《2025年课时提优计划作业本七年级数学上册苏科版》

2. 计算：
(1)$(-1)^4-\frac{1}{6}× [2-(-3)^2]$；
(2)$\left(-1\frac{1}{4}\right)× \frac{2}{5}× 8-9÷ \left(-\frac{3}{2}\right)^2$；
(3)$-1^{2026}-(2-0.5)× \frac{1}{3}× [1-(-3)^2]$；
(4)$-1^4-\left[(1-0.7)× \frac{1}{3}\right]× [3-(-2)^2]$；
(5)$-3^2× \left(-\frac{1}{3}\right)^2+\left(-\frac{3}{4}-\frac{1}{6}+\frac{3}{8}\right)× (-24)$；
(6)$-3-\left[-2^2+(2^3-4)÷ \left(1-1\frac{1}{3}\right)\right]$；
(7)$5-\left(\frac{1}{2}-\frac{2}{3}+\frac{2}{5}\right)÷ \left(-\frac{1}{30}\right)$；
(8)$-9^2+2× (-3)^2+(-6)÷ \left(-\frac{2}{3}\right)^2$；
(9)$(-3)^2× \left[-\frac{2}{3}+\left(-\frac{5}{6}\right)\right]-6÷ (-2)× \left(-\frac{1}{3}\right)$；
(10)$-2^3÷ \frac{4}{3}× \left(\frac{1}{2}-\frac{1}{3}\right)^2+\left[3-(-1)^3\right]$.

答案：
(1)原式=$1-\frac{1}{6}×(2-9)=1-\frac{1}{6}×(-7)=1+\frac{7}{6}=\frac{13}{6}$.
(2)原式=$-\frac{4}{5}×\frac{2}{5}×8-9÷\frac{9}{4}=-4-9×\frac{4}{9}=-4-4=-8$.
(3)原式=$-1-\frac{3}{2}×\frac{1}{3}×(-8)=-1+4=3$.
(4)原式=$-1-\frac{1}{10}×(-1)=-1+\frac{1}{10}=-\frac{9}{10}$.
(5)原式=$-9×\frac{1}{9}+(-\frac{3}{4})×(-24)-\frac{1}{6}×(-24)+\frac{3}{8}×(-24)=-1+18+4-9=12$.
(6)原式=$-3-[-4+4÷(-\frac{1}{3})]=-3-(-4-12)=13$.
(7)原式=$5-(\frac{1}{2}-\frac{2}{3}+\frac{2}{5})×(-30)=5-[\frac{1}{2}×(-30)-\frac{2}{3}×(-30)+\frac{2}{5}×(-30)]=5-(-15+20-12)=5+15-20+12=12$.
(8)原式=$-81+2×9+(-6)÷\frac{4}{9}=-81+18-6×\frac{9}{4}=-63-\frac{27}{2}=-\frac{153}{2}$.
(9)原式=$9×(-\frac{3}{2})-(-3)×(-\frac{1}{3})=-\frac{27}{2}-1=-\frac{29}{2}$.
(10)原式=$-8×\frac{3}{4}×\frac{1}{36}+4=-\frac{1}{6}+4=3\frac{5}{6}$.