分析 分清被除数的构成情况是解决本题的关键.当自变量取n时,被除数是5n项的和,其指数从0依次增加到5n-1.

解 当n=k+1时,被除数为1+2+2²+…+2^5k-1+2^5k+2^5k+1+…+2^5k+4,

从n=k到n=k+1增加的项为2^5k+2^5k+1+2^5k+2+2^5k+3+2^5k+4.

答案 2^5k+2^5k+1+2^5k+2+2^5k+3+2^5k+4