【题目】计算:

(1)(+)×(-60) (2) (-)×(-3)÷(-1)÷3;

(3) (-5)×(-3)+(-7)×(-3)+12×(-3) (4) 19×(-8)


参考答案:

【答案】(1)10 ; (2)-; (3)0; (4)-159

【解析】

根据四则运算法则,先去括号,将带分数化为假分数进而求解.

(1)(+)×(-60)=(-)×(-60)=10;

(2) (-)×(-3)÷(-1)÷3;= (-)×(-)×(-)×

(3) (-5)×(-3)+(-7)×(-3)+12×(-3),

= (-5)×(-)+(-7)×(-)+12×(-),

=(-)×[(-5) +(-7)+12],

=(-)×0,

=0;

(4) 19×(-8),

=19×(-8),

=-

=-159

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