《2025年口算训练六年级数学上册人教版双色升级版》

$\frac {9}{10}×\frac {2}{3}= $
$\frac {5}{6}×\frac {3}{7}= $
$\frac {5}{6}×\frac {1}{5}= $
$\frac {3}{4}×\frac {8}{13}= $
$\frac {2}{9}×\frac {3}{7}= $
$\frac {2}{7}×\frac {7}{17}= $
$6×\frac {1}{7}= $
$\frac {4}{5}×\frac {3}{4}= $
$\frac {11}{26}×\frac {13}{22}= $
$\frac {3}{4}×\frac {1}{2}= $
$\frac {6}{7}×\frac {14}{15}= $
$\frac {5}{7}×\frac {14}{25}= $
$\frac {5}{8}×\frac {4}{15}= $

答案： 解析：
这些题目都是分数乘法的基础练习。分数乘法的一般步骤是：直接将两个分数的分子相乘得到新的分子，两个分数的分母相乘得到新的分母。最后，如果要得到最简形式，需要进行约分。
答案：
$\frac{9}{10} × \frac{2}{3} = \frac{9 × 2}{10 × 3} = \frac{3}{5}$
$\frac{5}{6} × \frac{3}{7} = \frac{5 × 3}{6 × 7} = \frac{5}{14}$
$\frac{5}{6} × \frac{1}{5} = \frac{5 × 1}{6 × 5} = \frac{1}{6}$
$\frac{3}{4} × \frac{8}{13} = \frac{3 × 8}{4 × 13} = \frac{6}{13}$
$\frac{2}{9} × \frac{3}{7} = \frac{2 × 3}{9 × 7} = \frac{2}{21}$
$\frac{2}{7} × \frac{7}{17} = \frac{2 × 7}{7 × 17} = \frac{2}{17}$
$6 × \frac{1}{7} = \frac{6}{7}$
$\frac{4}{5} × \frac{3}{4} = \frac{4 × 3}{5 × 4} = \frac{3}{5}$
$\frac{11}{26} × \frac{13}{22} = \frac{11 × 13}{26 × 22} = \frac{1}{4}$
$\frac{3}{4} × \frac{1}{2} = \frac{3 × 1}{4 × 2} = \frac{3}{8}$
$\frac{6}{7} × \frac{14}{15} = \frac{6 × 14}{7 × 15} = \frac{4}{5}$
$\frac{5}{7} × \frac{14}{25} = \frac{5 × 14}{7 × 25} = \frac{2}{5}$
$\frac{5}{8} × \frac{4}{15} = \frac{5 × 4}{8 × 15} = \frac{1}{6}$

$\frac {3}{8}×\frac {4}{11}= $
$\frac {3}{4}×5= $
$\frac {3}{14}×21= $
$\frac {4}{9}×27= $
$\frac {9}{16}×24= $
$\frac {63}{11}×\frac {2}{9}= $
$\frac {2}{3}×\frac {1}{4}×\frac {1}{6}= $
$\frac {8}{63}×\frac {15}{32}×\frac {9}{10}= $
$\frac {3}{4}×\frac {1}{3}×\frac {7}{10}= $
$(\frac {1}{3}-\frac {1}{4})×24= $
$\frac {4}{15}×9+\frac {1}{5}= $
$\frac {54}{13}×\frac {5}{6}= $
$\frac {9}{56}×\frac {8}{27}×\frac {14}{15}= $

