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用你喜欢的方法计算下面各题。
$\frac{13}{21}×\frac{4}{7}+\frac{13}{21}×\frac{3}{7}$ （8 + $\frac{4}{5}$）÷4×5 $\frac{1}{13}+\frac{3}{23}+\frac{12}{13}+\frac{20}{23}$
$\frac{3}{5}-\frac{5}{11}+\frac{2}{5}-\frac{2}{11}$ $\frac{15}{17}÷7+\frac{2}{17}×\frac{1}{7}$ （$\frac{1}{3}-\frac{1}{5}+\frac{4}{15}$）×45
（$\frac{1}{19}+\frac{1}{7}$）×19×7 $\frac{5}{23}×24-\frac{5}{23}$ $\frac{15}{28}+\frac{14}{27}+\frac{13}{28}+\frac{12}{27}$
$\frac{2020}{2021}×2022$ 2023×$\frac{2021}{2022}+\frac{1}{2022}$
$\frac{13}{21}×\frac{4}{7}+\frac{13}{21}×\frac{3}{7}$ （8 + $\frac{4}{5}$）÷4×5 $\frac{1}{13}+\frac{3}{23}+\frac{12}{13}+\frac{20}{23}$
$\frac{3}{5}-\frac{5}{11}+\frac{2}{5}-\frac{2}{11}$ $\frac{15}{17}÷7+\frac{2}{17}×\frac{1}{7}$ （$\frac{1}{3}-\frac{1}{5}+\frac{4}{15}$）×45
（$\frac{1}{19}+\frac{1}{7}$）×19×7 $\frac{5}{23}×24-\frac{5}{23}$ $\frac{15}{28}+\frac{14}{27}+\frac{13}{28}+\frac{12}{27}$
$\frac{2020}{2021}×2022$ 2023×$\frac{2021}{2022}+\frac{1}{2022}$
答案：
$\frac{13}{21}\times\frac{4}{7}+\frac{13}{21}\times\frac{3}{7}$
=$\frac{13}{21}\times(\frac{4}{7}+\frac{3}{7})$
=$\frac{13}{21}\times1$
=$\frac{13}{21}$
(8 + $\frac{4}{5}$)÷4×5
=(8 + $\frac{4}{5}$)×$\frac{1}{4}$×5
=8×$\frac{1}{4}$×5 + $\frac{4}{5}$×$\frac{1}{4}$×5
=10 + 1
=11
$\frac{1}{13}+\frac{3}{23}+\frac{12}{13}+\frac{20}{23}$
=($\frac{1}{13}+\frac{12}{13}$)+($\frac{3}{23}+\frac{20}{23}$)
=1 + 1
=2
$\frac{3}{5}-\frac{5}{11}+\frac{2}{5}-\frac{2}{11}$
=($\frac{3}{5}+\frac{2}{5}$)-($\frac{5}{11}+\frac{2}{11}$)
=1 - $\frac{7}{11}$
=$\frac{4}{11}$
$\frac{15}{17}\div7+\frac{2}{17}\times\frac{1}{7}$
=$\frac{15}{17}\times\frac{1}{7}+\frac{2}{17}\times\frac{1}{7}$
=($\frac{15}{17}+\frac{2}{17}$)×$\frac{1}{7}$
=1×$\frac{1}{7}$
=$\frac{1}{7}$
($\frac{1}{3}-\frac{1}{5}+\frac{4}{15}$)×45
=$\frac{1}{3}$×45 - $\frac{1}{5}$×45 + $\frac{4}{15}$×45
=15 - 9 + 12
=18
($\frac{1}{19}+\frac{1}{7}$)×19×7
=$\frac{1}{19}$×19×7 + $\frac{1}{7}$×19×7
=7 + 19
=26
$\frac{5}{23}\times24-\frac{5}{23}$
=$\frac{5}{23}\times(24 - 1)$
=$\frac{5}{23}\times23$
=5
$\frac{15}{28}+\frac{14}{27}+\frac{13}{28}+\frac{12}{27}$
=($\frac{15}{28}+\frac{13}{28}$)+($\frac{14}{27}+\frac{12}{27}$)
=1 + $\frac{26}{27}$
=1$\frac{26}{27}$
$\frac{2020}{2021}\times2022$
=$\frac{2020}{2021}\times(2021 + 1)$
=$\frac{2020}{2021}\times2021+\frac{2020}{2021}\times1$
=2020 + $\frac{2020}{2021}$
=2020$\frac{2020}{2021}$
2023×$\frac{2021}{2022}+\frac{1}{2022}$
=(2022 + 1)×$\frac{2021}{2022}+\frac{1}{2022}$
=2022×$\frac{2021}{2022}+(\frac{2021}{2022}+\frac{1}{2022})$
=2021 + 1
=2022
=$\frac{13}{21}\times(\frac{4}{7}+\frac{3}{7})$
=$\frac{13}{21}\times1$
=$\frac{13}{21}$
(8 + $\frac{4}{5}$)÷4×5
=(8 + $\frac{4}{5}$)×$\frac{1}{4}$×5
=8×$\frac{1}{4}$×5 + $\frac{4}{5}$×$\frac{1}{4}$×5
=10 + 1
=11
$\frac{1}{13}+\frac{3}{23}+\frac{12}{13}+\frac{20}{23}$
=($\frac{1}{13}+\frac{12}{13}$)+($\frac{3}{23}+\frac{20}{23}$)
=1 + 1
=2
$\frac{3}{5}-\frac{5}{11}+\frac{2}{5}-\frac{2}{11}$
=($\frac{3}{5}+\frac{2}{5}$)-($\frac{5}{11}+\frac{2}{11}$)
=1 - $\frac{7}{11}$
=$\frac{4}{11}$
$\frac{15}{17}\div7+\frac{2}{17}\times\frac{1}{7}$
=$\frac{15}{17}\times\frac{1}{7}+\frac{2}{17}\times\frac{1}{7}$
=($\frac{15}{17}+\frac{2}{17}$)×$\frac{1}{7}$
=1×$\frac{1}{7}$
=$\frac{1}{7}$
($\frac{1}{3}-\frac{1}{5}+\frac{4}{15}$)×45
=$\frac{1}{3}$×45 - $\frac{1}{5}$×45 + $\frac{4}{15}$×45
=15 - 9 + 12
=18
($\frac{1}{19}+\frac{1}{7}$)×19×7
=$\frac{1}{19}$×19×7 + $\frac{1}{7}$×19×7
=7 + 19
=26
$\frac{5}{23}\times24-\frac{5}{23}$
=$\frac{5}{23}\times(24 - 1)$
=$\frac{5}{23}\times23$
=5
$\frac{15}{28}+\frac{14}{27}+\frac{13}{28}+\frac{12}{27}$
=($\frac{15}{28}+\frac{13}{28}$)+($\frac{14}{27}+\frac{12}{27}$)
=1 + $\frac{26}{27}$
=1$\frac{26}{27}$
$\frac{2020}{2021}\times2022$
=$\frac{2020}{2021}\times(2021 + 1)$
=$\frac{2020}{2021}\times2021+\frac{2020}{2021}\times1$
=2020 + $\frac{2020}{2021}$
=2020$\frac{2020}{2021}$
2023×$\frac{2021}{2022}+\frac{1}{2022}$
=(2022 + 1)×$\frac{2021}{2022}+\frac{1}{2022}$
=2022×$\frac{2021}{2022}+(\frac{2021}{2022}+\frac{1}{2022})$
=2021 + 1
=2022
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