《2025年速算天地数学口算心算六年级上册苏教版》

$\frac{1}{7} + \frac{1}{3} = $$\frac{10}{21}$ $\frac{5}{2} × \frac{1}{5} = $$\frac{1}{2}$
$12 ÷ \frac{1}{4} = $48 $\frac{4}{9} ÷ \frac{1}{2} = $$\frac{8}{9}$
$\frac{1}{3} - \frac{1}{6} = $$\frac{1}{6}$ $3 ÷ \frac{1}{9} = $27
$6 × \frac{3}{8} = $$\frac{9}{4}$ $4 - \frac{3}{4} - \frac{1}{4} = $3
$25 × \frac{4}{5} = $20 $\frac{5}{3} × \frac{5}{8} × \frac{4}{5} = $$\frac{5}{6}$
$\frac{5}{8} - \frac{1}{2} = $$\frac{1}{8}$ $6 ÷ 7 + \frac{1}{7} = $1
$\frac{7}{8} × \frac{3}{14} = $$\frac{3}{16}$ $(3 + \frac{5}{6}) × 6 = $23
$\frac{9}{10} - \frac{3}{10} = $$\frac{3}{5}$ $\frac{5}{4} × \frac{2}{15} + \frac{5}{6} = $1
$39 × \frac{4}{13} = $12 $4 × \frac{4}{9} + \frac{5}{9} × 4 = $4
$\frac{1}{3} + \frac{1}{8} = $$\frac{11}{24}$ $11 × (10 + \frac{1}{11}) = $111
$0 × \frac{5}{12} = $0 $(\frac{1}{7} + \frac{1}{5}) × 35 = $12

答案： $\frac{1}{7} + \frac{1}{3} = \frac{3}{21} + \frac{7}{21} = \frac{10}{21}$
$\frac{5}{2} × \frac{1}{5} = \frac{5×1}{2×5} = \frac{1}{2}$
$12 ÷ \frac{1}{4} = 12×4 = 48$
$\frac{4}{9} ÷ \frac{1}{2} = \frac{4}{9}×2 = \frac{8}{9}$
$\frac{1}{3} - \frac{1}{6} = \frac{2}{6} - \frac{1}{6} = \frac{1}{6}$
$3 ÷ \frac{1}{9} = 3×9 = 27$
$6 × \frac{3}{8} = \frac{6×3}{8} = \frac{18}{8} = \frac{9}{4}$
$4 - \frac{3}{4} - \frac{1}{4} = 4 - (\frac{3}{4} + \frac{1}{4}) = 4 - 1 = 3$
$25 × \frac{4}{5} = 5×4 = 20$
$\frac{5}{3} × \frac{5}{8} × \frac{4}{5} = \frac{5}{3}×(\frac{5}{8}×\frac{4}{5}) = \frac{5}{3}×\frac{1}{2} = \frac{5}{6}$
$\frac{5}{8} - \frac{1}{2} = \frac{5}{8} - \frac{4}{8} = \frac{1}{8}$
$6 ÷ 7 + \frac{1}{7} = \frac{6}{7} + \frac{1}{7} = 1$
$\frac{7}{8} × \frac{3}{14} = \frac{7×3}{8×14} = \frac{3}{16}$
$(3 + \frac{5}{6}) × 6 = 3×6 + \frac{5}{6}×6 = 18 + 5 = 23$
$\frac{9}{10} - \frac{3}{10} = \frac{6}{10} = \frac{3}{5}$
$\frac{5}{4} × \frac{2}{15} + \frac{5}{6} = \frac{1}{6} + \frac{5}{6} = 1$
$39 × \frac{4}{13} = 3×4 = 12$
$4 × \frac{4}{9} + \frac{5}{9} × 4 = 4×(\frac{4}{9} + \frac{5}{9}) = 4×1 = 4$
$\frac{1}{3} + \frac{1}{8} = \frac{8}{24} + \frac{3}{24} = \frac{11}{24}$
$11 × (10 + \frac{1}{11}) = 11×10 + 11×\frac{1}{11} = 110 + 1 = 111$
$0 × \frac{5}{12} = 0$
$(\frac{1}{7} + \frac{1}{5}) × 35 = \frac{1}{7}×35 + \frac{1}{5}×35 = 5 + 7 = 12$