《2025年同步口算练习册六年级数学上册人教版》

1. 直接写得数。
$\frac {1}{6}+\frac {3}{8}=$
$\frac {4}{13}×\frac {11}{12}=$
$0.9×\frac {2}{3}=$
$\frac {23}{10}×100=$
$\frac {4}{5}×\frac {9}{16}=$
$\frac {5}{11}×4.4=$
$\frac {8}{19}×8=$
$\frac {7}{20}-\frac {1}{4}=$
$\frac {5}{7}×35=$
$2-\frac {9}{11}=$
$\frac {4}{3}×\frac {9}{4}=$
$\frac {1}{3}+\frac {1}{4}=$
$\frac {2}{9}×\frac {1}{4}=$
$\frac {2}{3}+\frac {3}{4}×1=$
$12×(\frac {1}{2}+\frac {1}{3})=$
$4×(\frac {3}{4}-\frac {1}{2})=$

答案： $\frac {13}{24}$
$\frac {11}{39}$
0.6
230
$\frac {9}{20}$
2
$\frac {64}{19}$
$\frac {1}{10}$
25
$\frac {13}{11}$
3
$\frac {7}{12}$
$\frac {1}{18}$
$\frac {17}{12}$
10
1

2. 把上下结果相等的两个算式连起来。
$\frac {4}{5}×\frac {1}{6}+\frac {1}{5}×\frac {1}{6}$
$\frac {1}{6}+(\frac {4}{5}+\frac {1}{5})$
$\frac {4}{5}×\frac {1}{6}×\frac {1}{5}$
$\frac {4}{5}×\frac {1}{5}×\frac {1}{6}$
$(\frac {4}{5}+\frac {1}{5})×\frac {1}{6}$
$\frac {4}{5}+\frac {1}{5}+\frac {1}{6}$

答案： $\frac{4}{5}×\frac{1}{6}+\frac{1}{5}×\frac{1}{6}$-$(\frac{4}{5}+\frac{1}{5})×\frac{1}{6}$
$\frac{1}{6}+(\frac{4}{5}+\frac{1}{5})$ -$\frac{4}{5}+\frac{1}{5}+\frac{1}{6}$
$\frac{4}{5}×\frac{1}{6}×\frac{1}{5}$-$\frac{4}{5}×\frac{1}{5}×\frac{1}{6}$

3. 在〇里填“＞”“＜”或“=”。
$4×\frac {1}{2}$〇2
$0×\frac {3}{4}$〇$0+\frac {3}{4}$
$50×\frac {1}{2}$〇2.5
$\frac {5}{9}$〇$1-\frac {5}{9}×\frac {1}{5}$
$\frac {11}{8}×\frac {8}{11}$〇$\frac {1}{5}×5$
$\frac {3}{8}+1$〇$\frac {3}{8}×1$

答案： =
＜
＞
＜
=
＞

一桶油在甲、乙两个超市的原价都是80元。节假日优惠活动如右图，在（ ）超市买更便宜。
甲超市：降价$\frac {1}{10}$出售
乙超市：降价10元出售

答案： 甲
解析：甲超市：$80×(1 - \frac{1}{10}) = 72$（元），乙超市：$80 - 10 = 70$（元），72＞70，所以乙超市便宜。（注：此处根据计算结果应为乙，原答案可能有误，按正确计算修正）