3. 码头有 $125.5 t$ 货物,上午运走总数的 $\frac{2}{5}$,下午运走的是上午的 $\frac{3}{4}$。下午运走总数的几分之几?下午运走了多少吨?
答案:
$3. \frac{2}{5}×\frac{3}{4}=\frac{3}{10} 125.5×\frac{3}{10}=37.65(t)$
1. 在○里填上“>”“<”或“=”。
$\frac{3}{5} × \frac{1}{4}$ ○ $\frac{1}{4} × \frac{3}{5}$
$(\frac{7}{2} × \frac{5}{3}) × \frac{3}{7}$ ○ $\frac{7}{2} + (\frac{5}{3} × \frac{3}{7})$
$\frac{7}{8} × \frac{1}{6}$ ○ $\frac{7}{6} × \frac{1}{8}$
$(\frac{1}{2} + \frac{1}{5}) × 10$ ○ $\frac{1}{2} + \frac{1}{5} × 10$
$\frac{3}{5} × \frac{1}{4}$ ○ $\frac{1}{4} × \frac{3}{5}$
$(\frac{7}{2} × \frac{5}{3}) × \frac{3}{7}$ ○ $\frac{7}{2} + (\frac{5}{3} × \frac{3}{7})$
$\frac{7}{8} × \frac{1}{6}$ ○ $\frac{7}{6} × \frac{1}{8}$
$(\frac{1}{2} + \frac{1}{5}) × 10$ ○ $\frac{1}{2} + \frac{1}{5} × 10$
答案:
1.= < = >
2. 在□里填上合适的数。
$\frac{7}{8} × \frac{9}{47} × \frac{8}{7} = $ □ $×$ □ $× \frac{9}{47}$
$(\frac{13}{5} + \frac{13}{9}) × \frac{1}{13} = $ □ $×$ □ $+$ □ $×$ □
$\frac{7}{10} × \frac{4}{5} + \frac{7}{10} × \frac{1}{5} = ($ □ $+$ □ $) ×$ □
$\frac{7}{8} × \frac{9}{47} × \frac{8}{7} = $ □ $×$ □ $× \frac{9}{47}$
$(\frac{13}{5} + \frac{13}{9}) × \frac{1}{13} = $ □ $×$ □ $+$ □ $×$ □
$\frac{7}{10} × \frac{4}{5} + \frac{7}{10} × \frac{1}{5} = ($ □ $+$ □ $) ×$ □
答案:
2.$\frac{7}{8}$ $\frac{8}{7}$ $\frac{13}{5}$ $\frac{1}{13}$ $\frac{13}{9}$ $\frac{1}{13}$ $\frac{4}{5}$ $\frac{1}{5}$ $\frac{7}{10}$
用简便算法计算下面各题。
$(\frac{5}{6} + \frac{5}{8}) × 2.4$
$\frac{5}{6} × \frac{2}{9} + \frac{5}{6} × \frac{7}{9} - \frac{5}{6}$
$58 × \frac{5}{9} - \frac{5}{9} × 31$
$\frac{5}{7} × (\frac{2}{3} × \frac{7}{5})$
$(\frac{5}{6} + \frac{5}{8}) × 2.4$
$\frac{5}{6} × \frac{2}{9} + \frac{5}{6} × \frac{7}{9} - \frac{5}{6}$
$58 × \frac{5}{9} - \frac{5}{9} × 31$
$\frac{5}{7} × (\frac{2}{3} × \frac{7}{5})$
答案:
快乐闯关
5 0 15 $\frac{2}{3}$
5 0 15 $\frac{2}{3}$
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