《2025年口算训练六年级数学上册人教版双色升级版》

$\frac {1}{3}×\frac {3}{4}÷\frac {4}{5}= $
$\frac {1}{5}×\frac {7}{8}×\frac {5}{7}= $
$\frac {3}{4}×\frac {4}{9}×\frac {3}{5}= $
$\frac {2}{5}÷\frac {3}{5}÷\frac {4}{7}= $
$\frac {1}{6}×\frac {1}{2}×\frac {12}{13}= $
$\frac {1}{2}×\frac {2}{3}×\frac {1}{3}= $
$\frac {11}{14}×0×\frac {5}{8}= $
$12×\frac {1}{6}÷\frac {3}{5}= $
$\frac {8}{15}÷\frac {5}{7}×\frac {3}{8}= $
$1÷\frac {6}{7}×\frac {6}{7}= $
$\frac {2}{5}×3÷5= $
$\frac {5}{6}×\frac {2}{15}÷\frac {7}{18}= $
$32×\frac {1}{8}÷\frac {3}{4}= $

答案： 解析：这些题目都是基础的数学运算题目，主要考察分数的乘法和除法运算。
答案：
$\frac{1}{3} × \frac{3}{4} ÷ \frac{4}{5}$
$= \frac{1}{4} ÷ \frac{4}{5}$
$= \frac{5}{16}$
$\frac{1}{5} × \frac{7}{8} × \frac{5}{7}$
$= \frac{7}{40} × \frac{5}{7}$
$= \frac{1}{8}$
$\frac{3}{4} × \frac{4}{9} × \frac{3}{5}$
$= \frac{1}{3} × \frac{3}{5}$
$= \frac{1}{5}$
$\frac{2}{5} ÷ \frac{3}{5} ÷ \frac{4}{7}$
$= \frac{2}{3} ÷ \frac{4}{7}$
$= \frac{7}{6}$
$\frac{1}{6} × \frac{1}{2} × \frac{12}{13}$
$= \frac{1}{12} × \frac{12}{13}$
$= \frac{1}{13}$
$\frac{1}{2} × \frac{2}{3} × \frac{1}{3}$
$= \frac{1}{3} × \frac{1}{3}$
$= \frac{1}{9}$
$\frac{11}{14} × 0 × \frac{5}{8} = 0$
$12 × \frac{1}{6} ÷ \frac{3}{5}$
$= 2 ÷ \frac{3}{5}$
$= \frac{10}{3}$
$\frac{8}{15} ÷ \frac{5}{7} × \frac{3}{8}$
$= \frac{56}{75} × \frac{3}{8}$
$= \frac{7}{25}$
$1 ÷ \frac{6}{7} × \frac{6}{7}$
$= \frac{7}{6} × \frac{6}{7}$
$= 1$
$\frac{2}{5} × 3 ÷ 5$
$= \frac{6}{5} ÷ 5$
$= \frac{6}{25}$
$\frac{5}{6} × \frac{2}{15} ÷ \frac{7}{18}$
$= \frac{1}{9} ÷ \frac{7}{18}$
$= \frac{2}{7}$
$32 × \frac{1}{8} ÷ \frac{3}{4}$
$= 4 ÷ \frac{3}{4}$
$= \frac{16}{3}$

$12×(\frac {1}{3}-\frac {1}{6})=$2
$(\frac {1}{5}+\frac {1}{10})÷\frac {4}{5}=$$\frac {3}{8}$
$\frac {5}{7}+\frac {1}{8}+\frac {2}{7}=$$1\frac {1}{8}$
$\frac {3}{4}×\frac {1}{5}×\frac {4}{9}=$$\frac {1}{15}$
$(\frac {3}{5}-\frac {1}{15})÷\frac {8}{15}=$1
$(\frac {1}{3}+\frac {1}{2})×6=$5
$\frac {5}{6}×\frac {1}{4}×\frac {3}{5}=$$\frac {1}{8}$
$3×\frac {2}{5}+3×\frac {3}{5}=$3
$\frac {7}{12}÷\frac {3}{4}÷\frac {2}{3}=$$\frac {7}{6}$
$(\frac {1}{3}+\frac {2}{9})÷\frac {2}{3}=$$\frac {5}{6}$
$\frac {1}{17}×7÷\frac {1}{17}×7=$49
$(\frac {2}{3}+\frac {3}{4})÷\frac {17}{18}=$$\frac {3}{2}$
$\frac {3}{8}×\frac {2}{9}×\frac {6}{7}=$$\frac {1}{14}$

答案： $12×(\frac {1}{3}-\frac {1}{6})$
$=12×\frac {1}{3}-12×\frac {1}{6}$
$=4 - 2$
$=2$
$(\frac {1}{5}+\frac {1}{10})÷\frac {4}{5}$
$=(\frac {2}{10}+\frac {1}{10})×\frac {5}{4}$
$=\frac {3}{10}×\frac {5}{4}$
$=\frac {3}{8}$
$\frac {5}{7}+\frac {1}{8}+\frac {2}{7}$
$=(\frac {5}{7}+\frac {2}{7})+\frac {1}{8}$
$=1 + \frac {1}{8}$
$=1\frac {1}{8}$
$\frac {3}{4}×\frac {1}{5}×\frac {4}{9}$
$=\frac {3}{4}×\frac {4}{9}×\frac {1}{5}$
$=\frac {1}{3}×\frac {1}{5}$
$=\frac {1}{15}$
$(\frac {3}{5}-\frac {1}{15})÷\frac {8}{15}$
$=(\frac {9}{15}-\frac {1}{15})×\frac {15}{8}$
$=\frac {8}{15}×\frac {15}{8}$
$=1$
$(\frac {1}{3}+\frac {1}{2})×6$
$=\frac {1}{3}×6+\frac {1}{2}×6$
$=2 + 3$
$=5$
$\frac {5}{6}×\frac {1}{4}×\frac {3}{5}$
$=\frac {5}{6}×\frac {3}{5}×\frac {1}{4}$
$=\frac {1}{2}×\frac {1}{4}$
$=\frac {1}{8}$
$3×\frac {2}{5}+3×\frac {3}{5}$
$=3×(\frac {2}{5}+\frac {3}{5})$
$=3×1$
$=3$
$\frac {7}{12}÷\frac {3}{4}÷\frac {2}{3}$
$=\frac {7}{12}×\frac {4}{3}×\frac {3}{2}$
$=\frac {7}{9}×\frac {3}{2}$
$=\frac {7}{6}$
$(\frac {1}{3}+\frac {2}{9})÷\frac {2}{3}$
$=(\frac {3}{9}+\frac {2}{9})×\frac {3}{2}$
$=\frac {5}{9}×\frac {3}{2}$
$=\frac {5}{6}$
$\frac {1}{17}×7÷\frac {1}{17}×7$
$=\frac {1}{17}÷\frac {1}{17}×7×7$
$=1×49$
$=49$
$(\frac {2}{3}+\frac {3}{4})÷\frac {17}{18}$
$=(\frac {8}{12}+\frac {9}{12})×\frac {18}{17}$
$=\frac {17}{12}×\frac {18}{17}$
$=\frac {3}{2}$
$\frac {3}{8}×\frac {2}{9}×\frac {6}{7}$
$=\frac {1}{12}×\frac {6}{7}$
$=\frac {1}{14}$