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2025年快乐暑假活动五年级数学
注：目前有些书本章节名称可能整理的还不是很完善，但都是按照顺序排列的，请同学们按照顺序仔细查找。练习册 2025年快乐暑假活动五年级数学 答案主要是用来给同学们做完题方便对答案用的，请勿直接抄袭。
一、我会填。
1. $\frac {1}{5}+\frac {2}{3}=\frac {2}{3}+\frac {
2. $\frac {3}{7}+\frac {2}{9}+\frac {7}{9}=\frac {
3. $\frac {11}{13}-\frac {5}{12}-\frac {1}{12}=\frac {11}{13}-(\frac {
4. $\frac {1}{4}+\frac {7}{15}+\frac {3}{4}+\frac {8}{15}=(\frac {
5. $(\frac {1}{12}+\frac {3}{4})+(\frac {7}{12}+\frac {1}{4})=(\frac {1}{12}+\frac {
1. $\frac {1}{5}+\frac {2}{3}=\frac {2}{3}+\frac {
1
}{5
}$2. $\frac {3}{7}+\frac {2}{9}+\frac {7}{9}=\frac {
3
}{7
}+(\frac {2}{9}+\frac {7}{9})$3. $\frac {11}{13}-\frac {5}{12}-\frac {1}{12}=\frac {11}{13}-(\frac {
5
}{12
}+\frac {1
}{12
})$4. $\frac {1}{4}+\frac {7}{15}+\frac {3}{4}+\frac {8}{15}=(\frac {
1
}{4
}+\frac {3
}{4
})+(\frac {7
}{15
}+\frac {8
}{15
})$5. $(\frac {1}{12}+\frac {3}{4})+(\frac {7}{12}+\frac {1}{4})=(\frac {1}{12}+\frac {
7
}{12
})+(\frac {3}{4}+\frac {1
}{4
})$
答案：
1. $\frac{1}{5}$ 2. $\frac{3}{7}$ 3. $\frac{5}{12}$ $\frac{1}{12}$
4. $\frac{1}{4}$ $\frac{3}{4}$ $\frac{7}{15}$ $\frac{8}{15}$
5. $\frac{7}{12}$ $\frac{1}{4}$
4. $\frac{1}{4}$ $\frac{3}{4}$ $\frac{7}{15}$ $\frac{8}{15}$
5. $\frac{7}{12}$ $\frac{1}{4}$
二、判断对错。(对的画“√”，错的画“×”)
1. $\frac {3}{5}+\frac {5}{8}-\frac {1}{2}=\frac {3+5-1}{5+8-2}=\frac {7}{11}$(
2. $1-\frac {3}{5}+\frac {2}{5}=1-1=0$(
3. $\frac {5}{9}-\frac {5}{12}+\frac {1}{12}=\frac {1}{18}$(
1. $\frac {3}{5}+\frac {5}{8}-\frac {1}{2}=\frac {3+5-1}{5+8-2}=\frac {7}{11}$(
×
)2. $1-\frac {3}{5}+\frac {2}{5}=1-1=0$(
×
)3. $\frac {5}{9}-\frac {5}{12}+\frac {1}{12}=\frac {1}{18}$(
×
)
答案：
1. × 2. × 3. ×
1. 脱式计算。
$\frac {2}{3}+(\frac {1}{2}-\frac {1}{4})$ $\frac {4}{5}-\frac {3}{10}+\frac {2}{3}$ $\frac {1}{2}+\frac {1}{4}-\frac {1}{6}$
$\frac {1}{2}-(\frac {2}{3}-\frac {2}{5})$ $\frac {7}{8}-\frac {5}{12}+\frac {1}{6}$ $\frac {5}{6}-(\frac {1}{2}+\frac {1}{3})$
$\frac {2}{3}+(\frac {1}{2}-\frac {1}{4})$ $\frac {4}{5}-\frac {3}{10}+\frac {2}{3}$ $\frac {1}{2}+\frac {1}{4}-\frac {1}{6}$
$\frac {1}{2}-(\frac {2}{3}-\frac {2}{5})$ $\frac {7}{8}-\frac {5}{12}+\frac {1}{6}$ $\frac {5}{6}-(\frac {1}{2}+\frac {1}{3})$
答案：
$\frac{11}{12}$ $1\frac{1}{6}$ $\frac{7}{12}$ $\frac{7}{30}$ $\frac{5}{8}$ 0
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