《2025年口算训练六年级数学上册人教版双色升级版》

$\frac { 1 } { 2 } × \frac { 3 } { 8 } = \frac { 3 } { 11 } × \frac { 22 } { 9 } = \frac { 4 } { 7 } × \frac { 1 } { 8 } = \frac { 3 } { 13 } × \frac { 26 } { 37 } = \frac { 18 } { 35 } × \frac { 7 } { 9 } = \frac { 23 } { 24 } × \frac { 8 } { 69 } = \frac { 5 } { 6 } × \frac { 2 } { 7 } = \frac { 5 } { 9 } × 11 = \frac { 1 } { 2 } × \frac { 1 } { 4 } - \frac { 1 } { 8 } = \frac { 1 } { 2 } × \frac { 1 } { 4 } + \frac { 1 } { 8 } = \frac { 1 } { 2 } × \frac { 1 } { 4 } × \frac { 1 } { 8 } = \frac { 17 } { 24 } × \frac { 8 } { 51 } = \frac { 7 } { 11 } × \frac { 22 } { 49 } = $

答案： 解析：
题目考查的是分数的乘法和减法、加法的混合运算。
对于分数的乘法，直接将分子相乘，分母相乘即可。
对于分数的加减法，需要先找到通分母，然后进行分子的加减。
答案：
$\frac{1}{2} × \frac{3}{8} = \frac{3}{16}$
$\frac{3}{11} × \frac{22}{9} = \frac{2}{3}$
$\frac{4}{7} × \frac{1}{8} = \frac{1}{14}$
$\frac{3}{13} × \frac{26}{37} = \frac{6}{37}$
$\frac{18}{35} × \frac{7}{9} = \frac{2}{5}$
$\frac{23}{24} × \frac{8}{69} = \frac{1}{9}$
$\frac{5}{6} × \frac{2}{7} = \frac{5}{21}$
$\frac{5}{9} × 11 = \frac{55}{9}$
$\frac{1}{2} × \frac{1}{4} - \frac{1}{8} = \frac{1}{8} - \frac{1}{8} = 0$
$\frac{1}{2} × \frac{1}{4} + \frac{1}{8} = \frac{1}{8} + \frac{1}{8} = \frac{1}{4}$
$\frac{1}{2} × \frac{1}{4} × \frac{1}{8} = \frac{1}{64}$
$\frac{17}{24} × \frac{8}{51} = \frac{1}{9}$
$\frac{7}{11} × \frac{22}{49} = \frac{2}{7}$

$\frac { 5 } { 8 } × 6.4 = 90 × \frac { 1 } { 15 } = \frac { 3 } { 15 } × \frac { 5 } { 7 } = 16 × \frac { 5 } { 12 } = \frac { 7 } { 11 } × \frac { 33 } { 14 } = \frac { 8 } { 9 } × \frac { 3 } { 16 } = 4.5 × \frac { 2 } { 3 } = \frac { 4 } { 5 } × 30 = \frac { 9 } { 10 } × \frac { 25 } { 6 } = \frac { 7 } { 22 } × 11 = 0.6 × \frac { 2 } { 15 } = 0.8 × \frac { 3 } { 22 } = \frac { 5 } { 7 } × 4.9 = $

答案： $\frac{5}{8}×6.4 = 4$
$90×\frac{1}{15} = 6$
$\frac{3}{15}×\frac{5}{7} = \frac{1}{7}$
$16×\frac{5}{12} = \frac{20}{3}$
$\frac{7}{11}×\frac{33}{14} = \frac{3}{2}$
$\frac{8}{9}×\frac{3}{16} = \frac{1}{6}$
$4.5×\frac{2}{3} = 3$
$\frac{4}{5}×30 = 24$
$\frac{9}{10}×\frac{25}{6} = \frac{15}{4}$
$\frac{7}{22}×11 = \frac{7}{2}$
$0.6×\frac{2}{15} = 0.08$
$0.8×\frac{3}{22} = \frac{6}{55}$
$\frac{5}{7}×4.9 = 3.5$

$\frac { 9 } { 10 } × 1.5 = $$\frac{27}{20}$（或1.35）$\frac { 1 } { 42 } × \frac { 3 } { 4 } = $$\frac{1}{56}$$\frac { 2 } { 35 } × \frac { 21 } { 8 } = $$\frac{3}{20}$$\frac { 3 } { 15 } × \frac { 1 } { 24 } = $$\frac{1}{120}$$\frac { 2 } { 15 } × 7.5 = $1$2.4 × \frac { 3 } { 4 } = $1.8$\frac { 7 } { 45 } × \frac { 20 } { 21 } = $$\frac{4}{27}$$\frac { 5 } { 8 } × 1.2 = $$\frac{3}{4}$（或0.75）$0.8 × \frac { 7 } { 24 } = $$\frac{7}{30}$$\frac { 3 } { 7 } × 3.5 = $$\frac{3}{2}$（或1.5）$\frac { 15 } { 19 } × \frac { 19 } { 24 } = $$\frac{5}{8}$$\frac { 5 } { 16 } × 1.8 = $$\frac{9}{16}$（或0.5625）$\frac { 11 } { 27 } × \frac { 9 } { 11 } = $$\frac{1}{3}$

答案： $\frac{9}{10}×1.5 = \frac{9}{10}×\frac{3}{2} = \frac{27}{20} = 1.35$
$\frac{1}{42}×\frac{3}{4} = \frac{1×3}{42×4} = \frac{3}{168} = \frac{1}{56}$
$\frac{2}{35}×\frac{21}{8} = \frac{2×21}{35×8} = \frac{42}{280} = \frac{3}{20}$
$\frac{3}{15}×\frac{1}{24} = \frac{1}{5}×\frac{1}{24} = \frac{1}{120}$
$\frac{2}{15}×7.5 = \frac{2}{15}×\frac{15}{2} = 1$
$2.4×\frac{3}{4} = \frac{12}{5}×\frac{3}{4} = \frac{36}{20} = 1.8$
$\frac{7}{45}×\frac{20}{21} = \frac{7×20}{45×21} = \frac{140}{945} = \frac{4}{27}$
$\frac{5}{8}×1.2 = \frac{5}{8}×\frac{6}{5} = \frac{30}{40} = \frac{3}{4} = 0.75$
$0.8×\frac{7}{24} = \frac{4}{5}×\frac{7}{24} = \frac{28}{120} = \frac{7}{30}$
$\frac{3}{7}×3.5 = \frac{3}{7}×\frac{7}{2} = \frac{3}{2} = 1.5$
$\frac{15}{19}×\frac{19}{24} = \frac{15×19}{19×24} = \frac{15}{24} = \frac{5}{8}$
$\frac{5}{16}×1.8 = \frac{5}{16}×\frac{9}{5} = \frac{45}{80} = \frac{9}{16} = 0.5625$
$\frac{11}{27}×\frac{9}{11} = \frac{11×9}{27×11} = \frac{9}{27} = \frac{1}{3}$