2025年口算训练六年级数学上册人教版双色升级版


注:目前有些书本章节名称可能整理的还不是很完善,但都是按照顺序排列的,请同学们按照顺序仔细查找。练习册 2025年口算训练六年级数学上册人教版双色升级版 答案主要是用来给同学们做完题方便对答案用的,请勿直接抄袭。



《2025年口算训练六年级数学上册人教版双色升级版》

$4× \left(\frac{1}{8}+\frac{1}{4}\right)= $
$\left(6-\frac{1}{2}\right)× \frac{2}{3}= $
$1÷ \left(\frac{4}{7}+\frac{3}{7}\right)= $
$3-\left(\frac{7}{10}+\frac{1}{5}\right)= $
$\frac{5}{8}× \left(\frac{3}{4}-\frac{1}{2}\right)= $
$\frac{5}{8}÷ \left(\frac{3}{4}+\frac{1}{2}\right)= $
$2-\left(\frac{1}{2}+\frac{3}{4}\right)= $
$12× \left(\frac{1}{4}+\frac{1}{6}\right)= $
$\frac{4}{9}÷ \left(\frac{5}{6}-\frac{1}{2}\right)= $
$\frac{1}{2}÷ \left(\frac{1}{2}+\frac{1}{4}\right)= $
$4÷ \left(1-\frac{1}{2}\right)= $
$\frac{3}{4}÷ \left(\frac{5}{6}-\frac{1}{3}\right)= $
$72× \left(\frac{5}{12}+\frac{3}{18}\right)= $
答案: 解析:这些题目主要考查分数的四则运算,包括加减乘除以及与整数的混合运算。
答案:
$4 × \left( \frac{1}{8} + \frac{1}{4} \right) $
$=4 × \frac{3}{8}$
$ = \frac{3}{2}$
$\left( 6 - \frac{1}{2} \right) × \frac{2}{3} $
$= \frac{11}{2} × \frac{2}{3} $
$= \frac{11}{3}$
$1 ÷ \left( \frac{4}{7} + \frac{3}{7} \right) = 1 ÷ 1 = 1$
$3 - \left( \frac{7}{10} + \frac{1}{5} \right) $
$= 3 - \frac{9}{10} $
$= \frac{21}{10}$
$\frac{5}{8} × \left( \frac{3}{4} - \frac{1}{2} \right) $
$= \frac{5}{8} × \frac{1}{4} $
$= \frac{5}{32}$
$\frac{5}{8} ÷ \left( \frac{3}{4} + \frac{1}{2} \right) $
$= \frac{5}{8} ÷ \frac{5}{4} $
$= \frac{1}{2}$
$2 - \left( \frac{1}{2} + \frac{3}{4} \right) $
$= 2 - \frac{5}{4} $
$= \frac{3}{4}$
$12 × \left( \frac{1}{4} + \frac{1}{6} \right) $
$= 12 × \frac{5}{12} $
$= 5$
$\frac{4}{9} ÷ \left( \frac{5}{6} - \frac{1}{2} \right) $
$= \frac{4}{9} ÷ \frac{1}{3} $
$= \frac{4}{3}$
$\frac{1}{2} ÷ \left( \frac{1}{2} + \frac{1}{4} \right) $
$= \frac{1}{2} ÷ \frac{3}{4} $
$= \frac{2}{3}$
$4 ÷ \left( 1 - \frac{1}{2} \right) = 4 ÷ \frac{1}{2} = 8$
$\frac{3}{4} ÷ \left( \frac{5}{6} - \frac{1}{3} \right) $
$= \frac{3}{4} ÷ \frac{1}{2} $
$= \frac{3}{2}$
$72 × \left( \frac{5}{12} + \frac{3}{18} \right) $
$= 72 × \frac{7}{12} $
$= 42$
$\frac{1}{2}× \frac{1}{2}× \frac{1}{2}= $
$\frac{5}{6}÷ \frac{2}{7}÷ 35= $
$\frac{2}{3}× 4× \frac{3}{8}= $
$\frac{5}{7}÷ \frac{3}{14}÷ \frac{2}{3}= $
$\frac{1}{3}× \frac{1}{2}× \frac{1}{4}= $
$\frac{1}{6}÷ \frac{4}{9}× \frac{1}{3}= $
$\frac{4}{5}× \frac{2}{3}÷ \frac{4}{5}= $
$\frac{1}{3}× \frac{8}{33}÷ 2= $
$\frac{13}{3}× \frac{2}{13}× \frac{5}{26}= $
$\frac{2}{5}× \frac{5}{6}÷ \frac{1}{3}= $
$5÷ \frac{1}{13}× \frac{7}{13}= $
$\frac{3}{8}÷ \frac{5}{24}÷ \frac{1}{5}= $
$\frac{7}{12}× \frac{5}{42}× \frac{18}{5}= $
答案: $\frac{1}{2}× \frac{1}{2}× \frac{1}{2}=\frac{1×1×1}{2×2×2}=\frac{1}{8}$
$\frac{5}{6}÷ \frac{2}{7}÷ 35=\frac{5}{6}×\frac{7}{2}×\frac{1}{35}=\frac{5×7×1}{6×2×35}=\frac{1}{12}$
$\frac{2}{3}× 4× \frac{3}{8}=\frac{2×4×3}{3×8}=1$
$\frac{5}{7}÷ \frac{3}{14}÷ \frac{2}{3}=\frac{5}{7}×\frac{14}{3}×\frac{3}{2}=5$
$\frac{1}{3}× \frac{1}{2}× \frac{1}{4}=\frac{1×1×1}{3×2×4}=\frac{1}{24}$
$\frac{1}{6}÷ \frac{4}{9}× \frac{1}{3}=\frac{1}{6}×\frac{9}{4}×\frac{1}{3}=\frac{1×9×1}{6×4×3}=\frac{1}{8}$
$\frac{4}{5}× \frac{2}{3}÷ \frac{4}{5}=\frac{4}{5}×\frac{2}{3}×\frac{5}{4}=\frac{2}{3}$
$\frac{1}{3}× \frac{8}{33}÷ 2=\frac{1}{3}×\frac{8}{33}×\frac{1}{2}=\frac{4}{99}$
$\frac{13}{3}× \frac{2}{13}× \frac{5}{26}=\frac{13×2×5}{3×13×26}=\frac{5}{39}$
$\frac{2}{5}× \frac{5}{6}÷ \frac{1}{3}=\frac{2×5×3}{5×6}=1$
$5÷ \frac{1}{13}× \frac{7}{13}=5×13×\frac{7}{13}=35$
$\frac{3}{8}÷ \frac{5}{24}÷ \frac{1}{5}=\frac{3}{8}×\frac{24}{5}×5=9$
$\frac{7}{12}× \frac{5}{42}× \frac{18}{5}=\frac{7×5×18}{12×42×5}=\frac{3}{12}=\frac{1}{4}$
解方程。
$\frac{4}{7}x= \frac{5}{14}$
$x=$
$\frac{5}{8}$

