《2025年一本暑假计算加应用题五年级数学北师大版》

1. 直接写出得数。(每题 1★)
$\frac {7}{12}+\frac {5}{12}=$1 $\frac {3}{5}-\frac {1}{10}=$$\frac{1}{2}$ $\frac {7}{6}+\frac {5}{6}=$2 $1-\frac {1}{6}-\frac {1}{3}=$$\frac{1}{2}$
$\frac {5}{6}-\frac {1}{3}=$$\frac{1}{2}$ $4-\frac {2}{5}=$$3\frac{3}{5}$ $\frac {3}{8}+0.625=$1 $1-\frac {3}{8}-\frac {1}{8}=$$\frac{1}{2}$
$\frac {11}{15}-\frac {8}{15}=$$\frac{1}{5}$ $\frac {17}{24}-\frac {3}{8}=$$\frac{1}{3}$ $\frac {17}{18}-\frac {1}{9}=$$\frac{5}{6}$ $1-\frac {11}{15}-\frac {2}{15}=$$\frac{2}{15}$
$\frac {10}{23}-\frac {3}{46}=$$\frac{17}{46}$ $\frac {15}{22}-\frac {4}{11}=$$\frac{7}{22}$ $\frac {23}{36}-\frac {4}{9}=$$\frac{7}{36}$ $4-\frac {11}{3}-\frac {1}{3}=$0
$2-\frac {11}{9}=$$\frac{7}{9}$ $\frac {25}{18}-1=$$\frac{7}{18}$ $6-\frac {1}{9}=$$5\frac{8}{9}$ $28-\frac {8}{9}-\frac {1}{9}=$27

答案： 1 $\frac{1}{2}$ 2 $\frac{1}{2}$
$\frac{1}{2}$ $3\frac{3}{5}$ 1 $\frac{1}{2}$
$\frac{1}{5}$ $\frac{1}{3}$ $\frac{5}{6}$ $\frac{2}{15}$
$\frac{17}{46}$ $\frac{7}{22}$ $\frac{7}{36}$ 0
$\frac{7}{9}$ $\frac{7}{18}$ $5\frac{8}{9}$ 27

2. 计算下面各题,能简算的要简算。(每题 3★)
$\frac {9}{4}-(\frac {1}{4}+\frac {2}{5})$ $\frac {17}{13}+\frac {7}{15}+\frac {9}{13}+\frac {8}{15}$ $\frac {3}{4}+\frac {5}{9}+\frac {1}{6}-\frac {5}{9}$
$\frac {3}{7}+\frac {7}{9}+\frac {4}{7}$ $\frac {12}{7}+\frac {4}{9}+\frac {5}{9}+\frac {2}{7}$ $5.16+\frac {15}{11}+4.84-\frac {4}{11}$
$\frac {1}{6}+\frac {7}{19}+\frac {5}{6}$ $\frac {14}{15}+\frac {8}{11}+\frac {1}{15}+\frac {3}{11}$ $\frac {13}{9}-(\frac {4}{9}+\frac {8}{17})$

答案： 1 $\frac{3}{5}$ 3 $\frac{11}{12}$
$1\frac{7}{9}$ 3 11
$1\frac{7}{19}$ 2 $\frac{9}{17}$