{6}÷2= $
$0÷\frac {7}{9}×\frac {6}{7}= $
$\frac {5}{6}÷\frac {1}{3}÷\frac {2}{5}= $
$\frac {2}{3}×\frac {1}{6}÷\frac {4}{9}= $
$\frac {5}{14}×\frac {9}{28}×0= $
$\frac {1}{9}÷\frac {4}{3}×\frac {1}{4}= $
$\frac {7}{12}×\frac {5}{28}÷\frac {5}{6}= $
$\frac {11}{16}×\frac {8}{33}÷\frac {3}{14}= $
$\frac {2}{5}÷\frac {1}{3}×\frac {5}{18}= $

答案： 解析：这些题目都是基础的数学运算题目，主要考察分数的乘除运算。
答案：
$\frac {1}{3}÷\frac {1}{3}÷\frac {3}{2}$
$= 1 ÷ \frac {3}{2}$
$= \frac {2}{3}$
$\frac {1}{4}×\frac {1}{3}÷\frac {3}{4}$
$= \frac {1}{12} ÷ \frac {3}{4}$
$= \frac {1}{9}$
$\frac {1}{4}÷\frac {1}{3}×\frac {3}{4}$
$= \frac {3}{4} × \frac {3}{4}$
$= \frac {9}{16}$
$\frac {1}{4}×\frac {1}{3}×\frac {3}{4}$
$= \frac {1}{12} × \frac {3}{4}$
$= \frac {1}{16}$
$\frac {4}{3}÷\frac {1}{6}÷2$
$= 8 ÷ 2$
$= 4$
$0÷\frac {7}{9}×\frac {6}{7}$
$= 0 × \frac {6}{7}$
$= 0$
$\frac {5}{6}÷\frac {1}{3}÷\frac {2}{5}$
$= \frac {5}{2} ÷ \frac {2}{5}$
$= \frac {25}{4}$
$\frac {2}{3}×\frac {1}{6}÷\frac {4}{9}$
$= \frac {1}{9} ÷ \frac {4}{9}$
$= \frac {1}{4}$
$\frac {5}{14}×\frac {9}{28}×0$
$= 0$
$\frac {1}{9}÷\frac {4}{3}×\frac {1}{4}$
$= \frac {1}{12} × \frac {1}{4}$
$= \frac {1}{48}$
$\frac {7}{12}×\frac {5}{28}÷\frac {5}{6}$
$= \frac {5}{48} ÷ \frac {5}{6}$
$= \frac {1}{8}$
$\frac {11}{16}×\frac {8}{33}÷\frac {3}{14}$
$= \frac {1}{6} ÷ \frac {3}{14}$
$= \frac {7}{9}$
$\frac {2}{5}÷\frac {1}{3}×\frac {5}{18}$
$= \frac {6}{5} × \frac {5}{18}$
$= \frac {1}{3}$

$\frac {1}{2}÷\frac {9}{10}×0= $
$\frac {2}{3}×1÷\frac {8}{9}= $
$\frac {3}{4}×\frac {16}{23}÷\frac {16}{23}= $
$\frac {4}{7}÷\frac {16}{21}×\frac {1}{3}= $
$\frac {1}{3}÷\frac {1}{7}×\frac {1}{3}= $
$\frac {1}{5}+\frac {3}{7}+\frac {4}{7}= $
$\frac {3}{8}+25+\frac {5}{8}= $
$7÷\frac {1}{3}×\frac {1}{6}= $
$\frac {1}{4}×\frac {4}{5}÷\frac {8}{9}= $
$\frac {5}{8}-(\frac {5}{8}-\frac {1}{5})= $
$\frac {7}{9}×0÷\frac {5}{12}= $
$\frac {3}{14}÷\frac {3}{7}×\frac {24}{25}= $
$\frac {1}{2}÷\frac {3}{4}÷\frac {4}{9}= $

