《2025年口算训练五年级数学上册北师大版双色升级版》

$5.2÷0.4= (52)÷4$ $0.75÷0.25= (75)÷25$
$0.08÷0.2= (0.8)÷2$ $32÷0.08= (3200)÷8$
$0.46÷4.6= (4.6)÷46$ $1÷0.04= (100)÷4$
$0.1÷0.25= (10)÷25$ $5.9÷0.01= 590÷(1)$
$3÷0.6= 30÷(6)$ $0.39÷3.9= 39÷(390)$
$1.9÷0.19= 190÷(19)$ $13.8÷0.46= (1380)÷46$
$0.04÷0.5= 0.4÷(5)$ $0.83÷8.3= (8.3)÷83$
$(0.49)÷0.7= 4.9÷7$ $(36)÷6= 3.6÷0.6$
$0.54÷0.9= (5.4)÷(9)$ $(0.03)÷(0.5)= 0.3÷5$

答案： 52；75；0.8；3200；4.6；100；10；1；6；390；19；1380；5；8.3；0.49；36；5.4，9；0.03，0.5（后两空答案不唯一）

$3.5÷0.5=$7 $6.8÷0.2=$34 $7.8÷0.3=$26
$0.81÷0.9=$0.9 $0.18÷0.6=$0.3 $0.75÷0.5=$1.5
$9.2÷2.3=$4 $0.51÷0.3=$1.7 $73.73÷0.1=$737.3
$37.8÷0.7=$54 $0.39÷13=$0.03 $42.6÷0.6=$71
$3.24÷0.4=$8.1 $11.4÷0.6=$19 $0.45÷1.5=$0.3
$0.45÷15=$0.03 $25.9÷0.7=$37 $2.59÷0.7=$3.7
$1.884÷0.6=$3.14 $5.85÷0.5=$11.7 $0.95÷1.9=$0.5
$0.84÷14=$0.06 $4.914÷0.7=$7.02 $9.72÷0.3=$32.4

答案： $3.5 ÷ 0.5 = 7$
$6.8 ÷ 0.2 = 34$
$7.8 ÷ 0.3 = 26$
$0.81 ÷ 0.9 = 0.9$
$0.18 ÷ 0.6 = 0.3$
$0.75 ÷ 0.5 = 1.5$
$9.2 ÷ 2.3 = 4$
$0.51 ÷ 0.3 = 1.7$
$73.73 ÷ 0.1 = 737.3$
$37.8 ÷ 0.7 = 54$
$0.39 ÷ 13 = 0.03$
$42.6 ÷ 0.6 = 71$
$3.24 ÷ 0.4 = 8.1$
$11.4 ÷ 0.6 = 19$
$0.45 ÷ 1.5 = 0.3$
$0.45 ÷ 15 = 0.03$
$25.9 ÷ 0.7 = 37$
$2.59 ÷ 0.7 = 3.7$
$1.884 ÷ 0.6 = 3.14$
$5.85 ÷ 0.5 = 11.7$
$0.95 ÷ 1.9 = 0.5$
$0.84 ÷ 14 = 0.06$
$4.914 ÷ 0.7 = 7.02$
$9.72 ÷ 0.3 = 32.4$

已知甲数除以乙数的商是$2.86$,如果甲数扩大到原来的$10$倍,乙数缩小到原来的$\frac{1}{10}$,则商是(286)。

答案： 解析：
本题考查的是除法的性质。
根据除法的性质：被除数扩大n倍，商会扩大n倍，除数缩小n倍，商会扩大n倍。
已知甲数除以乙数的商是2.86，现在甲数扩大到原来的10倍，乙数缩小到原来的1/10。
所以商会扩大10÷(1/10)=100倍，即新的商是2.86×100=286。
答案：286。