答案： 解析：
这些题目都是分数乘法的基础练习题，主要考察分数的乘法运算以及分数与整数的乘法运算。
对于分数与分数的乘法，我们直接将两个分数的分子相乘得到新的分子，分母相乘得到新的分母。
对于分数与整数的乘法，我们将分数的分子与整数相乘，分母保持不变，最后进行化简。
如果有括号，先计算括号内的表达式，再进行乘法运算，可以利用乘法分配律简化计算。
答案：
$\frac{3}{8} × \frac{4}{11} = \frac{3 × 4}{8 × 11} = \frac{12}{88} = \frac{3}{22}$
$\frac{3}{4} × 5 = \frac{3 × 5}{4} = \frac{15}{4}$
$\frac{3}{14} × 21 = \frac{3 × 21}{14} = \frac{63}{14} = \frac{9}{2}=4.5$
$\frac{4}{9} × 27 = \frac{4 × 27}{9} = \frac{108}{9} = 12$
$\frac{9}{16} × 24 = \frac{9 × 24}{16} = \frac{216}{16} = \frac{27}{2}=13.5$
$\frac{63}{11} × \frac{2}{9} = \frac{63 × 2}{11 × 9} = \frac{126}{99} = \frac{14}{11}$
$\frac{2}{3} × \frac{1}{4} × \frac{1}{6} = \frac{2 × 1 × 1}{3 × 4 × 6} = \frac{2}{72} = \frac{1}{36}$
$\frac{8}{63} × \frac{15}{32} × \frac{9}{10} = \frac{8 × 15 × 9}{63 × 32 × 10} = \frac{1080}{20160} = \frac{3}{56}$
$\frac{3}{4} × \frac{1}{3} × \frac{7}{10} = \frac{3 × 1 × 7}{4 × 3 × 10} = \frac{21}{120} = \frac{7}{40}$
$(\frac{1}{3} - \frac{1}{4}) × 24 = (\frac{4}{12} - \frac{3}{12}) × 24 = \frac{1}{12} × 24 = 2$
$\frac{4}{15} × 9 + \frac{1}{5} = \frac{4 × 9}{15} + \frac{1}{5} = \frac{36}{15} + \frac{3}{15} = \frac{39}{15} = \frac{13}{5}=2.6$
$\frac{54}{13} × \frac{5}{6} = \frac{54 × 5}{13 × 6} = \frac{270}{78} = \frac{45}{13}$
$\frac{9}{56} × \frac{8}{27} × \frac{14}{15} = \frac{9 × 8 × 14}{56 × 27 × 15} = \frac{1008}{22680} = \frac{2}{45}$

$65×(1+\frac {2}{5})=$91
$80×(1+\frac {3}{4})=$140
$100×(1+\frac {3}{5})=$160
$25×(1+\frac {1}{5})=$30
$60×(1+\frac {2}{3})=$100
$30×(1+\frac {3}{10})=$39
$48×(1+\frac {1}{4})=$60
$50×(1+\frac {1}{2})=$75
$75×(1+\frac {1}{3})=$100
$75×(1+\frac {3}{5})=$120
$12×(1+\frac {5}{6})=$22
$56×(1+\frac {3}{8})=$77
$72×(1+\frac {5}{12})=$102

答案： 解析：
这些题目都是基础的数学运算题，主要考察的是乘法分配律的应用。
对于形如 $a×(1+\frac{b}{c})$ 的表达式，可以将其转化为 $a+\frac{a× b}{c}$ 来简化计算。
答案：
$65×(1+\frac {2}{5})$
$= 65 + \frac{65 × 2}{5}$
$= 65 + 26$
$= 91$
$80×(1+\frac {3}{4})$
$= 80 + \frac{80 × 3}{4}$
$= 80 + 60$
$= 140$
$100×(1+\frac {3}{5})$
$= 100 + \frac{100 × 3}{5}$
$= 100 + 60$
$= 160$
$25×(1+\frac {1}{5})$
$= 25 + \frac{25 × 1}{5}$
$= 25 + 5$
$= 30$
$60×(1+\frac {2}{3})$
$= 60 + \frac{60 × 2}{3}$
$= 60 + 40$
$= 100$
$30×(1+\frac {3}{10})$
$= 30 + \frac{30 × 3}{10}$
$= 30 + 9$
$= 39$
$48×(1+\frac {1}{4})$
$= 48 + \frac{48 × 1}{4}$
$= 48 + 12$
$= 60$
$50×(1+\frac {1}{2})$
$= 50 + \frac{50 × 1}{2}$
$= 50 + 25$
$= 75$
$75×(1+\frac {1}{3})$
$= 75 + \frac{75 × 1}{3}$
$= 75 + 25$
$= 100$
$75×(1+\frac {3}{5})$
$= 75 + \frac{75 × 3}{5}$
$= 75 + 45$
$= 120$
$12×(1+\frac {5}{6})$
$= 12 + \frac{12 × 5}{6}$
$= 12 + 10$
$= 22$
$56×(1+\frac {3}{8})$
$= 56 + \frac{56 × 3}{8}$
$= 56 + 21$
$= 77$
$72×(1+\frac {5}{12})$
$= 72 + \frac{72 × 5}{12}$
$= 72 + 30$
$= 102$