《2025年口算天天练每日5分钟六年级数学上册苏教版》

一、口算。
$\frac{1}{8}×\frac{5}{4}=$
$\frac{7}{16}+\frac{3}{4}=$
$12×\frac{5}{8}=$
$12÷\frac{2}{7}=$
$\frac{1}{4}×\frac{2}{9}=$
$\frac{5}{6}×\frac{3}{10}=$
$2-\frac{8}{5}=$
$\frac{33}{35}÷22=$
$\frac{2}{3}÷\frac{2}{9}=$
$15×\frac{3}{5}=$
$\frac{5}{12}×\frac{4}{5}=$
$\frac{3}{4}×\frac{16}{15}=$
$\frac{15}{16}×\frac{4}{5}=$
$\frac{4}{5}-\frac{7}{10}=$
$\frac{5}{8}÷\frac{5}{7}=$
$\frac{5}{8}÷\frac{3}{2}=$
$9×\frac{5}{9}=$
$\frac{3}{8}÷\frac{1}{6}=$
$\frac{1}{16}÷\frac{1}{12}=$
$\frac{2}{3}+\frac{1}{8}=$
$\frac{7}{8}×\frac{8}{7}=$
$\frac{3}{4}+\frac{1}{3}=$
$\frac{5}{12}×\frac{4}{15}=$
$\frac{2}{3}×\frac{3}{4}=$

答案： $\frac{5}{32}$
$\frac{19}{16}$
$\frac{15}{2}$
42
$\frac{1}{18}$
$\frac{1}{4}$
$\frac{2}{5}$
$\frac{3}{70}$
3
9
$\frac{1}{3}$
$\frac{4}{5}$
$\frac{3}{4}$
$\frac{1}{10}$
$\frac{7}{8}$
$\frac{5}{12}$
5
$\frac{9}{4}$
$\frac{3}{4}$
$\frac{19}{24}$
1
$\frac{13}{12}$
$\frac{1}{9}$
$\frac{1}{2}$

二、计算下面各题，怎样简便就怎样计算。
$35÷\frac{7}{8}-\frac{2}{7}-\frac{5}{7}$
$(54+\frac{9}{13})÷9+\frac{12}{13}$
$(\frac{5}{6}-\frac{1}{2})×(\frac{7}{8}-\frac{1}{2})$

答案： 39
7
$\frac{1}{8}$

一、用简便方法计算。
$\frac{7}{9}÷\frac{11}{5}+\frac{2}{9}×\frac{5}{11}$
$5×\frac{1}{5}+5×\frac{4}{5}$
$\frac{9}{2}×\frac{3}{8}-\frac{7}{2}÷\frac{8}{3}$
$1-\frac{5}{8}÷\frac{25}{28}-\frac{3}{10}$
$90×(\frac{1}{6}+\frac{1}{10}+\frac{1}{15})$
$(4-\frac{5}{11}-\frac{6}{11})÷\frac{9}{7}$
$\frac{7}{18}×\frac{1}{4}+\frac{3}{4}×\frac{7}{18}$
$(\frac{6}{13}+\frac{1}{21})×13+\frac{8}{21}$

答案： $\frac{5}{11}$
5
$\frac{3}{8}$
0
30
$\frac{7}{3}$
$\frac{7}{18}$
7

二、计算下面各题，怎样简便就怎样算。
$(\frac{3}{5}-\frac{1}{2})×\frac{5}{3}+\frac{2}{9}$
$\frac{7}{9}÷\frac{13}{5}+\frac{2}{9}×\frac{5}{13}$
$\frac{4}{5}×\frac{10}{3}-\frac{4}{5}×\frac{7}{3}$
$\frac{8}{15}×\frac{3}{4}-\frac{1}{6}÷\frac{1}{2}$
$(\frac{9}{10}+\frac{3}{5})×(\frac{2}{9}-\frac{2}{15})$
$\frac{2}{3}-(\frac{1}{6}+\frac{1}{4})÷\frac{3}{4}$
$\frac{8}{9}×\frac{3}{4}÷(\frac{1}{3}+\frac{1}{5})$
$\frac{7}{8}÷[(\frac{1}{2}+\frac{3}{5})×\frac{5}{11}]$
$(1-\frac{1}{4}×\frac{8}{9})÷\frac{7}{9}$
$12÷[(\frac{7}{9}-\frac{2}{3})×\frac{9}{10}]$
$\frac{3}{5}÷[(\frac{1}{5}+\frac{1}{3})÷\frac{2}{9}]$
$\frac{8}{49}÷[\frac{9}{8}-(\frac{1}{8}+\frac{3}{7})]$

答案： $\frac{7}{18}$
$\frac{5}{13}$
$\frac{4}{5}$
$\frac{1}{15}$
$\frac{2}{15}$
$\frac{1}{9}$
$\frac{5}{4}$
$\frac{7}{4}$
1
120
$\frac{1}{4}$
$\frac{2}{7}$