答案： 解析：这些题目主要考查分数的四则运算。
答案：
1. $\frac {1}{2}÷\frac {9}{10}×0$
$= \frac{1}{2} × \frac{10}{9} × 0$
$= 0$
2. $\frac {2}{3}×1÷\frac {8}{9}$
$= \frac{2}{3} × \frac{9}{8}$
$= \frac{3}{4}$
3. $\frac {3}{4}×\frac {16}{23}÷\frac {16}{23}$
$= \frac{3}{4} × \frac{16}{23} × \frac{23}{16}$
$= \frac{3}{4}$
4. $\frac {4}{7}÷\frac {16}{21}×\frac {1}{3}$
$= \frac{4}{7} × \frac{21}{16} × \frac{1}{3}$
$= \frac{1}{4}$
5. $\frac {1}{3}÷\frac {1}{7}×\frac {1}{3}$
$= \frac{1}{3} × 7 × \frac{1}{3}$
$= \frac{7}{9}$
6. $\frac {1}{5}+\frac {3}{7}+\frac {4}{7}$
$= \frac{1}{5} + 1$
$= \frac{6}{5}$
7. $\frac {3}{8}+25+\frac {5}{8}$
$= \frac{3}{8} + \frac{5}{8} + 25$
$= 1 + 25$
$= 26$
8. $7÷\frac {1}{3}×\frac {1}{6}$
$= 7 × 3 × \frac{1}{6}$
$= \frac{7}{2}$
9. $\frac {1}{4}×\frac {4}{5}÷\frac {8}{9}$
$= \frac{1}{5} × \frac{9}{8}$
$= \frac{9}{40}$
10. $\frac {5}{8}-(\frac {5}{8}-\frac {1}{5})$
$= \frac{5}{8} - \frac{5}{8} + \frac{1}{5}$
$= \frac{1}{5}$
11. $\frac {7}{9}×0÷\frac {5}{12}$
$= 0$
12. $\frac {3}{14}÷\frac {3}{7}×\frac {24}{25}$
$= \frac{3}{14} × \frac{7}{3} × \frac{24}{25}$
$= \frac{12}{25}$
13. $\frac {1}{2}÷\frac {3}{4}÷\frac {4}{9}$
$= \frac{1}{2} × \frac{4}{3} × \frac{9}{4}$
$= \frac{3}{2}$

解方程。
$x+\frac {4}{5}= \frac {5}{6}$
$x=$$\frac{1}{30}$
$x-15= \frac {3}{5}$
$x=$$15\frac{3}{5}$
$x+\frac {1}{2}x= \frac {4}{5}$
$x=$$\frac{8}{15}$
$24x= \frac {3}{4}$
$x=$$\frac{1}{32}$
$x-\frac {1}{4}x= \frac {15}{8}$
$x=$$\frac{5}{2}$
$x+\frac {2}{9}= \frac {1}{3}$
$x=$$\frac{1}{9}$
$3x+\frac {1}{5}x= 16$
$x=$5
$x-\frac {1}{6}x= \frac {25}{48}$
$x=$$\frac{5}{8}$

答案： 1.
解析：考查解一元一次方程，根据等式的性质，方程两边同时减去$\frac{4}{5}$求解。
答案：
$x + \frac{4}{5} = \frac{5}{6}$
$x=\frac{5}{6}-\frac{4}{5}$
$x=\frac{25}{30}-\frac{24}{30}$
$x = \frac{1}{30}$
2.
解析：考查解一元一次方程，根据等式的性质，方程两边同时加上$15$求解。
答案：
$x - 15 = \frac{3}{5}$
$x=\frac{3}{5}+15$
$x=\frac{3}{5}+\frac{75}{5}$
$x = 15\frac{3}{5}$
3.
解析：考查解一元一次方程，先合并同类项，再根据等式的性质求解。
答案：
$x+\frac{1}{2}x=\frac{4}{5}$
$\frac{3}{2}x=\frac{4}{5}$
$x=\frac{4}{5}×\frac{2}{3}$
$x = \frac{8}{15}$
4.
解析：考查解一元一次方程，根据等式的性质，方程两边同时除以$24$求解。
答案：
$24x=\frac{3}{4}$
$x=\frac{3}{4}÷24$
$x=\frac{3}{4}×\frac{1}{24}$
$x = \frac{1}{32}$
5.
解析：考查解一元一次方程，先合并同类项，再根据等式的性质求解。
答案：
$x-\frac{1}{4}x=\frac{15}{8}$
$\frac{3}{4}x=\frac{15}{8}$
$x=\frac{15}{8}×\frac{4}{3}$
$x = \frac{5}{2}$
6.
解析：考查解一元一次方程，根据等式的性质，方程两边同时减去$\frac{2}{9}$求解。
答案：
$x+\frac{2}{9}=\frac{1}{3}$
$x=\frac{1}{3}-\frac{2}{9}$
$x=\frac{3}{9}-\frac{2}{9}$
$x = \frac{1}{9}$
7.
解析：考查解一元一次方程，先合并同类项，再根据等式的性质求解。
答案：
$3x+\frac{1}{5}x=16$
$\frac{16}{5}x=16$
$x=16×\frac{5}{16}$
$x = 5$
8.
解析：考查解一元一次方程，先合并同类项，再根据等式的性质求解。
答案：
$x-\frac{1}{6}x=\frac{25}{48}$
$\frac{5}{6}x=\frac{25}{48}$
$x=\frac{25}{48}×\frac{6}{5}$
$x = \frac{5}{8}$