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用你喜欢的方法计算下列各题。
$\frac{9}{5}×11.6 + 18.4×\frac{9}{5}$ （$\frac{5}{3} - \frac{4}{9}$）×6×18 64.5×$\frac{1}{11} + \frac{1}{11}×34.5$
13.75×$\frac{5}{8} - 2.75×\frac{5}{8} - \frac{5}{8}$ 24×$\frac{51}{43} + 51×\frac{19}{43}$ 139×$\frac{137}{138} - 137×\frac{1}{138}$
$\frac{15}{4}×(\frac{1}{5} + \frac{2}{3})$ $\frac{15}{21}×\frac{3}{4} + \frac{10}{21}×\frac{3}{4} - 0.75$ 87×$\frac{3}{86}×\frac{2}{3}$
$\frac{2}{9} - \frac{7}{16}×\frac{2}{9}$ $\frac{14}{31}×23 + \frac{9}{31}×23 + 23×\frac{8}{31}$ （$\frac{5}{24} + \frac{7}{12} - \frac{2}{3}$）×48
$\frac{9}{5}×11.6 + 18.4×\frac{9}{5}$ （$\frac{5}{3} - \frac{4}{9}$）×6×18 64.5×$\frac{1}{11} + \frac{1}{11}×34.5$
13.75×$\frac{5}{8} - 2.75×\frac{5}{8} - \frac{5}{8}$ 24×$\frac{51}{43} + 51×\frac{19}{43}$ 139×$\frac{137}{138} - 137×\frac{1}{138}$
$\frac{15}{4}×(\frac{1}{5} + \frac{2}{3})$ $\frac{15}{21}×\frac{3}{4} + \frac{10}{21}×\frac{3}{4} - 0.75$ 87×$\frac{3}{86}×\frac{2}{3}$
$\frac{2}{9} - \frac{7}{16}×\frac{2}{9}$ $\frac{14}{31}×23 + \frac{9}{31}×23 + 23×\frac{8}{31}$ （$\frac{5}{24} + \frac{7}{12} - \frac{2}{3}$）×48
答案：
$\frac{9}{5}$×11.6+18.4×$\frac{9}{5}$
=$\frac{9}{5}$×(11.6+18.4)
=$\frac{9}{5}$×30
=54
($\frac{5}{3}$-$\frac{4}{9}$)×6×18
=$\frac{5}{3}$×6×18−$\frac{4}{9}$×6×18
=180−48
=132
64.5×$\frac{1}{11}$+$\frac{1}{11}$×34.5
=(64.5+34.5)×$\frac{1}{11}$
=99×$\frac{1}{11}$
=9
13.75×$\frac{5}{8}$−2.75×$\frac{5}{8}$-$\frac{5}{8}$
=(13.75−2.75−1)×$\frac{5}{8}$
=10×$\frac{5}{8}$
=$\frac{25}{4}$
24×$\frac{51}{43}$+51×$\frac{19}{43}$
=24×$\frac{51}{43}$+19×$\frac{51}{43}$
=(24+19)×$\frac{51}{43}$
=43×$\frac{51}{43}$
=51
139×$\frac{137}{138}$−137×$\frac{1}{138}$
=139×$\frac{137}{138}$-$\frac{137}{138}$×1
=(139−1)×$\frac{137}{138}$
=138×$\frac{137}{138}$
=137
$\frac{15}{4}$×($\frac{1}{5}$+$\frac{2}{3}$)
=$\frac{15}{4}$×$\frac{1}{5}$+$\frac{15}{4}$×$\frac{2}{3}$
=$\frac{3}{4}$+$\frac{5}{2}$
=$\frac{13}{4}$
$\frac{15}{21}$×$\frac{3}{4}$+$\frac{10}{21}$×$\frac{3}{4}$−0.75
=$\frac{15}{21}$×$\frac{3}{4}$+$\frac{10}{21}$×$\frac{3}{4}$-$\frac{3}{4}$
