用你喜欢的方法计算下面各题。
$15.8\div2.5\div0.4$ $4\times\frac{4}{5}\times25\%\times125$
$3.15 + 6.3 + 83.7 + 4.85$ $124\div12.4 + 2.5\times16$
$\frac{9}{5}\times(5.7 - 3.44\div0.8)$ $(\frac{1}{3} - \frac{1}{6} + \frac{1}{4})\times2.4$
$4.25\times1.8 + \frac{17}{4}\times8.2$ $\frac{9}{23}\times101 - \frac{9}{23}$
$15.8\div2.5\div0.4$ $4\times\frac{4}{5}\times25\%\times125$
$3.15 + 6.3 + 83.7 + 4.85$ $124\div12.4 + 2.5\times16$
$\frac{9}{5}\times(5.7 - 3.44\div0.8)$ $(\frac{1}{3} - \frac{1}{6} + \frac{1}{4})\times2.4$
$4.25\times1.8 + \frac{17}{4}\times8.2$ $\frac{9}{23}\times101 - \frac{9}{23}$
答案:
15.8÷2.5÷0.4
=15.8÷(2.5×0.4)
=15.8÷1
=15.8
$4\times\frac{4}{5}\times25\%\times125$
=(4×0.25)×(125×0.8)
=1×100
=100
3.15 + 6.3 + 83.7 + 4.85
=(3.15 + 4.85)+(6.3 + 83.7)
=8 + 90
=98
124÷12.4 + 2.5×16
=10 + 2.5×4×4
=10 + 10×4
=10 + 40
=50
$\frac{9}{5}\times(5.7 - 3.44÷0.8)$
=$\frac{9}{5}\times(5.7 - 4.3)$
=$\frac{9}{5}\times1.4$
=2.52
$(\frac{1}{3}-\frac{1}{6}+\frac{1}{4})\times2.4$
=$\frac{1}{3}\times2.4-\frac{1}{6}\times2.4+\frac{1}{4}\times2.4$
=0.8 - 0.4 + 0.6
=1
4.25×1.8 + $\frac{17}{4}\times8.2$
=4.25×1.8 + 4.25×8.2
=4.25×(1.8 + 8.2)
=4.25×10
=42.5
$\frac{9}{23}\times101-\frac{9}{23}$
=$\frac{9}{23}\times(101 - 1)$
=$\frac{9}{23}\times100$
=$\frac{900}{23}$
=15.8÷(2.5×0.4)
=15.8÷1
=15.8
$4\times\frac{4}{5}\times25\%\times125$
=(4×0.25)×(125×0.8)
=1×100
=100
3.15 + 6.3 + 83.7 + 4.85
=(3.15 + 4.85)+(6.3 + 83.7)
=8 + 90
=98
124÷12.4 + 2.5×16
=10 + 2.5×4×4
=10 + 10×4
=10 + 40
=50
$\frac{9}{5}\times(5.7 - 3.44÷0.8)$
=$\frac{9}{5}\times(5.7 - 4.3)$
=$\frac{9}{5}\times1.4$
=2.52
$(\frac{1}{3}-\frac{1}{6}+\frac{1}{4})\times2.4$
=$\frac{1}{3}\times2.4-\frac{1}{6}\times2.4+\frac{1}{4}\times2.4$
=0.8 - 0.4 + 0.6
=1
4.25×1.8 + $\frac{17}{4}\times8.2$
=4.25×1.8 + 4.25×8.2
=4.25×(1.8 + 8.2)
=4.25×10
=42.5
$\frac{9}{23}\times101-\frac{9}{23}$
=$\frac{9}{23}\times(101 - 1)$
=$\frac{9}{23}\times100$
=$\frac{900}{23}$
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