【题目】先化简,再求值:2(x2y+xy2)﹣2(x2y﹣x)﹣2xy2﹣2y,其中x=﹣2,y=2.


参考答案:

【答案】解:原式=2x2y+2xy2﹣2x2y+2x﹣2xy2﹣2y
=(2﹣2)x2y)+(2﹣2)xy2+2x﹣2y
=2x﹣2y,
当x=﹣2,y=2时,原式=2×(﹣2)﹣2×2=﹣8
【解析】根据去括号、合并同类项,可化简整式,把未知数的值代入,可得答案.

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