《2025年心算口算巧算六年级上册北师大版》

计算下面各题。$\frac{4}{5} × \frac{25}{16} + \frac{2}{3} × \frac{3}{4}$

答案： 解：$\frac{5}{4} + \frac{1}{2} = \frac{5}{4} + \frac{2}{4} = \frac{7}{4}$

$\frac{14}{3} × \frac{8}{7} - \frac{5}{6} × \frac{12}{15}$

答案： 解：$\frac{16}{3} - \frac{2}{3} = \frac{14}{3}$

$\frac{17}{32} ÷ 17 + \frac{3}{4} × \frac{9}{24}$

答案： 解：$\frac{17}{32} × \frac{1}{17} + \frac{27}{96} = \frac{1}{32} + \frac{9}{32} = \frac{10}{32} = \frac{5}{16}$

$(\frac{1}{3} + \frac{1}{4}) × 24$

答案： 解：$\frac{1}{3} × 24 + \frac{1}{4} × 24 = 8 + 6 = 14$

$(\frac{5}{8} + \frac{1}{4}) ÷ (\frac{3}{4} - \frac{1}{2})$

答案： 解：分子：$\frac{5}{8} + \frac{2}{8} = \frac{7}{8}$，分母：$\frac{3}{4} - \frac{2}{4} = \frac{1}{4}$
$\frac{7}{8} ÷ \frac{1}{4} = \frac{7}{8} × 4 = \frac{7}{2}$

$\frac{3}{4} - (\frac{7}{16} - \frac{1}{4})$

答案： 解：$\frac{3}{4} - \frac{7}{16} + \frac{1}{4} = (\frac{3}{4} + \frac{1}{4}) - \frac{7}{16} = 1 - \frac{7}{16} = \frac{9}{16}$

$\frac{4}{5} + \frac{4}{5} ÷ \frac{2}{3}$

答案： 解：$\frac{4}{5} + \frac{4}{5} × \frac{3}{2} = \frac{4}{5} + \frac{6}{5} = 2$

$(\frac{1}{2} + \frac{2}{3}) × \frac{2}{7}$

答案： 解：括号内：$\frac{3}{6} + \frac{4}{6} = \frac{7}{6}$
$\frac{7}{6} × \frac{2}{7} = \frac{1}{3}$

$\frac{16}{27} + \frac{11}{27} ÷ \frac{1}{5}$

答案： 解：$\frac{16}{27} + \frac{11}{27} × 5 = \frac{16}{27} + \frac{55}{27} = \frac{71}{27}$

$(\frac{1}{5} + \frac{1}{3}) ÷ \frac{8}{9}$

答案： 解：括号内：$\frac{3}{15} + \frac{5}{15} = \frac{8}{15}$
$\frac{8}{15} × \frac{9}{8} = \frac{3}{5}$

$\frac{5}{6} ÷ \frac{1}{8} × \frac{9}{16}$

答案： 解：$\frac{5}{6} × 8 × \frac{9}{16} = \frac{5 × 8 × 9}{6 × 16} = \frac{15}{4}$

$8 × \frac{1}{10} × \frac{25}{2}$

答案： 解：$8 × \frac{25}{20} = 8 × \frac{5}{4} = 10$

$200 ÷ (2 - \frac{2}{5})$

答案： 解：括号内：$\frac{10}{5} - \frac{2}{5} = \frac{8}{5}$
$200 × \frac{5}{8} = 125$

$\frac{9}{100} ÷ \frac{3}{5} + \frac{3}{10}$

答案： 解：$\frac{9}{100} × \frac{5}{3} + \frac{3}{10} = \frac{3}{20} + \frac{6}{20} = \frac{9}{20}$

$\frac{3}{50} × \frac{5}{9} + \frac{1}{25}$

答案： 解：$\frac{1}{30} + \frac{1}{25} = \frac{5}{150} + \frac{6}{150} = \frac{11}{150}$