《2025年口算训练六年级数学上册人教版双色升级版》

$5×\frac {8}{15}= $
$\frac {2}{11}×3+\frac {2}{11}= $
$(\frac {1}{4}+\frac {1}{4})×5= $
$\frac {8}{15}×\frac {1}{4}= $
$\frac {3}{10}×\frac {3}{4}= $
$\frac {2}{3}×\frac {2}{9}= $
$\frac {7}{11}×\frac {13}{21}= $
$\frac {8}{27}×\frac {9}{4}= $
$\frac {1}{24}×\frac {9}{4}= $
$\frac {6}{7}×\frac {14}{15}= $
$\frac {3}{8}×\frac {4}{11}= $
$\frac {4}{9}×\frac {18}{19}= $
$\frac {5}{6}×\frac {12}{25}= $

答案： 解析：这些题目都是分数乘法的计算题，直接使用分数乘法法则进行计算。
答案：
$5 × \frac{8}{15} = \frac{8}{3}$
$\frac{2}{11} × 3 + \frac{2}{11} = \frac{6}{11} + \frac{2}{11} = \frac{8}{11}$
$(\frac{1}{4} + \frac{1}{4}) × 5 = \frac{1}{2} × 5 = \frac{5}{2}$
$\frac{8}{15} × \frac{1}{4} = \frac{2}{15}$
$\frac{3}{10} × \frac{3}{4} = \frac{9}{40}$
$\frac{2}{3} × \frac{2}{9} = \frac{4}{27}$
$\frac{7}{11} × \frac{13}{21} = \frac{13}{33}$
$\frac{8}{27} × \frac{9}{4} = \frac{2}{3}$
$\frac{1}{24} × \frac{9}{4} = \frac{3}{32}$
$\frac{6}{7} × \frac{14}{15} = \frac{4}{5}$
$\frac{3}{8} × \frac{4}{11} = \frac{3}{22}$
$\frac{4}{9} × \frac{18}{19} = \frac{8}{19}$
$\frac{5}{6} × \frac{12}{25} = \frac{2}{5}$

$\frac {3}{4}×\frac {3}{8}= $
$\frac {2}{3}×\frac {3}{4}= $
$\frac {7}{12}×\frac {3}{14}= $
$\frac {4}{9}×\frac {6}{7}= $
$\frac {9}{10}×\frac {9}{8}= $
$\frac {3}{8}×\frac {3}{7}= $
$\frac {5}{8}×40= $
$80×\frac {3}{5}= $
$60×\frac {4}{5}= $
$90×\frac {4}{5}= $
$75×\frac {2}{3}= $
$68×\frac {3}{4}= $
$\frac {2}{15}×\frac {6}{7}= $

答案： 解析：
这些题目都是分数乘法的基础练习。分数乘法的一般步骤是：直接将两个分数的分子相乘得到新的分子，将两个分数的分母相乘得到新的分母，然后进行约分（如果可能）。如果其中一个乘数是整数，可以将整数看作分母为1的分数进行计算。
答案：
$\frac{3}{4} × \frac{3}{8} = \frac{9}{32}$
$\frac{2}{3} × \frac{3}{4} = \frac{1}{2}$
$\frac{7}{12} × \frac{3}{14} = \frac{1}{8}$
$\frac{4}{9} × \frac{6}{7} = \frac{8}{21}$
$\frac{9}{10} × \frac{9}{8} = \frac{81}{80}$
$\frac{3}{8} × \frac{3}{7} = \frac{9}{56}$
$\frac{5}{8} × 40 = 25$
$80 × \frac{3}{5} = 48$
$60 × \frac{4}{5} = 48$
$90 × \frac{4}{5} = 72$
$75 × \frac{2}{3} = 50$
$68 × \frac{3}{4} = 51$
$\frac{2}{15} × \frac{6}{7} = \frac{4}{35}$

$\frac {1}{12}×\frac {3}{4}=$$\frac{1}{16}$
$\frac {3}{8}×\frac {6}{5}=$$\frac{9}{20}$
$\frac {7}{10}×\frac {3}{14}=$$\frac{3}{20}$
$\frac {2}{5}×\frac {1}{7}=$$\frac{2}{35}$
$\frac {1}{8}×\frac {12}{11}=$$\frac{3}{22}$
$\frac {7}{9}×\frac {3}{14}=$$\frac{1}{6}$
$\frac {3}{2}×\frac {1}{12}=$$\frac{1}{8}$
$\frac {9}{16}×\frac {4}{27}=$$\frac{1}{12}$
$\frac {5}{14}×\frac {7}{25}=$$\frac{1}{10}$
$\frac {9}{14}×\frac {7}{6}=$$\frac{3}{4}$
$\frac {8}{15}×\frac {5}{12}=$$\frac{2}{9}$
$\frac {7}{18}×\frac {9}{14}=$$\frac{1}{4}$
$\frac {11}{21}×\frac {3}{22}=$$\frac{1}{14}$

答案： 解析：这些题目都是分数乘法的基础练习。分数相乘时，直接将分子相乘的积做分子，分母相乘的积做分母。
答案：
$\frac{1}{12} × \frac{3}{4} = \frac{1 × 3}{12 × 4} = \frac{3}{48} = \frac{1}{16}$
$\frac{3}{8} × \frac{6}{5} = \frac{3 × 6}{8 × 5} = \frac{18}{40} = \frac{9}{20}$
$\frac{7}{10} × \frac{3}{14} = \frac{7 × 3}{10 × 14} = \frac{21}{140} = \frac{3}{20}$
$\frac{2}{5} × \frac{1}{7} = \frac{2 × 1}{5 × 7} = \frac{2}{35}$
$\frac{1}{8} × \frac{12}{11} = \frac{1 × 12}{8 × 11} = \frac{12}{88} = \frac{3}{22}$
$\frac{7}{9} × \frac{3}{14} = \frac{7 × 3}{9 × 14} = \frac{21}{126} = \frac{1}{6}$
$\frac{3}{2} × \frac{1}{12} = \frac{3 × 1}{2 × 12} = \frac{3}{24} = \frac{1}{8}$
$\frac{9}{16} × \frac{4}{27} = \frac{9 × 4}{16 × 27} = \frac{36}{432} = \frac{1}{12}$
$\frac{5}{14} × \frac{7}{25} = \frac{5 × 7}{14 × 25} = \frac{35}{350} = \frac{1}{10}$
$\frac{9}{14} × \frac{7}{6} = \frac{9 × 7}{14 × 6} = \frac{63}{84} = \frac{3}{4}$
$\frac{8}{15} × \frac{5}{12} = \frac{8 × 5}{15 × 12} = \frac{40}{180} = \frac{2}{9}$
$\frac{7}{18} × \frac{9}{14} = \frac{7 × 9}{18 × 14} = \frac{63}{252} = \frac{1}{4}$
$\frac{11}{21} × \frac{3}{22} = \frac{11 × 3}{21 × 22} = \frac{33}{462} = \frac{1}{14}$