《2025年新课程能力培养六年级数学上册北师大版》

解方程
$ x + 70\%x = 340 $
$ \frac{2}{3}x + 70\%x = \frac{1}{6} $
$ x - 15\%x = 68 $
$ (1 - 25\%)x = 45 $

答案： 1. $x + 70\%x = 340$
解：$1.7x = 340$
$x = 340÷1.7$
$x = 200$
2. $\frac{2}{3}x + 70\%x = \frac{1}{6}$
解：$\frac{2}{3}x + \frac{7}{10}x = \frac{1}{6}$
$\frac{20}{30}x + \frac{21}{30}x = \frac{1}{6}$
$\frac{41}{30}x = \frac{1}{6}$
$x = \frac{1}{6}×\frac{30}{41}$
$x = \frac{5}{41}$
3. $x - 15\%x = 68$
解：$0.85x = 68$
$x = 68÷0.85$
$x = 80$
4. $(1 - 25\%)x = 45$
解：$0.75x = 45$
$x = 45÷0.75$
$x = 60$