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计算下面各题。
$(\frac{5}{6} + \frac{7}{24})×24$
$\frac{5}{3}×\frac{11}{5}×\frac{3}{4}$
$\frac{1}{4} + \frac{3}{4}÷\frac{2}{3}$
$\frac{8}{9}×\frac{21}{16} + \frac{1}{2}$
$\frac{8}{25}×\frac{5}{16}×\frac{2}{5}$
$\frac{7}{19} + \frac{12}{19}×\frac{5}{6}$
$\frac{4}{5} + \frac{4}{5}×\frac{1}{4}$
$\frac{7}{12}×\frac{4}{3} + \frac{2}{3}$
$21×(1 - \frac{2}{7})$
$\frac{5}{4}×\frac{1}{8}×16$
$\frac{8}{15}×\frac{5}{4}×\frac{2}{3}$
$(\frac{1}{2} - \frac{1}{4})×\frac{9}{10}$
$\frac{2}{5}×\frac{6}{7} - \frac{1}{7}×\frac{2}{5}$
$\frac{5}{8}×\frac{7}{9}×\frac{3}{7}$
$\frac{8}{13}×\frac{9}{10} + \frac{8}{13}×\frac{1}{10}$
$(\frac{5}{6} + \frac{7}{24})×24$
$\frac{5}{3}×\frac{11}{5}×\frac{3}{4}$
$\frac{1}{4} + \frac{3}{4}÷\frac{2}{3}$
$\frac{8}{9}×\frac{21}{16} + \frac{1}{2}$
$\frac{8}{25}×\frac{5}{16}×\frac{2}{5}$
$\frac{7}{19} + \frac{12}{19}×\frac{5}{6}$
$\frac{4}{5} + \frac{4}{5}×\frac{1}{4}$
$\frac{7}{12}×\frac{4}{3} + \frac{2}{3}$
$21×(1 - \frac{2}{7})$
$\frac{5}{4}×\frac{1}{8}×16$
$\frac{8}{15}×\frac{5}{4}×\frac{2}{3}$
$(\frac{1}{2} - \frac{1}{4})×\frac{9}{10}$
$\frac{2}{5}×\frac{6}{7} - \frac{1}{7}×\frac{2}{5}$
$\frac{5}{8}×\frac{7}{9}×\frac{3}{7}$
$\frac{8}{13}×\frac{9}{10} + \frac{8}{13}×\frac{1}{10}$
答案：
$(\frac{5}{6} + \frac{7}{24})×24$
解：$\frac{5}{6}×24 + \frac{7}{24}×24=20 + 7=27$
$\frac{5}{3}×\frac{11}{5}×\frac{3}{4}$
解：$\frac{11}{3}×\frac{3}{4}=\frac{11}{4}$
$\frac{1}{4} + \frac{3}{4}÷\frac{2}{3}$
解：$\frac{3}{4}×\frac{3}{2}=\frac{9}{8}$，$\frac{1}{4} + \frac{9}{8}=\frac{11}{8}$
$\frac{8}{9}×\frac{21}{16} + \frac{1}{2}$
解：$\frac{168}{144}=\frac{7}{9}$，$\frac{7}{9} + \frac{1}{2}=\frac{23}{18}$
$\frac{8}{25}×\frac{5}{16}×\frac{2}{5}$
解：$\frac{40}{400}=\frac{1}{10}$，$\frac{1}{10}×\frac{2}{5}=\frac{1}{25}$
$\frac{7}{19} + \frac{12}{19}×\frac{5}{6}$
解：$\frac{12}{19}×\frac{5}{6}=\frac{10}{19}$，$\frac{7}{19} + \frac{10}{19}=\frac{17}{19}$
$\frac{4}{5} + \frac{4}{5}×\frac{1}{4}$
解：$\frac{4}{5}×(1 + \frac{1}{4})=\frac{4}{5}×\frac{5}{4}=1$
$\frac{7}{12}×\frac{4}{3} + \frac{2}{3}$
解：$\frac{28}{36}=\frac{7}{9}$，$\frac{7}{9} + \frac{6}{9}=\frac{13}{9}$
$21×(1 - \frac{2}{7})$