$\frac{1}{2}x-\frac{1}{3}x= \frac{1}{4}$
$x=$
$\frac{3}{2}$

$x+\frac{2}{3}= \frac{4}{5}$
$x=$
$\frac{2}{15}$

$x-5= \frac{2}{5}$
$x=$
$\frac{27}{5}$

$x+\frac{1}{3}x= \frac{3}{4}$
$x=$
$\frac{9}{16}$

$\frac{1}{4}x= \frac{3}{8}$
$x=$
$\frac{3}{2}$

$\frac{1}{4}x+x= \frac{15}{16}$
$x=$
$\frac{3}{4}$

$\frac{3}{5}x-\frac{1}{2}x= \frac{5}{8}$
$x=$
$\frac{25}{4}$
答案: 解:
对于方程 $\frac{4}{7}x= \frac{5}{14}$:
两边同时乘以 $\frac{7}{4}$,得到:
$x= \frac{5}{14} × \frac{7}{4}$
$x= \frac{5}{8}$
对于方程 $\frac{1}{2}x-\frac{1}{3}x= \frac{1}{4}$:
合并同类项,得到:
$\frac{1}{6}x= \frac{1}{4}$
两边同时乘以 6,得到:
$x= \frac{3}{2}$
对于方程 $x+\frac{2}{3}= \frac{4}{5}$:
两边同时减去 $\frac{2}{3}$,得到:
$x= \frac{4}{5} - \frac{2}{3}$
$x= \frac{2}{15}$
对于方程 $x-5= \frac{2}{5}$:
两边同时加上 5,得到:
$x= 5\frac{2}{5}$
$x= \frac{27}{5}$
对于方程 $x+\frac{1}{3}x= \frac{3}{4}$:
合并同类项,得到:
$\frac{4}{3}x= \frac{3}{4}$
两边同时乘以 $\frac{3}{4}$,得到:
$x= \frac{9}{16}$
对于方程 $\frac{1}{4}x= \frac{3}{8}$:
两边同时乘以 4,得到:
$x= \frac{3}{2}$
对于方程 $\frac{1}{4}x+x= \frac{15}{16}$:
合并同类项,得到:
$\frac{5}{4}x= \frac{15}{16}$
两边同时乘以 $\frac{4}{5}$,得到:
$x= \frac{3}{4}$
对于方程 $\frac{3}{5}x-\frac{1}{2}x= \frac{5}{8}$:
合并同类项,得到:
$\frac{1}{10}x= \frac{5}{8}$
两边同时乘以 10,得到:
$x= \frac{25}{4}$

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