搜索
9 计算:
(1) $3\dfrac{1}{3}× \dfrac{6}{7}÷ \left(1\dfrac{3}{4}÷ 3\dfrac{1}{2}\right)$；
(2) $\dfrac{1}{15}÷ 3\dfrac{1}{4}+\dfrac{8}{13}× \dfrac{4}{15}+\dfrac{4}{13}÷ 3\dfrac{3}{4}$；
(3) $\dfrac{17}{2}÷ \left[6\dfrac{1}{3}-\left(3\dfrac{1}{3}+2\dfrac{2}{5}\right)\right]× \dfrac{2}{5}$；
(4) $\left(\dfrac{31}{97}+\dfrac{3131}{97}\right)÷ \dfrac{31313131}{97979797}$。
(1) $3\dfrac{1}{3}× \dfrac{6}{7}÷ \left(1\dfrac{3}{4}÷ 3\dfrac{1}{2}\right)$；
(2) $\dfrac{1}{15}÷ 3\dfrac{1}{4}+\dfrac{8}{13}× \dfrac{4}{15}+\dfrac{4}{13}÷ 3\dfrac{3}{4}$；
(3) $\dfrac{17}{2}÷ \left[6\dfrac{1}{3}-\left(3\dfrac{1}{3}+2\dfrac{2}{5}\right)\right]× \dfrac{2}{5}$；
(4) $\left(\dfrac{31}{97}+\dfrac{3131}{97}\right)÷ \dfrac{31313131}{97979797}$。
答案：
(1) $\frac{40}{7}$
(2) $\frac{4}{15}$
(3) $\frac{17}{3}$
(4) 102
(1) $\frac{40}{7}$
(2) $\frac{4}{15}$
(3) $\frac{17}{3}$
(4) 102
查看更多完整答案，请扫码查看
