已知平面内有一点P及一个△ABC,若
PA
+
PB
+
PC
=
AB
,则(  )
A.点P在△ABC外部B.点P在线段AB上
C.点P在线段BC上D.点P在线段AC上
PA
+
PB
+
PC
=
AB

PA
+
PB
+
PC
-
AB
=0,
PA
+
PB
+
BA
+
PC
=0,
PA
+
PA
+
PC
=0,
2
PA
=
CP
,∴点P在线段AC上,故选 D.
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