2025年鼎尖同步练习六年级数学上册人教版
注:目前有些书本章节名称可能整理的还不是很完善,但都是按照顺序排列的,请同学们按照顺序仔细查找。练习册 2025年鼎尖同步练习六年级数学上册人教版 答案主要是用来给同学们做完题方便对答案用的,请勿直接抄袭。
$3.14×1^{2}= $ $3.14×4^{2}= $ $3.14×17^{2}= $ $3.14×11^{2}= $
$3.14×13^{2}= $ $3.14×8^{2}= $ $3.14×5^{2}= $ $3.14×0.1^{2}= $
$3.14×0.4^{2}= $ $3.14×0.3^{2}= $ $3.14×1.2^{2}= $ $3.14×30^{2}= $
$3.14×14^{2}= $ $3.14×10^{2}= $ $3.14×16^{2}= $ $3.14×0.5^{2}= $
$3×\frac {5}{8}= $ $\frac {7}{20}×\frac {5}{14}= $ $\frac {7}{10}×\frac {1}{7}= $ $\frac {4}{5}÷\frac {4}{15}= $
$\frac {1}{9}×5= $ $\frac {4}{9}×\frac {27}{4}= $ $\frac {12}{13}×\frac {7}{24}= $ $\frac {7}{12}÷\frac {4}{7}= $
$\frac {7}{9}×\frac {3}{14}= $ $\frac {1}{4}÷\frac {4}{5}= $ $56×\frac {3}{7}= $ $\frac {4}{15}÷\frac {2}{5}= $
$3.14×13^{2}= $ $3.14×8^{2}= $ $3.14×5^{2}= $ $3.14×0.1^{2}= $
$3.14×0.4^{2}= $ $3.14×0.3^{2}= $ $3.14×1.2^{2}= $ $3.14×30^{2}= $
$3.14×14^{2}= $ $3.14×10^{2}= $ $3.14×16^{2}= $ $3.14×0.5^{2}= $
$3×\frac {5}{8}= $ $\frac {7}{20}×\frac {5}{14}= $ $\frac {7}{10}×\frac {1}{7}= $ $\frac {4}{5}÷\frac {4}{15}= $
$\frac {1}{9}×5= $ $\frac {4}{9}×\frac {27}{4}= $ $\frac {12}{13}×\frac {7}{24}= $ $\frac {7}{12}÷\frac {4}{7}= $
$\frac {7}{9}×\frac {3}{14}= $ $\frac {1}{4}÷\frac {4}{5}= $ $56×\frac {3}{7}= $ $\frac {4}{15}÷\frac {2}{5}= $
答案:
3.14 50.24 907.46 379.94
530.66 200.96 78.5 0.0314
0.5024 0.2826 4.5216 2826
615.44 314 803.84 0.785
$\frac{15}{8}$ $\frac{1}{8}$ $\frac{1}{10}$ 3
$\frac{5}{9}$ 3 $\frac{7}{26}$ $\frac{49}{48}$
$\frac{1}{6}$ $\frac{5}{16}$ 24 $\frac{2}{3}$
530.66 200.96 78.5 0.0314
0.5024 0.2826 4.5216 2826
615.44 314 803.84 0.785
$\frac{15}{8}$ $\frac{1}{8}$ $\frac{1}{10}$ 3
$\frac{5}{9}$ 3 $\frac{7}{26}$ $\frac{49}{48}$
$\frac{1}{6}$ $\frac{5}{16}$ 24 $\frac{2}{3}$
1. 解方程。
$\frac {11}{24}x= 33$ $\frac {1}{9}x+3= 7$ $\frac {1}{6}x-\frac {1}{12}x= \frac {5}{24}$
$\frac {11}{24}x= 33$ $\frac {1}{9}x+3= 7$ $\frac {1}{6}x-\frac {1}{12}x= \frac {5}{24}$
答案:
1.72 36 $\frac{5}{2}$
2. 计算下面图形中阴影部分的面积。(单位:cm)


答案:
2.$3.14× [(18÷ 2{)}^{2}-(8÷ 2{)}^{2}]=204.1(c{m}^{2})$
$\frac{1}{2}× 3.14× [(40÷ 2{)}^{2}-(20÷ 2{)}^{2}]=471(c{m}^{2})$
$\frac{1}{2}× 3.14× [(40÷ 2{)}^{2}-(20÷ 2{)}^{2}]=471(c{m}^{2})$
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