解：$21×\frac{5}{7}=15$
$\frac{5}{4}×\frac{1}{8}×16$
解：$\frac{5}{4}×2=\frac{5}{2}$
$\frac{8}{15}×\frac{5}{4}×\frac{2}{3}$
解：$\frac{40}{60}=\frac{2}{3}$，$\frac{2}{3}×\frac{2}{3}=\frac{4}{9}$
$(\frac{1}{2} - \frac{1}{4})×\frac{9}{10}$
解：$\frac{1}{4}×\frac{9}{10}=\frac{9}{40}$
$\frac{2}{5}×\frac{6}{7} - \frac{1}{7}×\frac{2}{5}$
解：$\frac{2}{5}×(\frac{6}{7} - \frac{1}{7})=\frac{2}{5}×\frac{5}{7}=\frac{2}{7}$
$\frac{5}{8}×\frac{7}{9}×\frac{3}{7}$
解：$\frac{5}{8}×\frac{1}{3}=\frac{5}{24}$
$\frac{8}{13}×\frac{9}{10} + \frac{8}{13}×\frac{1}{10}$
解：$\frac{8}{13}×(\frac{9}{10} + \frac{1}{10})=\frac{8}{13}×1=\frac{8}{13}$
解：$\frac{5}{6}×24 + \frac{7}{24}×24=20 + 7=27$
$\frac{5}{3}×\frac{11}{5}×\frac{3}{4}$
解：$\frac{11}{3}×\frac{3}{4}=\frac{11}{4}$
$\frac{1}{4} + \frac{3}{4}÷\frac{2}{3}$
解：$\frac{3}{4}×\frac{3}{2}=\frac{9}{8}$，$\frac{1}{4} + \frac{9}{8}=\frac{11}{8}$
$\frac{8}{9}×\frac{21}{16} + \frac{1}{2}$
解：$\frac{168}{144}=\frac{7}{9}$，$\frac{7}{9} + \frac{1}{2}=\frac{23}{18}$
$\frac{8}{25}×\frac{5}{16}×\frac{2}{5}$
解：$\frac{40}{400}=\frac{1}{10}$，$\frac{1}{10}×\frac{2}{5}=\frac{1}{25}$
$\frac{7}{19} + \frac{12}{19}×\frac{5}{6}$
解：$\frac{12}{19}×\frac{5}{6}=\frac{10}{19}$，$\frac{7}{19} + \frac{10}{19}=\frac{17}{19}$
$\frac{4}{5} + \frac{4}{5}×\frac{1}{4}$
解：$\frac{4}{5}×(1 + \frac{1}{4})=\frac{4}{5}×\frac{5}{4}=1$
$\frac{7}{12}×\frac{4}{3} + \frac{2}{3}$
解：$\frac{28}{36}=\frac{7}{9}$，$\frac{7}{9} + \frac{6}{9}=\frac{13}{9}$
$21×(1 - \frac{2}{7})$
解：$21×\frac{5}{7}=15$
$\frac{5}{4}×\frac{1}{8}×16$
解：$\frac{5}{4}×2=\frac{5}{2}$
$\frac{8}{15}×\frac{5}{4}×\frac{2}{3}$
解：$\frac{40}{60}=\frac{2}{3}$，$\frac{2}{3}×\frac{2}{3}=\frac{4}{9}$
$(\frac{1}{2} - \frac{1}{4})×\frac{9}{10}$
解：$\frac{1}{4}×\frac{9}{10}=\frac{9}{40}$
$\frac{2}{5}×\frac{6}{7} - \frac{1}{7}×\frac{2}{5}$
解：$\frac{2}{5}×(\frac{6}{7} - \frac{1}{7})=\frac{2}{5}×\frac{5}{7}=\frac{2}{7}$
$\frac{5}{8}×\frac{7}{9}×\frac{3}{7}$
解：$\frac{5}{8}×\frac{1}{3}=\frac{5}{24}$
$\frac{8}{13}×\frac{9}{10} + \frac{8}{13}×\frac{1}{10}$
解：$\frac{8}{13}×(\frac{9}{10} + \frac{1}{10})=\frac{8}{13}×1=\frac{8}{13}$
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