【题目】若(x+3)(x+n)=x2+mx﹣21,则m的值为(  )
A.2
B.-2
C.4
D.-4


参考答案:

【答案】D
【解析】解:(x+3)(x+n)=x2+nx+3x+3n=x2+(n+3)x+3n,
∵x2+mx﹣21=(x+3)(x+n),
∴x2+mx﹣21=x2+(n+3)x+3n,
∴m=n+3,﹣21=3n,
解得:n=﹣7,m=﹣4,
故选D.
把(x+3)(x+n)展开得出x2+(n+3)x+3n,得出x2+mx﹣21=x2+(n+3)x+3n,推出m=n+3,﹣21=3n,求出即可.

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