2025年暑假作业吉林教育出版社五年级综合北师大版
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1. 直接写出得数。
$\frac {1}{2}+\frac {1}{3}= $
$40÷\frac {8}{9}= $
$\frac {1}{2}+\frac {1}{3}= $
$\frac{5}{6}$
$\frac {1}{4}-\frac {1}{5}= $$\frac{1}{20}$
$48×\frac {3}{4}= $$36$
$\frac {4}{15}×\frac {5}{6}= $$\frac{2}{9}$
$40÷\frac {8}{9}= $
$45$
$1÷\frac {7}{8}= $$\frac{8}{7}$
$\frac {1}{8}×\frac {2}{3}= $$\frac{1}{12}$
$\frac {4}{15}×\frac {5}{17}= $$\frac{4}{51}$
答案:
$\frac{5}{6}$;$\frac{1}{20}$;$36$;$\frac{2}{9}$;$45$;$\frac{8}{7}$;$\frac{1}{12}$;$\frac{4}{51}$
2. 脱式计算。
$\frac {5}{12}+\frac {1}{6}+\frac {2}{9}$ $\frac {9}{10}-\frac {1}{5}-\frac {2}{3}$ $1-(\frac {2}{3}-\frac {2}{9})$
$\frac {15}{8}-\frac {5}{6}+\frac {1}{4}$ $\frac {7}{12}-\frac {1}{8}+\frac {1}{4}$ $\frac {11}{14}-(\frac {5}{18}+\frac {1}{7})$
$\frac {5}{12}+\frac {1}{6}+\frac {2}{9}$ $\frac {9}{10}-\frac {1}{5}-\frac {2}{3}$ $1-(\frac {2}{3}-\frac {2}{9})$
$\frac {15}{8}-\frac {5}{6}+\frac {1}{4}$ $\frac {7}{12}-\frac {1}{8}+\frac {1}{4}$ $\frac {11}{14}-(\frac {5}{18}+\frac {1}{7})$
答案:
$\frac{29}{36}$;$\frac{1}{30}$;$\frac{5}{9}$;$\frac{31}{24}$;$\frac{17}{24}$;$\frac{23}{63}$
3. 解方程。
$6x - x = 75$(
$x - \frac{3}{8} = \frac{13}{16}$(
$\frac{7}{8}y = \frac{3}{4}$(
$3.7 - 0.3x = 1.9$(
$8m - 16 = 40$(
$x÷6 = \frac{1}{6}$(
$6x - x = 75$(
$x = 15$
)$x - \frac{3}{8} = \frac{13}{16}$(
$x=\frac{19}{16}$
)$\frac{7}{8}y = \frac{3}{4}$(
$y=\frac{6}{7}$
)$3.7 - 0.3x = 1.9$(
$x = 6$
)$8m - 16 = 40$(
$m = 7$
)$x÷6 = \frac{1}{6}$(
$x = 1$
)
答案:
$x = 15$;$x=\frac{19}{16}$;$y=\frac{6}{7}$;$x = 6$;$m = 7$;$x = 1$
4. 列式计算。
(1)一个数的$\frac {5}{12}等于\frac {5}{6}$,求这个数。 (2)$\frac {9}{10}减去\frac {7}{15}的差与\frac {13}{20}$的和是多少?
(1)一个数的$\frac {5}{12}等于\frac {5}{6}$,求这个数。 (2)$\frac {9}{10}减去\frac {7}{15}的差与\frac {13}{20}$的和是多少?
答案:
(1)2;
(2)$\frac{13}{12}$
(1)2;
(2)$\frac{13}{12}$
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