《2025年天天练口算六年级数学上册人教版》

$\frac{5}{9}× \frac{6}{25}= \frac{5× 6}{9× 25}= \frac{2}{15}$
$\frac{5}{12}× 16= \frac{5× 16}{12}= \frac{20}{3}$
$\frac{8}{11}× \frac{7}{24}= \frac{8× 7}{11× 24}= \frac{7}{33}$
$\frac{50}{52}× \frac{6}{25}= \frac{50× 6}{52× 25}= \frac{3}{13}$
$5× \frac{3}{25}= $\frac{5× 3}{25}$= $\frac{3}{5}$$
$27× \frac{2}{9}= $\frac{27× 2}{9}$= 6$
$\frac{25}{36}× \frac{3}{10}= $\frac{25× 3}{36× 10}$= $\frac{5}{24}$$
$\frac{1}{3}× 15= $\frac{1× 15}{3}$= 5$

答案： 解析：这些题目考查分数的约分与计算。需要先对分子分母进行因式分解，然后约去公因数，再进行计算。
答案：
$\frac{5}{9}× \frac{6}{25}= \frac{5× 6}{9× 25}=\frac{30}{225}=\frac{2}{15}$；
$\frac{5}{12}× 16= \frac{5× 16}{12}=\frac{80}{12}=\frac{20}{3}$；
$\frac{8}{11}× \frac{7}{24}= \frac{8× 7}{11× 24}=\frac{56}{264}=\frac{7}{33}$；
$\frac{50}{52}× \frac{6}{25}= \frac{50× 6}{52× 25}=\frac{300}{1300}=\frac{3}{13}$；
$5× \frac{3}{25}= \frac{5× 3}{25}=\frac{15}{25}=\frac{3}{5}$；
$27× \frac{2}{9}= \frac{27× 2}{9}=\frac{54}{9}=6$；
$\frac{25}{36}× \frac{3}{10}= \frac{25× 3}{36× 10}=\frac{75}{360}=\frac{5}{24}$；
$\frac{1}{3}× 15= \frac{1× 15}{3}=5$。

$\frac{3}{5}× \frac{4}{7}=$$\frac{12}{35}$
$\frac{1}{2}-\frac{1}{4}=$$\frac{1}{4}$
$\frac{11}{48}× \frac{6}{11}=$$\frac{1}{8}$
$\frac{5}{6}× 32=$$\frac{80}{3}$
$\frac{2}{3}× \frac{3}{10}=$$\frac{1}{5}$
$2-\frac{24}{25}=$$\frac{26}{25}$
$\frac{1}{5}+\frac{1}{3}=$$\frac{8}{15}$
$\frac{6}{21}-\frac{2}{21}=$$\frac{4}{21}$
$\frac{2}{9}× \frac{4}{7}=$$\frac{8}{63}$
$\frac{7}{8}× 72=$63
$28× \frac{3}{7}=$12
$\frac{5}{8}× 64=$40
$\frac{3}{16}× \frac{2}{3}=$$\frac{1}{8}$
$\frac{7}{54}× \frac{12}{49}=$$\frac{2}{63}$
$\frac{4}{81}× 9=$$\frac{4}{9}$
$\frac{5}{12}× \frac{4}{35}=$$\frac{1}{21}$
$\frac{4}{15}× 55=$$\frac{44}{3}$
$\frac{5}{8}× 72=$45
$\frac{5}{7}× \frac{2}{25}=$$\frac{2}{35}$
$\frac{15}{64}× \frac{8}{45}=$$\frac{1}{24}$
$\frac{5}{16}× \frac{2}{5}=$$\frac{1}{8}$
$\frac{7}{12}-\frac{5}{12}=$$\frac{1}{6}$
$\frac{5}{7}× \frac{1}{10}=$$\frac{1}{14}$
$\frac{7}{20}× \frac{4}{35}=$$\frac{1}{25}$

答案： 解析：
这些题目都是基础的分数乘法、减法、加法和分数与整数的乘法运算。
对于分数的乘法，我们直接相乘即可，分子乘分子，分母乘分母。
对于分数的加减，我们需要找到通分母，然后进行分子的加减。
对于分数与整数的乘法，我们将整数与分子相乘，分母保持不变，最后进行约分。
答案：
$\frac{3}{5} × \frac{4}{7} = \frac{12}{35}$
$\frac{1}{2} - \frac{1}{4} = \frac{2}{4} - \frac{1}{4} = \frac{1}{4}$
$\frac{11}{48} × \frac{6}{11} = \frac{66}{528} = \frac{1}{8}$
$\frac{5}{6} × 32 = \frac{160}{6} = \frac{80}{3}$ 或者写为混合数 $26\frac{2}{3}$
$\frac{2}{3} × \frac{3}{10} = \frac{6}{30} = \frac{1}{5}$
$2 - \frac{24}{25} = \frac{50}{25} - \frac{24}{25} = \frac{26}{25}$ 或者写为混合数 $1\frac{1}{25}$
$\frac{1}{5} + \frac{1}{3} = \frac{3}{15} + \frac{5}{15} = \frac{8}{15}$
$\frac{6}{21} - \frac{2}{21} = \frac{4}{21}$
$\frac{2}{9} × \frac{4}{7} = \frac{8}{63}$
$\frac{7}{8} × 72 = \frac{504}{8} = 63$
$28 × \frac{3}{7} = \frac{84}{7} = 12$
$\frac{5}{8} × 64 = \frac{320}{8} = 40$
$\frac{3}{16} × \frac{2}{3} = \frac{6}{48} = \frac{1}{8}$
$\frac{7}{54} × \frac{12}{49} = \frac{84}{2646} = \frac{2}{63}$
$\frac{4}{81} × 9 = \frac{36}{81} = \frac{4}{9}$
$\frac{5}{12} × \frac{4}{35} = \frac{20}{420} = \frac{1}{21}$
$\frac{4}{15} × 55 = \frac{220}{15} = \frac{44}{3}$ 或者写为混合数 $14\frac{2}{3}$
$\frac{5}{8} × 72 = \frac{360}{8} = 45$
$\frac{5}{7} × \frac{2}{25} = \frac{10}{175} = \frac{2}{35}$
$\frac{15}{64} × \frac{8}{45} = \frac{120}{2880} = \frac{1}{24}$
$\frac{5}{16} × \frac{2}{5} = \frac{10}{80} = \frac{1}{8}$
$\frac{7}{12} - \frac{5}{12} = \frac{2}{12} = \frac{1}{6}$
$\frac{5}{7} × \frac{1}{10} = \frac{5}{70} = \frac{1}{14}$
$\frac{7}{20} × \frac{4}{35} = \frac{28}{700} = \frac{1}{25}$