=$\frac{3}{4}$×($\frac{15}{21}$+$\frac{10}{21}$−1)
=$\frac{3}{4}$×$\frac{4}{21}$
=$\frac{1}{7}$
87×$\frac{3}{86}$×$\frac{2}{3}$
=(86+1)×$\frac{2}{86}$
=86×$\frac{2}{86}$+$\frac{2}{86}$
=2+$\frac{1}{43}$
=2$\frac{1}{43}$
$\frac{2}{9}$-$\frac{7}{16}$×$\frac{2}{9}$
=$\frac{2}{9}$×(1−$\frac{7}{16}$)
=$\frac{2}{9}$×$\frac{9}{16}$
=$\frac{1}{8}$
$\frac{14}{31}$×23+$\frac{9}{31}$×23+23×$\frac{8}{31}$
=($\frac{14}{31}$+$\frac{9}{31}$+$\frac{8}{31}$)×23
=1×23
=23
($\frac{5}{24}$+$\frac{7}{12}$-$\frac{2}{3}$)×48
=$\frac{5}{24}$×48+$\frac{7}{12}$×48−$\frac{2}{3}$×48
=10+28−32
=6
=$\frac{9}{5}$×(11.6+18.4)
=$\frac{9}{5}$×30
=54
($\frac{5}{3}$-$\frac{4}{9}$)×6×18
=$\frac{5}{3}$×6×18−$\frac{4}{9}$×6×18
=180−48
=132
64.5×$\frac{1}{11}$+$\frac{1}{11}$×34.5
=(64.5+34.5)×$\frac{1}{11}$
=99×$\frac{1}{11}$
=9
13.75×$\frac{5}{8}$−2.75×$\frac{5}{8}$-$\frac{5}{8}$
=(13.75−2.75−1)×$\frac{5}{8}$
=10×$\frac{5}{8}$
=$\frac{25}{4}$
24×$\frac{51}{43}$+51×$\frac{19}{43}$
=24×$\frac{51}{43}$+19×$\frac{51}{43}$
=(24+19)×$\frac{51}{43}$
=43×$\frac{51}{43}$
=51
139×$\frac{137}{138}$−137×$\frac{1}{138}$
=139×$\frac{137}{138}$-$\frac{137}{138}$×1
=(139−1)×$\frac{137}{138}$
=138×$\frac{137}{138}$
=137
$\frac{15}{4}$×($\frac{1}{5}$+$\frac{2}{3}$)
=$\frac{15}{4}$×$\frac{1}{5}$+$\frac{15}{4}$×$\frac{2}{3}$
=$\frac{3}{4}$+$\frac{5}{2}$
=$\frac{13}{4}$
$\frac{15}{21}$×$\frac{3}{4}$+$\frac{10}{21}$×$\frac{3}{4}$−0.75
=$\frac{15}{21}$×$\frac{3}{4}$+$\frac{10}{21}$×$\frac{3}{4}$-$\frac{3}{4}$
=$\frac{3}{4}$×($\frac{15}{21}$+$\frac{10}{21}$−1)
=$\frac{3}{4}$×$\frac{4}{21}$
=$\frac{1}{7}$
87×$\frac{3}{86}$×$\frac{2}{3}$
=(86+1)×$\frac{2}{86}$
=86×$\frac{2}{86}$+$\frac{2}{86}$
=2+$\frac{1}{43}$
=2$\frac{1}{43}$
$\frac{2}{9}$-$\frac{7}{16}$×$\frac{2}{9}$
=$\frac{2}{9}$×(1−$\frac{7}{16}$)
=$\frac{2}{9}$×$\frac{9}{16}$
=$\frac{1}{8}$
$\frac{14}{31}$×23+$\frac{9}{31}$×23+23×$\frac{8}{31}$
=($\frac{14}{31}$+$\frac{9}{31}$+$\frac{8}{31}$)×23
=1×23
=23
($\frac{5}{24}$+$\frac{7}{12}$-$\frac{2}{3}$)×48
=$\frac{5}{24}$×48+$\frac{7}{12}$×48−$\frac{2}{3}$×48
=10+28−32
=6
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