(3)(a)当动点P在射线BA的右侧时,结论是

∠PBD=∠PAC+∠APB .

(b)当动点P在射线BA上,

结论是∠PBD =∠PAC +∠APB .

或∠PAC =∠PBD +∠APB 或 ∠APB = 0°,

∠PAC =∠PBD(任写一个即可).

(c) 当动点P在射线BA的左侧时,

  • 答案
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