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用公式法解一元二次方程:
1. $2x^{2}+x - 2 = 0$;
2. $x^{2}-2x = 5$;
3. $x^{2}-6x + 9 = 0$;
4. $x^{2}-4x + 5 = 0$;
5. $2x^{2}-3x - 1 = 0$;
6. $x^{2}-4x - 3 = 0$;
7. $x^{2}+4x - 2 = 0$;
8. $2x^{2}+4x - 3 = 0$;
9. $x^{2}+\sqrt{5}x - 1 = 0$;
10. $\frac{1}{2}x^{2}-\frac{1}{4}x - 1 = 0$.
1. $2x^{2}+x - 2 = 0$;
2. $x^{2}-2x = 5$;
3. $x^{2}-6x + 9 = 0$;
4. $x^{2}-4x + 5 = 0$;
5. $2x^{2}-3x - 1 = 0$;
6. $x^{2}-4x - 3 = 0$;
7. $x^{2}+4x - 2 = 0$;
8. $2x^{2}+4x - 3 = 0$;
9. $x^{2}+\sqrt{5}x - 1 = 0$;
10. $\frac{1}{2}x^{2}-\frac{1}{4}x - 1 = 0$.
答案：
1.$x_{1}=\frac{-1+\sqrt{17}}{4},x_{2}=\frac{-1-\sqrt{17}}{4}$2.$x_{1}=1+\sqrt{6},x_{2}=1-\sqrt{6}$3.$x_{1}=x_{2}=3$4.无实数根5.$x_{1}=\frac{3+\sqrt{17}}{4},x_{2}=\frac{3-\sqrt{17}}{4}$6.$x_{1}=2+\sqrt{7},x_{2}=2-\sqrt{7}$7.$x_{1}=-2+\sqrt{6},x_{2}=-2-\sqrt{6}$8.$x_{1}=\frac{-2+\sqrt{10}}{2},x_{2}=\frac{-2-\sqrt{10}}{2}$9.$x_{1}=\frac{3-\sqrt{5}}{2},x_{2}=\frac{-3-\sqrt{5}}{2}$10.$x_{1}=\frac{1+\sqrt{33}}{4},x_{2}=\frac{1-\sqrt{33}}{4}$
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