(本小题满分14分)                                                                                                                                          

已知函数f(x)=f(x)满足f(-x)=-f(x).

(1)求实数a的值;

 

(本小题满分14分)                                                                                                                                          

解:(1)函数f(x)的定义域为R,又f(x)满足f(-x)= -f(x),

所以f(-0)= -f(0),即f(0)=0.

所以,解得a=1,                                  ………………3分

此时, ,经检验满足题意,故a=1           ………………4分

(2)设x1x2,

f(x1)-f(x2)=

因为x1x2,则02x12x2,则f(x1)-f(x2) 0,即f(x1) f(x2).

所以f(x)在定义域R上为增函数.                               ………………9分

(3),                              ………………11分

因为,所以

的值域为.                                     ………………14分

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