1. 先指出下列各题的运算顺序,再计算。
$\frac{1}{3}+\frac{1}{4}\div\frac{1}{4}+\frac{1}{3}$ $5\div\frac{5}{7}-\frac{5}{7}\div5$ $[1-(\frac{3}{4}-\frac{1}{3})]\div\frac{1}{12}$
$7.08\times5\div7.08\times5$ $(6-\frac{3}{5}\times\frac{2}{3})\div\frac{7}{10}$ $(\frac{1}{2}-\frac{3}{8})\div(\frac{4}{25}\times\frac{15}{16})$
$\frac{1}{3}+\frac{1}{4}\div\frac{1}{4}+\frac{1}{3}$ $5\div\frac{5}{7}-\frac{5}{7}\div5$ $[1-(\frac{3}{4}-\frac{1}{3})]\div\frac{1}{12}$
$7.08\times5\div7.08\times5$ $(6-\frac{3}{5}\times\frac{2}{3})\div\frac{7}{10}$ $(\frac{1}{2}-\frac{3}{8})\div(\frac{4}{25}\times\frac{15}{16})$
答案:
2. 能简便的用简便方法计算。
$\frac{3}{5}\div\frac{3}{4}+\frac{2}{5}\div\frac{3}{4}$ $(\frac{3}{4}\div\frac{1}{2}+\frac{1}{2})\div\frac{2}{3}$ $\frac{7}{8}\div\frac{1}{2}-\frac{3}{4}\times\frac{5}{6}$
$\frac{3}{4}\times7+\frac{1}{4}\div\frac{1}{7}$ $9.2\div(1.01 - 0.09)\times10$ $1.25\times99\times0.8 + 1$
$\frac{3}{5}\div\frac{3}{4}+\frac{2}{5}\div\frac{3}{4}$ $(\frac{3}{4}\div\frac{1}{2}+\frac{1}{2})\div\frac{2}{3}$ $\frac{7}{8}\div\frac{1}{2}-\frac{3}{4}\times\frac{5}{6}$
$\frac{3}{4}\times7+\frac{1}{4}\div\frac{1}{7}$ $9.2\div(1.01 - 0.09)\times10$ $1.25\times99\times0.8 + 1$
答案:
3. 下列等式如果成立,在$\bigcirc$里打“√”。
$3.8\div1.9 = 76\div38$ $\bigcirc$ $0.39\div\frac{3}{5}=0.13\times5$ $\bigcirc$
$0.1\times10 = 0.1\div0.1$ $\bigcirc$ $3.2\div0.125 = 3.2\times8$ $\bigcirc$
$(\frac{3}{8}+\frac{2}{5})\times80=\frac{3}{8}+\frac{2}{5}\times80$ $\bigcirc$ $4\times\frac{4}{5}+\frac{4}{5}=4$ $\bigcirc$
$1.25\times32\times0.25 = 1.25\times8 + 4\times0.25$ $\bigcirc$ $5\div\frac{3}{5}+5\div\frac{2}{5}=5\div1$ $\bigcirc$
$3.8\div1.9 = 76\div38$ $\bigcirc$ $0.39\div\frac{3}{5}=0.13\times5$ $\bigcirc$
$0.1\times10 = 0.1\div0.1$ $\bigcirc$ $3.2\div0.125 = 3.2\times8$ $\bigcirc$
$(\frac{3}{8}+\frac{2}{5})\times80=\frac{3}{8}+\frac{2}{5}\times80$ $\bigcirc$ $4\times\frac{4}{5}+\frac{4}{5}=4$ $\bigcirc$
$1.25\times32\times0.25 = 1.25\times8 + 4\times0.25$ $\bigcirc$ $5\div\frac{3}{5}+5\div\frac{2}{5}=5\div1$ $\bigcirc$
答案:
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